Fun fact extension: In base twelve, the number 321' is the smallest prime number of that form since 21' = 5 x 5. The smallest base where 21 is prime is base three, convinetly the smallest base where 2 is a digit.
It is because the vector has the values [ number, t , t^2 ], and since t^2 after the transformation is 2t. then the vector will be (0, 2, 0). For example if t^2 after the transformation would be 2t^2 then the vector would be ( 0, 0, 2) but it wasn't
My confusion is I can't help but think of "T" as "designed" to work properly on basis B or basis C, but not both. I guess if it's "designed" for a basis it must be the standard basis, i.e., i, j,k.
I'm taking applied linear algebra in the summer and we have 5 weeks to learn everything. I was going to drop but it was a day later before I could. Test every week and 2 quizzes every week. This is such a horrible way to learn math...
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Great video! You used the examples right out of the text book I'm using but explained the solutions so much clearer than the textbook could do!
Whish I found these at the start of the semester.
This was exactly what I needed to see, thanks!!
This has been the most unintuitive section of the linear algebra book so far
Fun fact extension: In base twelve, the number 321' is the smallest prime number of that form since 21' = 5 x 5. The smallest base where 21 is prime is base three, convinetly the smallest base where 2 is a digit.
I appreciate your fun fact extension. Thanks for sharing.
I don't understand how you got the vector (0, 2, 0) (16:11)
It is because the vector has the values [ number, t , t^2 ], and since t^2 after the transformation is 2t. then the vector will be (0, 2, 0). For example if t^2 after the transformation would be 2t^2 then the vector would be ( 0, 0, 2) but it wasn't
That was actually really cool but also odd for the start of the video fun fact…why only 82…
My confusion is I can't help but think of "T" as "designed" to work properly on basis B or basis C, but not both. I guess if it's "designed" for a basis it must be the standard basis, i.e., i, j,k.
at 11:40 you say T relative to B but write T relative to T. I could be incorrect but wouldn't the subscript be a B?
Yes, absolutely - that should be a subscript of B. Good catch.
Very interesting and confusing topic at the same time. Beginning of the video was more confusing than the rest.
In an serious note, does that mean applying an any operator to a function is, in a sense, applying a linear transformation?
That does seem to be the case, yes.
thanks, could you plz send me book title of this course
Hi, the text is Linear Algebra and Its Applications, 5th Edition, by Lay.
I'm taking applied linear algebra in the summer and we have 5 weeks to learn everything. I was going to drop but it was a day later before I could. Test every week and 2 quizzes every week. This is such a horrible way to learn math...
this is hard to understand for non math majors. im an engineering major and i had a really hard time understanding this.
My immediate question is how high did your coworker check?
I think he check up to 500499...321. But as far as I am aware, no number exists other than the one I talked about that is not prime.