lets say the angle (b+2,a) made with x-axis is theta . so Tan(theta)=a/(b+2) now , adding pi/4 in theta as rotation in anticlokwise will increase the angle with x-axis by pi/4. we know the new coordinates are (-1/√2 , 7/√2) . Tan(theta+pi/4)=(7/√2)/(-1/√2)=-7 => Tan(theta) + 1/1-Tan(theta)= -7 by solving we get ,Tan(theta)=4/3 a=4 , b=1. so 2a-b=7
We can assume x= rcos theta and y=r sin theta Then tan theta= y/x Again tan (π/4+ theta) can be found And distances can be compared It shud be (a+b+2)/√2, (a-b-2)/√2
Do you like the new format 😅
Great 😂
Format is great but try to improve the camera angle
I think this ques is present in cengage coordinate geometry
don’t worry, you ear phone is working just fine 😂
Maruti forest society me rehte ho kya?
@@lure0id haan shi bola
But if you remember that rotation matrix this becomes more easy nd fast!!
lets say the angle (b+2,a) made with x-axis is theta . so Tan(theta)=a/(b+2)
now , adding pi/4 in theta as rotation in anticlokwise will increase the angle with x-axis by pi/4.
we know the new coordinates are (-1/√2 , 7/√2) .
Tan(theta+pi/4)=(7/√2)/(-1/√2)=-7
=> Tan(theta) + 1/1-Tan(theta)= -7
by solving we get ,Tan(theta)=4/3
a=4 , b=1. so 2a-b=7
Rotation sunte hi physics walo ko rolling without slipping dimag mein aata hai, hamein complex numbers :)
Loved the bloopers 😂 keep working hard fam 💪
We can assume x= rcos theta and y=r sin theta
Then tan theta= y/x
Again tan (π/4+ theta) can be found
And distances can be compared
It shud be (a+b+2)/√2, (a-b-2)/√2
Hii bhaiii
Rotn matrix watching from hell🤔....
Content top class❤❤ Audio quality third class 😢😢
💀damn , I missed!
Par mujhe to sab sunai de raha
Solution?
Aap Agra m khaa se ho?
Same approach is used in vector too
my head rotated 360 when i heard your voice only on the left side of my ear in headphones
😂
mene 15 seconds me kia tha bina PEN UTHAYE
Yes lmao very easy i dont think anybody does the whole long method
i did in same way
bamboozled
me who did it in less than 10 secs
Are Einstein baba ap?😮
@@TobiZet_9 bhai idk why but when i saw the question the first thing that came in my mind is parametric forms of transformed points 🤣🤣🤣
first