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JEE SIMPLIFIED SUBJECT
เข้าร่วมเมื่อ 22 ต.ค. 2021
JEE Math and Physics like Never Before.
( This channel contains full course video of JEE Simplified )
( This channel contains full course video of JEE Simplified )
Right way to rotate #jeemains2025
I hope you like the video, it took some time to shoot it as I ain't used to of face cam content, do join our telegram community - t.me/s/jeesimplified
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What is {SO60}? - courses.jeesimplified.com/courses/SO60-Physics-11th--SO60-Math-12th-66aa723563695c5cb00b3f32-66aa723563695c5cb00b3f32
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00:00 Solving
01:47 Bloopers!
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What is {SO60}? - courses.jeesimplified.com/courses/SO60-Physics-11th--SO60-Math-12th-66aa723563695c5cb00b3f32-66aa723563695c5cb00b3f32
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00:00 Solving
01:47 Bloopers!
มุมมอง: 2 401
วีดีโอ
Terror of Rotation Destroyed | Concept Crunch - Episode 11
มุมมอง 4.9K16 ชั่วโมงที่ผ่านมา
🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified Time Stamps 00:00 Behind Trans plus Rotational 10:00 Problem 21:02 HW Problems
The subtle exponential #jeemains2025
มุมมอง 8Kวันที่ผ่านมา
We hope you enjoyed how exponential and expansion can occur so subtly, there's a similar breed where expansion of ln(1 x) is used in un popular ways, to stay tuned with all the rare types and the common ones as well, give a shot to our revision course or Set of 60 program, You certainly won't regret it 😁 Links are given below Course description links courses.jeesimplified.com/courses Time Stamp...
Reminder of Remainder #jeemains2025
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We hope that you learned how fundamental properties can occur at unexpected times, a mix of such unique illustrations must be practices by you in case aiming for top ranks. for that only we offer {SO60} to those who struggle with problem solving Here's the link for more details courses.jeesimplified.com/courses
Silly Mistake Guaranteed | Try it | #jee2025 #2026
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🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified Time Stamps 00:00 Introduction 00:23 Wrong Approach 01:28 Right Approach 02:31 Introduction to R...
JEE Mains went wild
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🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified Time Stamps 00:00 Introduction 00:17 Revision Course 00:53 Solution 1 Starts 05:46 Solution 2 St...
Impulse and Conservation of Linear Momentum | Concept Crunch - Episode 10
มุมมอง 6Kหลายเดือนก่อน
🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified Time Stamps 00:00 Introduction 06:13 Conservation of Linear Momentum 09:07 Problem 1 (Impulse-Mo...
Binomial Series | Concept Crunch | Episode 9
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🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified . . . Time Stamps 00:00 Introduction 01:12 Basic Binomial Series 04:07 Binomial Series involving...
Energy Conservation and Inelastic Process | Concept Crunch - Episode 8
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🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified Time Stamps 00:00 Mech Energy Conservation 03:31 Closed System 05:10 Higher Principle for Energy...
Rotation in Complex Numbers | Concept Crunch - Episode 7
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🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified . . . Time Stamps 00:00 Introduction 00:46 03:00 Rotation without changing the mod 04:13 Rotatio...
Polar Coordinates | Concept Crunch - Episode 6
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🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified Time Stamps 00:00 Interesting Question 00:08 What are polar coordinates? 05:10 Mathematical Deri...
Special Series | Concept Crunch - Episode 5 #jee2025
มุมมอง 10Kหลายเดือนก่อน
🔸To join our Problem-Solving course for JEE Advance {Set of 60} which ensures strengthening, revision, and concept coverage altogether, go here - courses.jeesimplified.com/courses 🔹To join the full syllabus revision course forms.gle/NcywqBrqSE45PhCUA 🔹Join the Telegram community t.me/s/jeesimplified Time Stamps 00:00 Introduction 00:26 Indexing 01:13 Telescopic series begins 01:48 Vn Method - P...
Wedge Constraint | Concept Crunch - Episode 4
มุมมอง 7Kหลายเดือนก่อน
Wedge Constraint | Concept Crunch - Episode 4
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River, Rain Problems | Kinematics | Concept Crunch - Episode 2
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Inequalities | Fundamental of math | Concept Crunch - Episode 1
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Inequalities | Fundamental of math | Concept Crunch - Episode 1
Let's do this together, Concept Crunch! #jeeadvanced
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Future IITIANs assemble! and crack the series #jee2025
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Racing down the Incline | Relative Kinematics | JEE Physics | Day 6 (30 Day Series)
lets say the angle (b+2,a) made with x-axis is theta . so Tan(theta)=a/(b+2) now , adding pi/4 in theta as rotation in anticlokwise will increase the angle with x-axis by pi/4. we know the new coordinates are (-1/√2 , 7/√2) . Tan(theta+pi/4)=(7/√2)/(-1/√2)=-7 => Tan(theta) + 1/1-Tan(theta)= -7 by solving we get ,Tan(theta)=4/3 a=4 , b=1. so 2a-b=7
Solution?
Easy sawal ko complex Bana diya
Yes lmao very easy i dont think anybody does the whole long method
Rotn matrix watching from hell🤔....
But if you remember that rotation matrix this becomes more easy nd fast!!
5:28 we break it like 1/3{whole in sigma [(r+3)-(r)]/(r)(r+1)(r+2)(r+3)) i recently solved the same type q in my adv test edit: the ans for sum to inf is 1/18 edit2: 7:17 i did the divide by 2^n and 3^n on my own but after that it was just unintuitive and also kinda crazyy
Good obs brother
We can assume x= rcos theta and y=r sin theta Then tan theta= y/x Again tan (π/4+ theta) can be found And distances can be compared It shud be (a+b+2)/√2, (a-b-2)/√2
Hii bhaiii
me to neet de raha hu, maine ye kyu dekha
me who did it in less than 10 secs
Are Einstein baba ap?😮
@@TobiZet_9 bhai idk why but when i saw the question the first thing that came in my mind is parametric forms of transformed points 🤣🤣🤣
don’t worry, you ear phone is working just fine 😂
Maruti forest society me rehte ho kya?
Aap Agra m khaa se ho?
my head rotated 360 when i heard your voice only on the left side of my ear in headphones
😂
Content top class❤❤ Audio quality third class 😢😢
💀damn , I missed!
Same approach is used in vector too
i did in same way
Rotation sunte hi physics walo ko rolling without slipping dimag mein aata hai, hamein complex numbers :) Loved the bloopers 😂 keep working hard fam 💪
bamboozled
first
Do you like the new format 😅
Great 😂
Format is great but try to improve the camera angle
I think this ques is present in cengage coordinate geometry
So no one’s gonna talk about the sticky notes in background? The background is mesmerising for maths lovers 💫
Im cooked
For finding angular momentum about a reference point, we first find the AM about the centre of mass of that body, and then assuming the whole body as a point object at its centre of mass, we find the AM of this point mass (i.e. COM) about the external point which was asked.
mza aya bhot , muje geometry abhi interesting lag rhi h , thank you bhaiya for posting this illustration
bhaiya diagram bnane m 3 min lge but ban gya shi , aage ka kch smj nhi aaya kyuki limits nhi pdha
19:23 bhaiya maxima kyu calculate kia apne ?
Most terms were getting cut, pretty good question, looks monstrous but in the end converges to a small expression, took 15 mins..
Bhaiya mere pehle do option aur last option correct aagaya
When we expand the expression say (x+y)^n We are selecting any r terms from a total of n terms For example to find coefficient of y^3 in (x+y)^7 (x+y)(x+y)(x+y)(x+y)(x+y)(x+y)(x+y) We will select any 3 terms out of these 7 thus to select 3 items out of 7 we write 7C3
Priyank bhaiya ne physics chhod diya kya
Power ko distribute ke liye
Congruence modulo and ye without pen paper solved
This can be explained easily by PASCAL'S TRIANGLE👍👍👍 and by Simple Observation of first 2 to 3 power...👍👍👍
Two equations for finding value of 'x' and 'y' 1) ax + by = C 2) px + qy =C (If "C" is the Real Number as- 0,1,2,3......). Can we write or say. "ax+by = px+qy = C" ("ax+by = px+qy") ( Because both are equal to "C"). Is it true or not. please help with example 🙏
I think we can do it also using Pascal's triangle!!
this is due to the no of terms of one term
Guy in my left ear speaking the truth 🗣️🗣️🗣️🙏🏽🙏🏽
My left ear 🗣️🗣️
Doubt if we put n = 3 and r = 2 then ans should be 8 but from this expression it is 4 😢
Gol h Gol h Gol h
We know pascal triangle ❤
While writing the r+1th term we will all the brackets of (x+y)(x+y).... n times From this when ever we expand the net power of each term will have net power of n So now we know that we need to select lets say r brackets outof which we will multiply all the y's and the rest n-r brackets we will multiply the x's And the number of ways we can do is nCr*1 so we will hage nCr*1 type of brackets having the y power as r and x power as n-r hence the term nCrx^n-r y^r ( student of so60 math physics , revision course maths and physics ❤❤❤)
Bohot paisa hai bhai tere paas
@@Ss-xl4xi sabh gareeb nahi hote
Same song in the background bhaiya ?
Your logo is copied
Pnc se prove kiya tha is formulae ko
The ncr is for selecting the number of brackets to multiply iykwim
those saying 'pascals triangle' is❗️ not❗️ really the answer. Think where pascals triangle came from- like they are the coefficients, yes, nCr but that doesn't answer his question. Think like (x+y)^2= (x+y)(x+y) Now x^2 can come in only 1 way -> x×x so coefficient is 1. and xy can come in 2 ways ->x×y+y×x (2 brackets) so 4C2 idk if i could explain well
While writing the r+1th term we will all the brackets of (x+y)(x+y).... n times From this when ever we expand the net power of each term will have net power of n So now we know that we need to select lets say r brackets outof which we will multiply all the y's and the rest n-r brackets we will multiply the x's And the number of ways we can do is nCr*1 so we will hage nCr*1 type of brackets having the y power as r and x power as n-r hence the term nCrx^n-r y^r
Please turn the music up I am able to hear your voice 😡
10:36 ln(i) is not simply i.pi/2 but rather 2ni.pi/2... so there will be infinitely many solutions
Use induction to proof😎