Bless you mate, i'm a mech eng student but my first year electric coursework had me in a mess, I had several problems with capacitors in combination of series and parallel at the same time but i've sorted it now thanks to you, cheers.
So now with online classes and teacher just giving us exercises without explanation, finding this complete video with all the things I was asked for is really a relief, thank you!
I have been following your videos and just wanted to at least say thank you for taking the time to make these videos. They have been easy to understand and extremely helpful, thanks again.
Our class is gonna start on capacitance in series and parallel monday. This was very helpful and you explained it well. Because of just finishing series, parallel, and series-parallel, I was able to follow along with ya . I feel like I may have the jump on everyone come monday. Thanks for making this viddy.
+james mcgrady Great that you were preparing ahead of time, glad that you found the videos helpful and thanks for commenting. You can see a listing of all my videos at my website, www.stepbystepscience.com
+Kyle Alecxander Ozoa That is a great comment, Thank you very much. I try to go through everything step-by-step. In fact …..you can see a listing of all my videos at my website,www.stepbystepscience.com
+Irfan Haider Thanks you, I tried to cover all of the basic concepts in these videos. You can see a listing of all my videos at my website, www.stepbystepscience.com
+Nick Bowyer Thanks for the comment, I try to use a lot of primary color and go through everything step by step. You can see a listing of all my videos at my website, www.stepbystepscience.com
Really helpful thanks, working out the energy stored in each capacitor seem pretty simple. Am I right in think that working out the total energy in the circuit will be achieved by adding the total energy of each capacitor together?
You are very welcome. Sincerely THAT BERLIN GERMANY PHYSICS TEACHER GUY. You can see a listing of all my videos at my website, www.stepbystepscience.com
What is the charged of each capasitor ? for example Q2=C2*V2=¤mikroFarady or(MikroC) *3.75v=15.00MikroC .Dont you think you should change the sign of capasitor to Mikro F? otherwise it was best video ! Thank you for sharing your knowlage with us .
daeser1 Yes that is what I did, Charge(total) = Capacitance(total) x Voltage(total)…as I said before for me the total capacitance and the equivalent capacitance refer to the same thing. Q = C x V….Am I answering your question?
+ihonestytruthful Thank you, I tr to get right to the point and then go through the pems step by step.....in fact you can see a listing of all my videos at my website, www.stepbystepscience.com
No! But this is a common mistake. Please remember that the voltage drop across parallel circuit is "always" equal. So the voltage drop across each of the capacitors is 3.73 V. You can see a listing of all my videos at www.stepbystepscience.com
sir how would i solve for the maximum voltage that can be applied in a series circuit if each capacitor's value has voltage rating,? example : c1= .002 uF, volatge rating= 120V c2= .002 uF, voltage rating= 26V c3= .002 uF, volatge rating= 120V.. i solved for the total capacitance and i got .00067uF. but i dont know how will i solve for the voltage, will i just add it? thank u.
Yes, they are the same thing, and no that is not a silly question. The terminology can be very confusing. Probably "potential difference" is the better term but since it is measure in volts it is often referred to a the "voltage".
This is a little hard to convey in a comment but.....yes the charge on each series capacitors is the same. Imagine a certain amount of charge comes out of the battery, this is deposited on the first capacitor and pushes the same amount of charge on to the second capacitor and on down the line.....I also made a video explaining this concept...Charge for Capacitors in Series
hey great work but i think you made a mistake near the end for Q1 and Q3 the individual values are suppose to be V1= 1.87 and V2=1.87, not 3.74 because thats the total some of voltage for V1 and V2. Please Correct me if I'm wrong.
This is a very good questions and a common mistake. C1 and C2 are in parallel therefore they have the same voltage drop and that is 3.74 V as I stated in the video. Whether resistors, capacitors or some other type of circuit element, the the voltage difference across parallel elements is equal. Thanks for the comment.
aria k No I think I have it right, but yours is a common confusion that people have. This is a little hard to explain here….First of course parallel circuit elements do have the the same voltage drop across them. The drop across is 5.26V, then the voltage drop across each of the other two is 9.00 - 5.26V. For each "path" the voltage is shared between two capacitors. For each of the two paths the total drop must add to 9V. In your case it would be 5.26V + 1.87V = 7.13V and that ain't 9V. Does that help?
Are you telling me or asking me…The sum of the charge stored on all of the capacitors is referred to as Qtotal. Equivalent is usually used when talking about the all or some of the capacitors in the circuit, usually people say the "equivalent capacitance of the circuit is….." but sometimes I say the "total capacitance". For me the total capacitance and the equivalent capacitance are the something.
learned more in a ten minute video than 50 minutes of watching my professor try to figure stuff out. Really nice job!
Thanks man, you make writing these formulas a lot more understandable then some of the other videos I've viewed. Keep up the good work!
+Leo Payne Thank you for the positive commented and great that the videos are helpful.
Thank you. My professor spent like 2 days on this. You explained it in 10 min
Bless you mate, i'm a mech eng student but my first year electric coursework had me in a mess, I had several problems with capacitors in combination of series and parallel at the same time but i've sorted it now thanks to you, cheers.
Great and thanks for the comment. Are you in the UK? I live in Berlin but my son is studying mechanical engineering at Southampton. Have a great day.
Yes good teaching
Answered my Physics assignment because of this!! Thank you so much!! I really had a hard time understanding the lesson so this is a big help :--)
Great, thanks for the comment.
This was so much simpler than what I've been taught thankyou
It is usually not tanks for too complicated, thanks for the comment.
Thank you sir!
My professor never told us what to do when combining parallel and series capacitors; you saved my homework!
Really, that seems a bit weird. Great that you found the video helpful.
I think you are the best teacher for solving these sacking problems
Very nice of you to say...You can see a listing of all my videos at www.stepbystepscience.com
So now with online classes and teacher just giving us exercises without explanation, finding this complete video with all the things I was asked for is really a relief, thank you!
Great it was helpful! Thanks for watching and commenting.
I have been following your videos and just wanted to at least say thank you for taking the time to make these videos. They have been easy to understand and extremely helpful, thanks again.
Thank you very much, that is very nice of you to say.
Our class is gonna start on capacitance in series and parallel monday. This was very helpful and you explained it well. Because of just finishing series, parallel, and series-parallel, I was able to follow along with ya . I feel like I may have the jump on everyone come monday. Thanks for making this viddy.
+james mcgrady Great that you were preparing ahead of time, glad that you found the videos helpful and thanks for commenting. You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you, very helpful video and you have a pleasant voice for narrating videos like this!
absolute life saver , your explanation , at least for me , was better than any others on youtube.
Thank you for commenting. You can see a listing of all my videos at www.stepbystepscience.com.
Thank you, sir.... It was really helpful.....now all the confusion of circuit capacitance has been removed from me.😊😊
No problem, glad that you found the video helpful.
Found this recently and it really help me in my exam just now. 😊 thankyou so much
Glad it helped!
THANK YOU, this was much needed. Exam in 2 days!
Dario Dipaola YOU ARE WELCOME, I wish you much success with your exam.
I wish all teachers were like you sir
So nice of you, thanks!
Very good and useful video. Just a heads up that for Question 5 you used C as a measure of capacitance instead of F. Other than that very useful video
THANK YOU YOU SAVED ME ON MY HOMEWORK I LOVE YOU
Happy to hear that. Best wishes to you.
thank you so much Brian Swarthout, this video helped me so much in doing my test....this is in Fiji.
Perfection....and well explained!!! Wish my UNIVERSITY(!!) professor was like you.
Thank you for the positive comment!
Really Helpful. it was shorty and very explained. thanks
Thank you so much!! thanks for breaking it down into parts and making it easier to understand :)
Thank you, this made it a lot clearer for me.
***** great and thank you for commenting.
Hii sir
This helped me do my homework! Thank you for this
Glad it helped! Best wishes.
Wonderfully worked out. Explained throughly and I really enjoyed learning from a bright guy like you! Keep up the tutorials Brian!
+Kyle Alecxander Ozoa That is a great comment, Thank you very much. I try to go through everything step-by-step. In fact …..you can see a listing of all my videos at my website,www.stepbystepscience.com
very helpful video for building up a concept about series and parallel combinatons of capacitor
+Irfan Haider Thanks you, I tried to cover all of the basic concepts in these videos. You can see a listing of all my videos at my website, www.stepbystepscience.com
thanks a lot for guiding me....
what a helpful lesson,thanks rehan
I think that you're an angel and if I pass my test tomorrow I'l buy you chips.
did you ever buy those chips
Very nicely explained. Thanks a lot.
Thank you so much. You just solved my doubt ,your kinda savior of all the students
Just try to help out a bit, thanks for the comment. You can a listing of all my videos from my website at www.stepbystepscience.com
Great explanation. Thank you for your video.
@Blas Hernandez, Thank you for the positive comment…It means a lot to me!
thankyou so much, helped me with my homework
Awesome, thanks for letting me know. You can see a listing of all my videos at www.stepbystepscience.com
Very nice explanation...hats off
+Rehan Khan Thanks for the positive comment.
Great video! You have really helped me here thankyou. I really like how you present your videos.
+Nick Bowyer Thanks for the comment, I try to use a lot of primary color and go through everything step by step.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Really helpful thanks, working out the energy stored in each capacitor seem pretty simple. Am I right in think that working out the total energy in the circuit will be achieved by adding the total energy of each capacitor together?
Thank you. I had a struggle with this.
Great that the video helped, it can be a bit confusing.
Brilliant, thank you. Very clearly explained. Helps a lot.
+Richard Graham Great, thanks for the comment. You can see a listing of all my videos at my website, www.stepbystepscience.com
I don't know what to say but that was great thank you so much
I am also not sure what to say but….thank you for commenting.
thank you very much very easy to follow you, but how would you calculate the total energy in this circuit?
should i calculate the energy in parallel and add the energy in C3?
calculate the energy stored in each capacitor, I think
Very helpful video. I have a question. Let's say you are given the CT and you don't have C2 but you do have C3. How do you get the C2?
perfect explanation,even the stray cat in the yard behind will learn how to calculate capacitances.
+Илиян Попов Thanks for the positive comment.
You can see a listing of all my videos at my website, www.stepbystepscience.com
thank you you have make easier to understand
Thanks Brian good teaching!
Thank you for the compliment.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank u proffesser nice job
No professor here, just a high school science teacher.
Kk im diploma student in electrical
THANK YOU FOR THIS 🤗🤗🤗
So happy to help. Thanks for watching!
Maraming salamat po 😀
+Trixia Gonzales Walang anuman. (Is that right?) You can see a listing of all my videos at my website, www.stepbystepscience.com
+Trixia Gonzales hahahahahaha
pinay
Thank you. Very helpful. Sincerely THAT NAVY GAL
You are very welcome. Sincerely THAT BERLIN GERMANY PHYSICS TEACHER GUY. You can see a listing of all my videos at my website, www.stepbystepscience.com
Good explanation
You are welcome and thanks for the comment.
Liked. Subscribe. And Shared to my classmates. Thank you for this sir. It was very helpful to us G12 students 🙏💖
Thanks so much and all the best to you and your classmates!
This is a great video, thanks.
+Ruben Tavarez thanks for the great comment
You can link to all my videos at my website: www.stepbystepscience.com
+Brian Swarthout do you have one where an unknown Resistance is involved in a combination circuit?
What is the charged of each capasitor ? for example Q2=C2*V2=¤mikroFarady or(MikroC) *3.75v=15.00MikroC .Dont you think you should change the sign of capasitor to Mikro F?
otherwise it was best video ! Thank you for sharing your knowlage with us .
daeser1 Yes that is what I did, Charge(total) = Capacitance(total) x Voltage(total)…as I said before for me the total capacitance and the equivalent capacitance refer to the same thing. Q = C x V….Am I answering your question?
best videos short, sweet and simple
+ihonestytruthful Thank you, I tr to get right to the point and then go through the pems step by step.....in fact you can see a listing of all my videos at my website, www.stepbystepscience.com
+Brian Swarthout thanks a lot I did not know you had a website :) ... I wish you all the best. 💚
3.74 corresponds to the total voltage between C1 and C2, right? so their individual voltages are 3.74/2?
No! But this is a common mistake. Please remember that the voltage drop across parallel circuit is "always" equal. So the voltage drop across each of the capacitors is 3.73 V.
You can see a listing of all my videos at www.stepbystepscience.com
Thank you King
Welcome!
Can you explain why in no. 5 why charge of Q3 is 26.3 micro coulomb?
Very helpful !
Glad you think so!
got it. and now I know the behavior of charge also.
Great and thanks for all of your positive comnents.
That was superb
Thanks so much!
this was perfect!!!
Nice.
i ll see your videos brian and thanks for the reply i appreciate that
Thanks man your a legend!!!!!!
Thank you for the positive comment!
Thank you so much
You're most welcome
ver4y good and easy to follow.
Thank you for the comment, I try to do everything step by step.
Great video!
Thanks for watching and commenting. You can see a listing of all my videos at my website, www.stepbystepscience.com
thats superb. thanks a lot.
Thanks for the help
😀
+Henry Sanctuary You are very welcome.
You can see a listing of all my videos at my website, www.stepbystepscience.com
great teacher
Thanks for the great comment.
You can see a listing of all my videos at my website, www.stepbystepscience.com
the totatl capacitance when calculated has uF in the denominator and not in the numerator in the two step process.
sir how would i solve for the maximum voltage that can be applied in a series circuit if each capacitor's value has voltage rating,?
example :
c1= .002 uF, volatge rating= 120V
c2= .002 uF, voltage rating= 26V
c3= .002 uF, volatge rating= 120V..
i solved for the total capacitance and i got .00067uF.
but i dont know how will i solve for the voltage, will i just add it? thank u.
Thank you sir!! So much
i think you meant uF instead of uC for Capacitance in some of the calculations! Otherwise great :)
I have a silly question: is the potential difference for each capacitor the same as a voltage across each capacitor? I mean those both mean the same?
Yes, they are the same thing, and no that is not a silly question. The terminology can be very confusing. Probably "potential difference" is the better term but since it is measure in volts it is often referred to a the "voltage".
Thank you sir😊
You are very welcome....You can see a listing of all my videos at www.stepbystepscience.com
thank you
You are ver welcome.
check out this and all my videos at the new learning site
www.bibblio.org
Gee, you are incredible!! Thanks for the awesome vids (:
How can the charge Q3 equal the total charge? That would mean all the charge in the circuit is on capacitor 3 and no charge is on the first two...
This is a little hard to convey in a comment but.....yes the charge on each series capacitors is the same. Imagine a certain amount of charge comes out of the battery, this is deposited on the first capacitor and pushes the same amount of charge on to the second capacitor and on down the line.....I also made a video explaining this concept...Charge for Capacitors in Series
brian i have a doubt what ll be the amps in this circuit ?
+Ar Un I am not sure what you mean but OK….You can see a listing of all my videos at my website, www.stepbystepscience.com
Awesome job :)
Franz Andrei Cruspero Thank you very much for the comment.
THANK YOU
Check it out!!! Electric circuits with capacitors in parallel and in series. That 's intense!!!
hey great work but i think you made a mistake near the end for Q1 and Q3 the individual values are suppose to be V1= 1.87 and V2=1.87, not 3.74 because thats the total some of voltage for V1 and V2. Please Correct me if I'm wrong.
This is a very good questions and a common mistake. C1 and C2 are in parallel therefore they have the same voltage drop and that is 3.74 V as I stated in the video. Whether resistors, capacitors or some other type of circuit element, the the voltage difference across parallel elements is equal. Thanks for the comment.
aria k No I think I have it right, but yours is a common confusion that people have. This is a little hard to explain here….First of course parallel circuit elements do have the the same voltage drop across them. The drop across is 5.26V, then the voltage drop across each of the other two is 9.00 - 5.26V. For each "path" the voltage is shared between two capacitors. For each of the two paths the total drop must add to 9V. In your case it would be 5.26V + 1.87V = 7.13V and that ain't 9V. Does that help?
Thanks
You are very welcome
thx very helpful
thank you very much.
amazing
Thank you! Cheers!
Thank youuuuu!!!
+AndrewEKlein22 You are very welcome!
THANKS
thato tsamai You are very welcome!
Can someone explain why my tutor was adding ' X10 to the power of minus 6' to find the charge?
He is converting uc to c.
Micro coloumb to coloumb.
yesssss!!!!!! thank you!!!! guy!!!!!
You are very welcome girl!!!!! You can a listing of all my videos from my website, www.stepbystepscience.com
Arent you gonna convert uc to c?
AWESOME
👏👏
Thank you
In triangle form how to do
thanks
you are welcome. you can see a listing of all my videos at my website, www.stepbystepscience.com
Awesome video!!!! *SUBSCRIBED
Thank for the comment and for subscribing.
Nice Positive.
-Comment.
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Qtotal is not the same as the Qeq.
Are you telling me or asking me…The sum of the charge stored on all of the capacitors is referred to as Qtotal. Equivalent is usually used when talking about the all or some of the capacitors in the circuit, usually people say the "equivalent capacitance of the circuit is….." but sometimes I say the "total capacitance". For me the total capacitance and the equivalent capacitance are the something.
Hola !! Imao Afky sudia
+shamit sharma Sure, whatever that means, thanks,
You can see a listing of all my videos at my website, www.stepbystepscience.com
i want some more tough questions of circuits and Electrostatic , can u give me some wid solutions ?