Moose are very large. The biggest on record is 2.3 meters tall and 680kg. To put that into perspective, they would have to duck underneath basketball hoops, and most people are eye level with the _bottom_ of the chest of a moose. It can literally step over slightly shorter people lol.
Hey! I'm catching up with your streams, almost at a real time already. Wanted to share my opinion on a train problem. I think you overthink it a little. Yes, you cannot feed a buffer from 2 conveyors and use this buffer to feed 2 freight car at the same time, but you can feed each conveyor to it's own buffer and then each buffer to each freight car with 2 conveyors. This way you will achieve the same result just with one extra buffer. I did it a lot of times and it never failed me. Otherwise thanks for these streams, it makes my working hours much more pleasant.
By the way, I don't know if later streams address this (potential) issue, but the way that your ore comes into the train stations has potential for irregularity (it won't happen for a while due to backlog). Due to how your industrial storage containers (the ore buffers at the extraction sites) work, the output does not split evenly; if the buffer is ever emptied, only one station will fill with ore until it backs up. I don't know if this will become a relevant problem (due to the miners and stations working for a while without offloading the ore), but if it does, it probably can be fixed by simply splitting the output belt coming from the miner into two separate buffer containers before going into the train station. That way the splitters ensure that both stations get equal amounts of ore without relying on one side to back up first.
@2:05:25 Can't you still achieve the equivalent of max belt speed if you split across multiple cars, with a separate storage buffer for each? Let's say you have two outputs at 780 units each from your factory and a max belt speed of 780. We can't load into one car, because that would be 780 x2 belts (1560) max rate into the storage, and then the same 780 x2 belts max into the car minus the loss during loading. But if you pre-split your factory output into 4 belts (now each belt is carrying 390) and then into two industrial storage and each storage with two belts to its own freight car. Each storage/car still loads at the max rate of 780x2 minus the pause during loading, but your rate into each storage is now only 390x2. This difference means you'll make up the loss, and still match your total factory output (1560) because you're filling two cars. So half the load rate per belt/car, but twice as many belts/cars (390x2x2 = 1560) while creating a gap between max belt speed (which didn't change) and load rate per belt large (which you halved) large enough to mitigate the loss from loading pause. Am I missing something?
No? Basically, you are saying that the initial belt going to the train station, if it is split and then put into a buffer before the station, it would work. Long story short, if you split your input belt and have separate buffers for each line of the split, it would allow it to work smoothly as well as using an industrial buffer into 2 train station inputs.
@@Dally1991 No, I didn't misunderstand anything, I was affirming what you said. Your scenario outlined above would work just fine. I just reiterated it succinctly in order to clarify my context, though it seems I still failed. The "No?" statement was to your question if, "Am I missing something?"
@Dally1991 No problem, text-based communication is like that. One side could mean to say one thing, and the other can take it a completely different way. Hope you have a great day!
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Moose are very large. The biggest on record is 2.3 meters tall and 680kg. To put that into perspective, they would have to duck underneath basketball hoops, and most people are eye level with the _bottom_ of the chest of a moose. It can literally step over slightly shorter people lol.
Hey!
I'm catching up with your streams, almost at a real time already. Wanted to share my opinion on a train problem. I think you overthink it a little. Yes, you cannot feed a buffer from 2 conveyors and use this buffer to feed 2 freight car at the same time, but you can feed each conveyor to it's own buffer and then each buffer to each freight car with 2 conveyors. This way you will achieve the same result just with one extra buffer. I did it a lot of times and it never failed me. Otherwise thanks for these streams, it makes my working hours much more pleasant.
By the way, I don't know if later streams address this (potential) issue, but the way that your ore comes into the train stations has potential for irregularity (it won't happen for a while due to backlog). Due to how your industrial storage containers (the ore buffers at the extraction sites) work, the output does not split evenly; if the buffer is ever emptied, only one station will fill with ore until it backs up.
I don't know if this will become a relevant problem (due to the miners and stations working for a while without offloading the ore), but if it does, it probably can be fixed by simply splitting the output belt coming from the miner into two separate buffer containers before going into the train station. That way the splitters ensure that both stations get equal amounts of ore without relying on one side to back up first.
Water in copper refineries are wrong (you are pushing 780 as in caterium ones, but copper needs just 520 - so 3 extractors at 72.222% for each line)
Depot for high speed connectors;) don’t forget
@2:05:25 Can't you still achieve the equivalent of max belt speed if you split across multiple cars, with a separate storage buffer for each?
Let's say you have two outputs at 780 units each from your factory and a max belt speed of 780. We can't load into one car, because that would be 780 x2 belts (1560) max rate into the storage, and then the same 780 x2 belts max into the car minus the loss during loading. But if you pre-split your factory output into 4 belts (now each belt is carrying 390) and then into two industrial storage and each storage with two belts to its own freight car. Each storage/car still loads at the max rate of 780x2 minus the pause during loading, but your rate into each storage is now only 390x2. This difference means you'll make up the loss, and still match your total factory output (1560) because you're filling two cars. So half the load rate per belt/car, but twice as many belts/cars (390x2x2 = 1560) while creating a gap between max belt speed (which didn't change) and load rate per belt large (which you halved) large enough to mitigate the loss from loading pause. Am I missing something?
No? Basically, you are saying that the initial belt going to the train station, if it is split and then put into a buffer before the station, it would work. Long story short, if you split your input belt and have separate buffers for each line of the split, it would allow it to work smoothly as well as using an industrial buffer into 2 train station inputs.
@adamwalker3560 You completely misunderstood what I said and then explained to me exactly the same thing I originally said. -_-;;
@@Dally1991 No, I didn't misunderstand anything, I was affirming what you said. Your scenario outlined above would work just fine. I just reiterated it succinctly in order to clarify my context, though it seems I still failed. The "No?" statement was to your question if, "Am I missing something?"
@@adamwalker3560 Well, then I'm the one who misunderstood. My apologies for that!
@Dally1991 No problem, text-based communication is like that. One side could mean to say one thing, and the other can take it a completely different way. Hope you have a great day!
Fewer circuit boards!