Why don't you add a negative sign in the equation for resistance for dq/dt? I understand that the charge on the capacitor is growing, but isn't the charge on the resistor declining as shown in the previous video?
That's what I wanted to ask about, but only about the negative sign in the last video which when taking the derivative of Qe^(-t/RC) is gonna equal to -(Q/RC)*e^(-t/RC) but he had the best tutorial explanation though
LASSEVIREN1, without the LOAD, how much current in amps can a 4700uf hold store with a power supply DC voltage at +450vdc? the 4700uf filter cap will charge up to +450vdc but how much current is the 4700uf holding storing? What formula can I use to calculate how much current the filter cap is storing in amps?
Sir How about a new video explaining a circuit placing or now adding a PARALLEL RESISTOR WITH THE CAPACITOR and the mathematical physics analysis step by step as you have done here on this video. Thank You.
You don't explain your terms. You don't explain the relationships. You don't explain what "dq'/dt" is, and why it is important. Your Q looks exactly like an 8. You don't explain that Q is charge. You don't explain that E is voltage. Your video is very badly presented. You assume that your audience already understands your terms, the relationships involved, and how the equation results. In other words, you explain exactly as if your audience already understands the charging equation and doesn't need your explanation. Unless someone already understands all of the factors and relationships involved, they cannot learn from your video.
@@ahmedkunbargi8096 , I did, from a previous electronics class I had taken at a local college, from a very patient professor who went through everything, step by step, and didn't assume we already knew the equation or the terms. That's why I was so critical of this video. The presenter could have, and should have, explained the elements better, and how they relate to each other.
You made me happy today.
Exactly what I was looking for. Thanks a lot!
Thañks sir for ur video has helped me so much 🙏
How can I give more than one like to your video?
Thanks very much.
It was very helpful
You got the best physics 2 tutorials
I'm glad that I already subscribed to your channel
you are amazing!
This is awesome!!!! Thanks a lot. Saved my life.
Why don't you add a negative sign in the equation for resistance for dq/dt? I understand that the charge on the capacitor is growing, but isn't the charge on the resistor declining as shown in the previous video?
That's what I wanted to ask about, but only about the negative sign in the last video which when taking the derivative of Qe^(-t/RC) is gonna equal to -(Q/RC)*e^(-t/RC)
but he had the best tutorial explanation though
Thank you so much!! Your explanation is very clear!! Thank you again!
Thank you, Kind Sir!
Aapne meri aankhe khol dii...Kab se silly mistake kari jaa rahi thi...😅😂 Thank you so much for this!
Translation:
You just opened my eyes...I had been doing silly mistake..!
😂😅
LASSEVIREN1,
without the LOAD, how much current in amps can a 4700uf hold store with a power supply DC voltage at +450vdc? the 4700uf filter cap will charge up to +450vdc but how much current is the 4700uf holding storing?
What formula can I use to calculate how much current the filter cap is storing in amps?
Sir How about a new video explaining a circuit placing or now adding a PARALLEL RESISTOR WITH THE CAPACITOR and the mathematical physics analysis step by step as you have done here on this video. Thank You.
that was a bad ass ending. the professors equivalent of dropping the mic
really helpful
Sir, plz upload a vedio on DC response of RLC circuit plz🙏🙏
Really informative videos, thanks a lot.
when the equation is E-(dq/dt)R-q/c=0 why is the q of the part q/c not dq? could someone explain?
Because they different between current and charge, C is charge and current by definition was dq/dt (flow of charge)
What if this comes in the recommendation section someday... What will commerce and art students think 😂😂😂
thanks a lot for your efforts
Excellent lecture Sir 🙏🙏🙏🙏🙏
Helped a lot sir..
Thank you sir, I'm grateful
Thank you. All the best in your studies.
wow thank u very much for the video helped a lot!!!!
Thanks a lot!!! You are the best!!
Harder than discharging a capacitor :(
Well done
Thanks a lot ,Sir
Thank youu so much! God blesss u
You don't explain your terms. You don't explain the relationships. You don't explain what "dq'/dt" is, and why it is important. Your Q looks exactly like an 8. You don't explain that Q is charge. You don't explain that E is voltage. Your video is very badly presented. You assume that your audience already understands your terms, the relationships involved, and how the equation results. In other words, you explain exactly as if your audience already understands the charging equation and doesn't need your explanation. Unless someone already understands all of the factors and relationships involved, they cannot learn from your video.
youch, i can feel that student frustration through my screen. hope you figured it out, buddy
@@ahmedkunbargi8096 , I did, from a previous electronics class I had taken at a local college, from a very patient professor who went through everything, step by step, and didn't assume we already knew the equation or the terms. That's why I was so critical of this video. The presenter could have, and should have, explained the elements better, and how they relate to each other.
i didnot understand this but now i understand thanksssss