So many thanks for your extremely kind words, Mr.Lubbock. With your permission, I may put it in my teaching dossier, for next year "quality assurance of teaching" review. Sincerely.
The only video I have seen that not only explain the bjt biasing theory, but also (and more important), how to set resistor values to a proper biasing given a specific Q-point.
Mr Rolinychupetin. Your explanation of this tutorial was wonderful especially the voltage divider section. Keep up the good work. I am having an exam next week Tuesday and I believe this tutorial will do me a lot of good. GOD Bless you.
I hope you realize the impact you're having. I hope you realize you're teaching many more students than the ones you see. I hope you realize that some of us don't have good teachers or we just didn't understand the material when it was presented in class or our books are poor but we can come on here and watch your videos two, three or ten times until we understand. I hope you realize that what you are doing is greatly appreciated and is having an impact beyond your institution. Lubbock, TX
Thank you M. Arda y, and thank you for including what country you are writing from. Turkey, no less. One of the cradles of the western civilization, and of the beginning of humankind perception of the electrical phenomena: Thales of Mileto.
Thank you Mr. Roliny Chupetin for all these alsome videos, saving lives here! For me the nicest thing about them is that I can have an overall understanding about one matter, with all the concepts together. IMO usually teatchers want the students to repeat an reapeat each step, what makes the students loose the overall concept. Best regards.
Hi.very nice approximations.. Is it posssible to make R2 > R1? Why does the voltage Rc is 3/4 of the half and the voltage Re is 1/4? Is it possible to make them equal? VRc = BRe =7.5/2
It is clear from your closing remarks that you have designed a transistor stage has 2 outputs: Ve: an IN-phase voltage output at the emitter Vc ; an OUT-of-phase voltage output at the collector. Vc ~(5.6/2.2)Ve , ACgain=x2.5 ...of course this circuit is NOT a typical AC amplifier due to the unbypassed emitter.
Mr. Martin, thank you for your comments. In reality it is an AC amplifier. But we are looking at the DC bias. The emitter resistor bypass capacitor, and the two coupling capacitor (one to the previous stage and one with the following stage or perhaps the load) in a DC model are open circuits, that is why you don't see them there. Please remember that the impedance of a capacitor is Zc = -j/(wC). In DC, the impedance of each one of those three capacitors in infinity, an open circuit, so they vanish from the action. Again, thank you for the comment, because the same idea may have been lurking in the minds of other of my very dear viewers/followers/fans/students.
The best teacher on TH-cam, on any subject; period.
I love your enthusiasm and support.
by far the best explanation of bjt amp design I've found over the last two weeks of studying them. thank you so much for your great work!
First time I've ever heard anyone work out the design from the beginning, thank you!
So many thanks for your extremely kind words, Mr.Lubbock. With your permission, I may put it in my teaching dossier, for next year "quality assurance of teaching" review. Sincerely.
The best explanation I have ever seen by far of the design of a simple common emitter circuit.
The only video I have seen that not only explain the bjt biasing theory, but also (and more important), how to set resistor values to a proper biasing given a specific Q-point.
Mr Rolinychupetin. Your explanation of this tutorial was wonderful especially the voltage divider section. Keep up the good work. I am having an exam next week Tuesday and I believe this tutorial will do me a lot of good. GOD Bless you.
I hope you realize the impact you're having. I hope you realize you're teaching many more students than the ones you see. I hope you realize that some of us don't have good teachers or we just didn't understand the material when it was presented in class or our books are poor but we can come on here and watch your videos two, three or ten times until we understand.
I hope you realize that what you are doing is greatly appreciated and is having an impact beyond your institution.
Lubbock, TX
Your tutorial helped a ton in my introduction to electronics final. I can't thank you enough. Regards from Turkey
Thank you M. Arda y, and thank you for including what country you are writing from. Turkey, no less. One of the cradles of the western civilization, and of the beginning of humankind perception of the electrical phenomena: Thales of Mileto.
Excellent class sir. BTW, you have a voice of a gentleman. Thank you!
Thank you Mr. Roliny Chupetin for all these alsome videos, saving lives here! For me the nicest thing about them is that I can have an overall understanding about one matter, with all the concepts together. IMO usually teatchers want the students to repeat an reapeat each step, what makes the students loose the overall concept. Best regards.
Wow! the best explanation of the subject i've ever heard. Thanks for that. Thanks from Poland!
Thank you Mr. Przezdziecki. You are only a few kilometers (miles) away.
very very nice and neat explanation. Better than a book description. It is not a struggle anymore, its fun !
Man GOD bless you, you just teach me what my teacher couldn't.
Best explanation I have seen yet. Thanks.
Huge thanks from from Norway, these videos has helped me immensely =)
You are welcome, thank you for reporting where you're writing from.
Finally someone♥️
Nice explanation, very easy to understand. Big thanks from Malaysia
Thank you, Mr. Heidy from Malaysia. Greeting from Canada.
clear explanation..perfect voice..happy learning from an automation engineer college student in Greece..thank u sir!
I appreciate you making these videos... I am just sitting and watching the videos :) great they are...
This was excellent instruction. Thank for our effort.
Glad it was helpful!
A really nice and elegant explanation. Kind regards. Nick, UK. Physics and maths instructor.
+Nick Allen Thank you.
Better than my teachers explanation. Cheers roliny
Wow this is the best walk-through of this I'v seen!
you are one in a million. Thank you!
I love your enthusiasm and support. Thanks.
You are Sir, A Master Teacher! Thanks a lot!!
Wow, thanks!
Hi.very nice approximations..
Is it posssible to make R2 > R1?
Why does the voltage Rc is 3/4 of the half and the voltage Re is 1/4?
Is it possible to make them equal?
VRc = BRe =7.5/2
Greeting from Indonesia, thank you very much you helped me so much...
i studied Computer Engineering.
TH-cam algorithm, I love you!
beautifully presented and explained. loved it.
A very clear and logical explanation. Thank you!
Thanks a million. This was very helpful.
perfect explanation! thank you! :D
I didn't understand how you distribute the voltage across RC and RE please someone explain to me ):
Half of Vcc is given to Vce (the voltage between the emitter and the collector) while the other half is split 3/4 to RC while 1/4 to RE.
Wow thankyou so much from Australia !! :)
Thank you for your encouragement and for reporting where you are writing from :)
Thankyou from sydney australia
Nice to hear from you, itzlagana from Sydney, Australia. You're welcome!
Your a great teacher, carry on I am learning loads!
Awesome video, but how do I determine the values if I have a predetermined voltage gain of 35?
a very good explanation im designing a ce amplifier two stages and you really helped!! thanks a lot
Very clear explanation.
Glad you think so!
great work sir
Nice work - well done!
Great job, i appreciate it very much, ill see more off your videos!
It is clear from your closing remarks that you have designed a transistor stage has 2 outputs:
Ve: an IN-phase voltage output at the emitter
Vc ; an OUT-of-phase voltage output at the collector.
Vc ~(5.6/2.2)Ve , ACgain=x2.5 ...of course this circuit is NOT a typical AC amplifier due to the unbypassed emitter.
Mr. Martin, thank you for your comments. In reality it is an AC amplifier. But we are looking at the DC bias. The emitter resistor bypass capacitor, and the two coupling capacitor (one to the previous stage and one with the following stage or perhaps the load) in a DC model are open circuits, that is why you don't see them there. Please remember that the impedance of a capacitor is Zc = -j/(wC). In DC, the impedance of each one of those three capacitors in infinity, an open circuit, so they vanish from the action. Again, thank you for the comment, because the same idea may have been lurking in the minds of other of my very dear viewers/followers/fans/students.
Thank you so much
You're most welcome
how do you determine the value of beta?
i was lost ....Thank you from jordan
You are most welcome, Mr. Naif. And thank you for including your country in your post. Sincerely.
U saved the day!!!!
Awesome explanation! Love your videos
Thank you!
Thanking you sir
You are welcome.
@truckrally Jag är glad att mina videor är bevakade i Sverige.
Sound advice!
THANKS A LOT!!!!!
hero
😇😇😇👍👍👍🙏🙏🙏 really good, great job.