Simplification of Boolean expression | Boolean algebra simplification examples | Mruduraj

[@westgrant]

Excelent, very clear, and easy to understand

[@Manisha-s2i2s]

for the 1st question the ans is : AC+BC'

[@veeraragavanveeraragavan2339]

Wonderful teaching sir

[@LearningVibes]

Thank you so much.
Where do you study?

[@kyrpap3953]

at the boolean expression F(A,B,C)=A'BC+AB'C+ABC'+ABC i found C(AXORB)+AB. Is that correct?

[@akashKumar-xm1eq]

Very nice sir 👍

[@ChandramouliPatra-l5r]

1)AC+BC' and 2) C+C'(B+A)

[@TTdairy-b5p]

My 2nd answer is B+AC’+BC’+A’C

[@MihretAyalkbet-k2x]

u are right but this is not the most efficient circuit, the answer is B+c

[@oconsertador9021]

Thank you

[@LearningVibes]

you are most welcome
You can refer this playlist to learn more in digital electronics
th-cam.com/play/PLho7ncbqgQbsTVOcMNViMIRSnARSTdnv1.html

[@KamrulZaman-rw4ow]

first is AC+BC' and second is A+B+C

[@MihretAyalkbet-k2x]

the second question answer =B+c

[@susannegwangwadza3643]

On the first one I got F(ABC) = A + BC ( not)

[@3ygie556]

AC ( B' +B) + BC'
AC (1) + BC'
AC + BC'

[@TimothyGabutu]

Sir can you comment the answer so we can confirm

[@TTdairy-b5p]

My 2nd ans is B+ac+bc+ac

[@randellmendoza7387]

sir, what's the answer for question 2?
what I got is
CB + AC' +A'C

[@priyankalaad9502]

C'(A + B) + C can someone confirm?