6.3 - Orthogonal Projections

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  • เผยแพร่เมื่อ 12 ม.ค. 2025

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  • @YasinFarid04
    @YasinFarid04 8 หลายเดือนก่อน

    The best approximation theorem simplifies complex problems by providing a clear path to finding optimal solutions

  • @sarahstets
    @sarahstets 8 หลายเดือนก่อน +1

    One video down for rewatching them all

  • @userozancinci
    @userozancinci 3 ปีที่แล้ว +3

    Totally underrated bro thanks a lot!

  • @nicholaspisano37
    @nicholaspisano37 ปีที่แล้ว +1

    Do you care about whether we simplify fractions or not?
    Also, this overlaps so incredibly well with calculus 3, except for the fact that we did all of this in August.

  • @browncow7113
    @browncow7113 ปีที่แล้ว

    Bonus point attempt: If we have a vector/point that can be written as a coordinate with respect to a bunch of axes then "the projection of that vector with respect to those axes" is just equal to that coordinate. If you have a fly on a piece of paper and shine a light on it from directly above, its feet are touching its shadow.

  • @Elijah_Hoenig
    @Elijah_Hoenig ปีที่แล้ว

    So for an orthonormal matrix U whose columns form the basis for W; UᵀUx = x, but UUᵀx = x̑.

  • @nicholaspisano37
    @nicholaspisano37 ปีที่แล้ว

    Also, where does the formula for z hat apparate from?

  • @mattg9601
    @mattg9601 3 ปีที่แล้ว

    Could a geometrical conclusion to proof theorem 9 be the fact that the (y-v) vector is the hypotenuse which is always the longest side of a right triangle?

  • @alejandrochavarriagonzalez7024
    @alejandrochavarriagonzalez7024 8 หลายเดือนก่อน

    I think the best way to understand projections is to draw and look at pictures, however, I see now that we can only draw so many dimensions:(

  • @1of1stapha4
    @1of1stapha4 2 ปีที่แล้ว

    You are generational