9701/42/O/N/23/Q2 Cambridge International A Level Chemistry 9701 October/November 2023 Paper 42 Q2
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- เผยแพร่เมื่อ 26 ต.ค. 2024
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⬇️⬇️Useful 9701 Cambridge International AS & A Level Chemistry Paper 4 playlists⬇️⬇️:
9701/41/O/N/23 │ (9701/W23/41)
• 9701/41/O/N/23 Cambrid...
9701/42/O/N/23 │ (9701/W23/42)
• 9701/42/O/N/23 Cambrid...
9701/41/M/J/23 │ (9701/S23/41)
• 9701/41/M/J/23 Cambrid...
9701/42/M/J/23 │ (9701/S23/42)
• 9701/42/M/J/23 Cambrid...
9701/42/F/M/23 │ (9701/M23/42)
• 9701/42/F/M/23 Cambrid...
9701/41/O/N/22 │ (9701/W22/41)
• 9701/41/O/N/22 Cambrid...
9701/42/O/N/22 │ (9701/W22/42)
• 9701/42/O/N/22 Cambrid...
9701/41/M/J/22 │ (9701/S22/41)
• 9701/41/M/J/22 Cambrid...
9701/42/M/J/22 │ (9701/S22/42)
• 9701/42/M/J/22 Cambrid...
9701/42/F/M/22 │ (9701/M22/42)
• 9701/42/F/M/22 Cambrid...
Hi all, please help to subscribe, like, and share with your friends if you find this video helpful. You can access the full playlists from the description. Your support is much appreciated.
You're the best Sir 👏 Thanks so much
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Your explanation is so good tq 🙏
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Hello, for dii) if solubility has decreased due to common ion effect, doesn't that increase the concentration?
in (e)(ii), the formation of more solid will not increase the solid concentration. You need to understand the concentration of solid is always constant. The concentration here means the amount of solid that "dissolved" to form the respective ions.
hi. as you said in the start if we add OH it will react with C6H5COOH. i wanted to ask why will it not react with the negative C6H5COO ion in product side or why it will not react with H+ ions to neutralize it?
You need to understand how the buffer solution works. OH- is a base and it will react with the acid. Normally we don't use H+ as it is not the buffer species.
@@i.love.theamkl thankyou for replying and helping out
1:59 is it wrong if I mention just h+ and oh-
the answer just not specific enough, means too general as it is not involving buffer species.