Inverse Trig Functions With Double Angle Formulas and Half Angle Identities - Trigonometry

[@TheOrganicChemistryTutor]

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This is the only place where I learn maths without getting any headaches. Thank you so much for breaking these nerve-wracking questions for us.

[@papiyaraut6518]

So true!!

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Best teacher I've seen on this planet

[@DixieNormus420]

"So if you saw a terrible looking expression like this...." LOL! It's almost like you read my mind. Every time I see a terrible looking expression I come and visit one of your videos!

[@inongesimenda8600]

THE LAST PART OF THE VIDEO WAS LITERAL MAGIC WHAT!?

[@georgesadler7830]

MR. Organic Chemistry Tutor, thank you for explaining the Inverse Trig Functions with Double Formulas and Half Angle Identities in old fashion Trigonometry.

[@BarbaraRademacher]

Very, very helpful. I like your approach very much.

[@tacendaeunoia7667]

12:05 it could've been in the 3rd quadrant as well . (You didn't mention any sort of angle restrictions)

[@ndumisothulani]

You deserve a prize my teacher 🔥🔥

[@medinapaoloc.364]

Kindly explain; why inverse half angle aren't in square root? Just like... Cos²theta = 1 + Cos(theta) / 2... Why are not in square root?

[@jurguengarcia6995]

Very helpful.. Thanks 😁👍

[@tonexlets2183]

Thank you very much!!!🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

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[@ashirahcox6961]

@3:22 how did you get 13 as the hypothenuse?

[@JoshuaMiguelDeGuzman]

Same question

[@KK-ni7tp]

same question +2

[@Ivy-jo7tl]

@@KK-ni7tp Pythagorean Theorem you goofy ahhhs

[@no.8952]

The hypotenuse would have to be 13, as the opp and adjacent sides were 5 and 12, which are the two sides of the 5, 12, 13 triangle.

[@abhyaskanaujia4910]

Thank you so much

[@dionagona8205]

How do you determine what quadrant it’s in?

[@pratyu.sheesh]

All ratios positive + 1st quad
Sin and cosec positive, others negative in 2nd quad
Tan and cot positive, others negative in 3rd quad
Cos and sec positive, " " in 4th quad.
Remember it like A-S-T-C anticlockwise.
A- All
S- sin ( and cosec ofcourse)
T- tan
C-cos

[@jinnjinn5567]

You can also memorize the range of inverse trig functions if you would like
and you can multiply radians by 180/π to convert to degrees
*Range of inverse trig functions*
arcsin [-π/2, π/2]
arccos [0, π]
arctan (-π/2, π/2)
arccsc [-π/2, π/2]
arcsec [0, π]
arccot (0, π)

[@疏影横斜水清浅暗香浮]

Remember All Students Take Calculus

[@aphelmusonda5253]

thenk you proffessor

[@sophie-mp6bz]

thank you!

[@uhno2378]

Why doesn't it exist in Quadrant 3 and 4

[@thefluffygenius4857]

Really cool!

[@aceaj2620]

I don’t understand, so if I have sin2 theta = 0.87 how do I find theta

[@InexorableVideos]

You don't actually need double angle formulae for this.
I am going to use X instead of theta but it's the same concept.
To isolate the X in sin(2X)=0.87, you just need to perform the inverse function on both sides. So you do arcsin(sin(2X))=arcsin(0.87) (this is sin to the power of minus one on a calculator, or shift sin) then you have 2X≈60.46 degrees because the arcsin cancels out the sin function. So divide both sides by two you have X≈30.23 degrees.
Hope this helps.

[@darkshadow5845]

0:01 I would cry

[@SuzanneTegroen]

when i find the third angle it is giving me a decimal number

[@SuzanneTegroen]

cos(sin^-1 8/25)

[@siddhantsrivastava4353]

How do you determine what is the opposite number of the triangle

[@bababooey8820]

Pythagoran teorem.

[@blumckenzie]

a^2+b^2=c^2

[@brandanburgess8652]

life saver

[@krishnaveniveedhi4451]

Only good