DeMorgan simplification
ฝัง
- เผยแพร่เมื่อ 26 ก.ย. 2018
- #digitalelectronicsstephenmendes #electronicsstephenmendes
Using DeMorgan theorem to simplify Boolean functions involving nand and nor gates
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Thank you I did not understand how to put the brackets and your video helped me a lot 👍
Beautifully done.
Man i love the accent and this guy explain better than my CS teacher during online classes
Just a big thank you for explaining this in a very simple way.
Kind Regards
Thanks for your comment.... glad I was able to help you
Thank you so much for this! In my course we're told to just memorise DeMorgan cases, but understanding them makes it so much easier.
Thank you so much for this.
Excellent work 👏
Thankyou so much for the explanation..its realy useful and clear❤❤ continue teaching.
thank u so much, i understand demorgan simplification now :)
Thanks a lot sir, it really helped
thanks for example with double negation rule used
Thank you sir. I fucking love you.
This is the best explanation you will find on this topic...... and there are videos for all other topics in electronics as well ....... I am helping you succeed with your education challenges.... spread the word ..... and then ASK QUESTIONS if you have problem...... how can there be a simpler approach ? ? ...... watch the video(s) and follow the steps 🙂🙂🤞👌👍
this is acc pretty simple
what if there is the same number of and and or operators, how do you know which one is dominant
@@santoszuniga7127 in some cases, you may need to use brackets...... however, a DeMorgan's BAR over an expression acts like brackets (and whatever is under it is treated as if it was enclosed in brackets)
Thank you from Namibia; Africa I under this topic better
All the way to Angola!
Thanks sir ❤
why does the middle in 3:25 did not became a B even when there is two bars? and why did it became addition?
It does become a B watch some more to 4:35 ..... cause I am doing it in slow motion as I explain what is happening..... it becomes addition (actually OR operator) because that is what DeMorgan simplification is all about ...... changing AND to OR ...... or OR to AND.... every time you remove a bar that goes over an expression
5:20 This is not right because A'C doesn't have brackets around it.
Your rule has an exception, unless you made a mistake.
'Brackets must be added once 'bigbar' is removed, but only to variables that share an addition sign.'
He clarifies in 7:20
🙂.... all comments are appreciated..... this is how students LEARN ..... and videos get improved 😁
Wow 👌
Great video. @9:59 How did you come with the final expression. Than you.
the answer to your question may be found by watching (my video on SOP and POS ) th-cam.com/video/ss6N2uUEiV4/w-d-xo.html
BUT if you still don't "get it" after watching that video on SOP and POS then I can try to explain it some other way 😊
Thank you so much for the quick response!
why are there no brackets on the first sub expression?, even though you remove a big bar from it?
Brackets are required for terms connected with OR operator ...... this is due to "precedence of operators" ...... AND takes precedence over OR (so no brackets are required)..... just like multiplication and division take precedence over addition and subtraction ..... if you were doing mathematics you would bracket addition of terms but not multiplication .... "precedence of operators" is a concept in algebra that also applies to transcendental functions ..... and leads to universal "hierarchy of operations"
@@StephenMendes thank you so much
Could you please solve this by demorgan's theorems A+BC'
A+BC is already in its simplified form so there is nothing to "solve" (it cannot be simplified any further) ..... if you want the Truth Table (I have it in one of my videos) ..... there is 0 in the first 3 rows..... and then it is 1 for all the other rows.... if you need something else you can ask again and be more specific about what you are trying to do
whats the step for 8:10 u just went so fast
the official step is called "distributing multiplication over addition" (actually distributing AND over OR in boolean logic) ....... speaking loosely I call it "multiply out the brackets".... in any case ac(b+d)(e+f) = acbe + acbf + acde + acdf ..... best wishes 😊
This is a nice video but, the content move to fast for many others that may not have some basic understanding of boolean algebra
TH-cam allows to slow down videos...... or simply pause video..... or rewind and watch over section giving trouble..... my experience has been that videos that move slowly cause people to get fed up and leave ...... probably because people watching TH-cam for education purposes have limited time.... thanks for your comment 👍
great video - thanks - may I ask your accent - is it Irish or Jamaican?
Actually it's Barbadian..... I live on Barbados an island in the Caribbean
@@StephenMendes thanks! I looked at more of your videos and realised where you lived - looks like a paradis. Great logic videos - very useful thanks
@@djneils100 I am trying to build a couple of the more interesting digital projects here on the PB502 logic trainer that I reviewed in another vid...... so if you like the DIY stuff .... you might want to hang around the channel for a while 😊.... thanks for your comments
Please if you have z'+z'what will be the answer
The answer is z'
Couldn´t the first example be simplified even more than it was?
you did not watch the entire video ..... the final simplification is at 9:26 ..... A'C
I am puzzled, "bif bar" is that supposed to be "big" or is this a term on its own? ( 6:07 )
Big Bar is what I meant ...... my "G" has often been confused with an "f"..... sorry
Thanks a lot and dude which accent is this
Barbados ..... it's a small tropical island in the Caribbean ...... and I native there 🙂
Ok....
are you a Barbadian?
Yes I am
yup I can tell
Yes
yes
Watch at 2x speed and you will achieve normal human speed.
this just confused me even worse
I do not know why.... you simply have to FOLLOW THE STEPS ... one after the other and they will lead you to the correct solution every time .... thousands of people have been helped by this video..... watch the video over and over and over again until you can perform the steps for yourself
@@StephenMendes Doesn't help that you don't point to what you're talking about for starters
@@DC-zb7uf if you can identify the place in the video where you having distress... I am more than willing to help you....... thousands of people have found this video helpful in understanding De Morgan Simplification (which is based on a few SIMPLE and REPETITIVE steps) .... this video "number one" on understanding this topic.....so I am sure that if you make the effort you can understand it also....please identify what it is that is "giving you stress"... thank you
@@StephenMendes Sir this is indeed a confusing topic for some but if basics are clear, its damn easy. You helped me alot, thanks..😊😊
@@shreyanshsolanki9139 Thanks for your comments .... glad I could help you
Damn my teacher makes this confusing I barely understood can you please help me understand it?
just re-watch the video and stop it as needed to make notes...... you need to actually concentrate on what I am doing........ this is not an episode of "House" 😊
@@StephenMendes I understand how to break the lines and change sign however when there is alot of bars I don't understand how to break the bar
@@User89018 the procedure is the same ..... start from the TOP bar (and then progressively repeat the procedure for all subsequent bars below that )..... 1. remove the bar 2. change operators (AND to OR and OR to AND) 3. Put bar over each sub-expression...... that's all there is to it ..... it's shown in the video 😊..... so I can't understand .... can you give an example ?
@@StephenMendes I understand to do demorgan now thanks! I had some homework questions I think I them right however I still have trouble with drawing logic diagram from boolean expression and simplify boolean expression.
@@User89018 keep at it.... you'll get thru .... did you see my other video on those topics ?.... check the playlist
Plz solve ( (A+ B+c)d)'
dA + dB + dC
U dng lots of confusion...like our mam 😥😥😥😥😖
in 8:35 you have a strange expression. I have never seen the distribution property being used this way.
The distribution property should have given you.
(A'CA' + A'CB) (B'+C)
then doing it again
A'CA'B' + A'CA'C + A'CA'C + A'CBC
Important step when teaching a video. Students might get confused, especially undergrads.
Hey there.... thanks for your comment...
"I have never seen the distribution property being used this way."..... such use is allowed in Boolean Algebra (where the set of symbols is restricted to zero and one) and I assure you there are textbooks that support it...... however I agree with you that students need to understand how to EXPAND as well as SIMPLIFY any algebraic expression 🙂
Are u indian
I don't think so😐
No I am not Indian
Are you fracai