Collector Feedback Biasing
ฝัง
- เผยแพร่เมื่อ 20 ส.ค. 2024
- Analog Electronics: Collector Feedback Biasing
Topics Covered:
1. Difference between emitter biasing and collector feedback biasing.
2. Calculation of operating point.
3. Advantages and disadvantages of collector feedback biasing.
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Thank you So much sir for this great explanation... I think the answer is, applying KVL in output loop we can find, Vcc = IRc + Vce... Now IRc is the potential drop across Rc... So if Rc increases then the potential drop across Rc will also increase... And it is clear from the mentioned equation that Vcc will also increase...
you should increase the vcc voltage for make ratio vcc/rc constant to save q-point stable
Please make a playlist so it would be easy to find videos in sequence. Other than that, excellent work.
Vcc = Vce+IcRc. So increasing Rc will increase Vcc..
0:57 I always confuse here! But it’s absolutely easy now.
Thank u sir.
First of all thanks for the lectures.All the topics are explianed briliantly.
For keeping the Q point fixed we have to increase Vcc on increasing Rc.
please provide lectures on op-amp.
as Rc increases,operating point moves left (slope=-1/Rc),hence to compensate,Vcc must be increased
Great explanation sir 👍👍. You're the best.
should we bow, yes he is the king... how do i thank this man, forever grateful.... THANKYOU SIR
Q point shifts whenever there is change in Ic value(since Ic is one of the coordinates),thus if Rc increases Ic will decreases hence to increase the Ic(to keep up the stability) Vcc(voltage at point)should be increased.
since voltage is directly proportional to resistance .if the resistance value is required to be increased than voltage must also be increased to balance the current.
if we increase the Rc ,that would be decrease the output value of collector emitter voltage,so increase the Vcc will maintain the variation in Vce
Voltage kbse resistance k directly proportionally hone lg gya
By increasing Rc the potential drop across Rc increases and thus Vcc should be greater than the potential drop so that the transistor is in active state.
i have exam today after an hour 2pm watching this and hopfully claimed toget good marks in paper😍😍😍😍
As Vce = Vcc - IRc as Rc increases IRc drop increases then Vce changes that results to change in Q point that is not good so if you pheripherally increase Vcc then Q point becomes stable
As Rc increases, most of the voltage Vcc will drops at Rc only.remaning voltage divides into Vbe & Vcb.And Vbe~0.7.That means Vcb is decreasing. But we know that Vcb has to large enough to make base-collector junction reverse biased if not circuit goes to saturation region eventually there will be no current in circuit.So we have to increase Vcc.
I think
Rc increase, without changing Vcc, less current draw, (Ic+Ib) decreases, Ic decrease with Ib of ratio B. This results Q point drift towars cutoff, increase Vcc to keep Vcc/Rc ratio back would lift the Q point back to original point.
Ohms law tells V=IR, if R need to be raised then V must be increased in order to maintain constant current through the crct.
We have to increase Vcc along with Rc....to keep the Q-point stable.(because the ratio Vcc/Rc...should be constant for stable Q-point on active region).
If Collector feedback biasing has also same disadvantages as emitter bias. Then what different purpose it serves?
Difference here arises in the stability factor [S]
One resistance can be negotiated just by changing emitter bais to collector bias
legends watching it in 2023.
excellent work done 7 years ago
when Rc increases, the voltage drop IcRc increases. If IcRc increases,Vce decreases. if Vce decreases,the Q-Point will approach saturation region. so inorder to compensate ,Vcc must be increased. Also it is clear from the equation, Ic=(Vcc-Vbe)/Rc that if Rc increases, Vcc will increase.
Follow these equations .
Vcc=Vce+IcRc-----(1)
Vce=Vcc-IcRc------(2)
In a collector feedback bias circuit, the current through the collector resistor is ________ and the collector current is ________.
finds a collector feedback video and finds the ans at the very beginning. IB+IC , IC. TYL!
It really helps me sir.
Gd evng sir,if collector increases y the collector to emitter voltage decreases nd base current decreses?
with increase in Rc only the voltage to base is decreasing and a time will come when both the junctions will become reverse bias thus cutoff region.
Thank you sir ❤️
how exactly does this method stabilizes the q-point against the change in Vcc !
See as we increase Vcc, both Vce and Ic increases as we can see in the formulae of Ic and Vce
Right bro
Vcc does increase for high value of Rc in order to satisfy the condition "β Rc >>Rb" and in order to make collector current Ic free of stabilization factor β so
that operating point Q can be stabilized.
If resistance value increases then the drop across the resistor will also increases so to compensate that drop we will use large value of Vcc
Vcc increases because for high resistance we need to apply high voltages to flow current according to ohm's law......
as Rc increases the drop across it also increases. so it results in the increase of Vcc so that required amount of current reaches the transistor.
thanks you neso academy to help clear my concepts 😊
The Vcc increases with the increase in Rc because to keep the Q.point stable
thanks helpfully lecture
Thank you
Sir! In this case how I (c) is independent of temperature and how operating point is independent of Vcc
Sir please give lectures on feedback amplifiers.
Thank you very much sir 🙏
how is this different from a emitter-bias configuration (with respect to advantages and disadvantages).
if Rcc increases potential drop also increases , we need to provide high voltage Vcc
it will also involve the resistior below npn transistor
GREAT LECTURE!!! HATS OFF TO YOU SIR!!!
and the answer for that ques is
when Rc increases ,the voltage through that resistor Rc also increases since resistor is proportional to voltage.....hence VCC INCREASES...
Sir,is this correct??
Because high value of Rc increases drop across IcRc so large input voltage is reqd. Thus we need high Vcc
I think so large value of the RC decrising the current passing through the transistor there is reason choosing large or incrising value of the vcc
as in active region transister acts as an amplifier, thus the output current should be high....since we are required to increase Rc thus the Vcc in needed to larger
How do we calculate if there is a resistor E and we don't know it's value?
why there is minus after vcc in first equation?
If Rc increases, drop across it increases... Since the load and bjt are connected ahead..they will not get enough supply...
How does COLLECTOR FEEDBACK BIASING insulates Q point against the variation of Vcc .....? Please explain sir.....🙏
great work 👍👌
If vcc increases the voltage drop across the resistor rc increases so if vcc increases then rc increases
In output loop, Vcc = Rc * I + Vce. So if Rc increase then Vcc also increase.
My answer is also same.
thank you, this helps a lot
I have tried to make a small Signal model of the Selve biased EC-Stage with Emitter degeneration and it was not easy. In fact the Formula was way to big. Now if i have even an capacitor parallel to an Emitter resistance, the Problem becomes even bigger.
Does anone have a good advice / Approach to such a Problem?
Compensate rise in Rc by a rise in Vcc, so that Ic can be maintained at same value. It is after all one of the coordinates for Q-point
V=ir so when vcc increases the rc also increses and the rb is neglected
Sir please microcontroller lectures
Sir you will derive the formula Vce=Vcc-(Ic+Ib)Rc,if Rc increases then Vce decreases that mean the R.B potential across Vcb decreases(Vce=Vcb+Vbe) which causes unfaithful amplification , for this reason if Rc increases then we should do increases Vcc, Sir please check my answer (trueor false)
Plz make videos on feedback amplifiers
Is collector base bias is better or emitter feedback bias is better one? Explain how?
V directly proportional to R ....hence ....if VCC increases...rc also increase
when RC is a large value, VCC increases because there is a low voltage drop across RC. Because RC has a high resistance then IC has a low value.
How it is stabilizing qpoint for variations in vcc??
to maintain the value of Vce we need to increase Vcc for a arge value of Rc
If we increase Rc value,the slope ,intersecting points of load line will change .so,to get rid of this Vcc is to be increased.
What is the reason for doin all these bias configuration to CE configuration not other configurations of transistors ? Can anyone tell
7:20, i just consider the equation appear earlier, it show that Rc increase, will lead to Ib decrease and so Ic. finally Ib equal to zero. the transistor stop working. Ib(Rc+Rb+betaRc)=Vcc- Vce. ( assume in active region, beta is constant) is a possible answer?
How does collector biasing stabilizes q point despite the variations in Vcc?
If we start increasing Rc without increasing Vcc, we get smaller values which drives Ic towards zero putting Vce equal to Vcc, which is for sure the start of saturation, i guess!
@Guoyi Xu agreed
Plus having such a large RC defeats the purpose of having a BJT as a simple amplifier. Moderation I guess
Sir plzz make video on negative feedback
How is Rb providing a -ve feed back resistance ??
VERY WELL
how it is stabilizing Qpoint against temp and Vcc variation?
watch previous videos of Emitter-bias configuration
Vcc must be increased to keep the BC jxn reverse biased 👀
in a feedback what happend when vce equal vcc ? plz answer me
Vcc can only be equal to Vce if the transistor is operating in cut off mode... Only then will the voltage not drop across resistance Rc
lecture on feedback amplifier please
How there is no effect on operating point with respect to change in VCC???
how can collector feedback biasing stabilizes Q-pt against change in Vcc?
can any one explain me how reduce in Rb result in reduction of rev bais of C-B junction..... i stuck there...
if Vcc is not high,then current will not flow through Rc.
sir i have one doubt i.e in my college notes it is written that when ic increases Vce decreases so Ib decreases which wiil decrease that IC SIR PLEASE REPLY MY EXAM IS THERE
AM I CORRECT? PLEASE TELL ME NESO ACADEMY.
Why reducing base resistance reduces reverse bias of the Collector base junction.?
In base current equation if we reduce the Rb value , ib increases
If we sustitube increased ib to the
Vce equation the value of Vce decreses
bcz Vcc is the volage of collector and Vc=Ic*Rc .
the disadvantages of emitter bias and feedback bias is same ?
Sir which kind of feedback is collector feedback biasing in ce configuration?
plss add a lecture about current mirror 😌😌😫
Plz explain feedback circuit too
more the resistence, more the voltage drop, if we need the same Ic, with the increase of Rc, Vcc should be increased accordingly
No one can teach kvl rule exactly on youtube
For compensate voltage drop across Rc
if Rc increases then the resistance is very high......if the resistance is high,less current will flow....in order for current to flow through it....we have to increase Vcc
To stabilize q point in active region
sir how this ckt is independent on biasing voltage Vcc?
to maintain same cuurent and stable q point
ans- sir cause Vcc = IRc + Ib*Rb
To make Vce constant
Vcc increased for forward biasing of ouput circuit
Sir,what will be the re model for this??
If we increase Rc then drop across Rc increases, results more Vcc value.
Why with decrease in Rb the reverse bias of C-B junction decreases?????? Plzzz sir
Have you got the answer ??