Mesh Analysis with Current Source

Network Theory: Mesh Analysis with Current Source
Topics discussed:
1) Applying mesh analysis in the networks having the current source in a separate mesh.
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#NetworkTheoryByNeso #NetworkTheory #MeshAnalysis

[@UniversalSaad]

Every teacher of NESO ACADEMY is Perfection. They have removed the word complexity from my dictionary. My HUGE respect to you, sir. Thanks for all the efforts you did for us.

[@YouKnowMeDuh]

So simple, why didn't I realize this 2 days ago 🤔 thank you for your help! Hope I remember this for the duration of my circuits learning...

[@HimanshuYadav-qy5sm]

Teaching is 2nd best thing of this channel
Dark theme is still n.o 1

[@imtiazahmad5344]

sir your style of teaching is amazing

[@fanman420]

youre a life saver for electrical engineering classes

[@harrytaylor4360]

Really helpful! just wanted to add that using resistances of 1 ohm in examples like this could be confusing, since as as the coefficient of one is implied, it may appear as though our equations are solely based around current, rather than voltages in terms of (unknown current * resistance constant).
Also, what happened to the passive sign convention? is it not standard?!

[@meck_billions]

thanks much Sir i have understood well your solution
keep on going

[@percybyssheshelley9403]

Thank you...You're a great teacher🖤

[@trevorgleeson5281]

Thank you!! very helpful

[@tunji7120]

you're a life saver g

[@nithyat9025]

Awesome explanation 👍

[@mohsinkhan-ps5wl]

how to apply kvl in a circuit having dependent current and voltage source

[@ArbinSama00]

Best education on TH-cam ❣️❣️❣️

[@deepikarani8309]

Very helpful
Thanks

[@rohitsingla4420]

Best explanation ever

[@ayushsinghpawar4191]

Watching at 1.5x speed. Even considering 2x

[@vinayakisd9849]

😂

[@aanisamanzoor1495]

Same here.... 🙂

[@adhishumarani8567]

God

[@shahidparvez8712]

Same here bro😂

[@sadatiqbalpriom7389]

Here I am contemplating why doesn’t make watching at 2.25/2.5x speed possible

[@jokanolayusuff4820]

Really, helpful.

[@shahidparvez8712]

Thank you sir. I'm dependent on you for my GATE preparation 🥰

[@avinashchowdhury2533]

How do we know the voltage across 2 amp resistance

[@moazelsawaf2000]

Thanks sir

[@chalapakaramya8868]

Gud explanation sir I can understand now this problem

[@continnum_radhe-radhe]

Thank you so much 🔥🔥🔥

[@jaybhattacharya4665]

Thanks for help I was not able to understand mesh analysis in college classes.Now all my doubts are clear.

[@jaydobariya7602]

If current source and voltage source both present in one mesh then what happened??

[@madhumitha5199]

Thank you sir

[@varunchowdary1961]

Good explanation 👍

[@girisvlogs1152]

Tysm sir🙂

[@sreekanth2339]

Thank you SIR

[@Kavyakommu_5089]

Good explanation sir

[@olaayman1900]

thank you

[@nehalkr1924]

Nice explanation

[@yawg333]

how are you combining equation 5 and 4 like that can we have the full method as to how you reached that conclusion

[@yawg333]

i understood. you multiplied equation 5 by 4 times to eliminate current variable I1 when you subtract equation 5 from 4

[@rohitsingla4420]

Excellent

[@tarunchelumalla007]

Thank u bro

[@MohitKumar-iz6bs]

Thanks sir ♡

[@pawanraj-vu9wd]

thanks sir

[@rebekahmoncada8980]

Why is the voltage from I1 not (-2) in the equation? Initially he marks it down as +2 but I was taught that it should be negative as it is going in through the negative terminal...

[@bharathkumar3307]

U r best 👍💯👍💯👍💯👍💯than lecture s ☺☺☺☺☺☺☺

[@daydreameryt7871]

Hello sir I have a question of mesh analysis but I can't solve it can u help me

[@mitchythekid5596]

God bless you sir

[@asadahmadkhan1054]

Sir you are the bast

[@rounaknag68]

Can we solve the mesh analysis problem by nodal analysis method?

[@MANOJSAHOO-ku5et]

Super lecture.

[@m.varunreddy7365]

thanks a lot

[@shex9002]

Frkn love u man

[@yxxshvs]

Thankyou sir

[@al-raffysarip4812]

How to calculate using mesh method when there's a current source and a resistor between two meshes?

[@sritulasigayathrikandiband3520]

use super mesh method

[@davidhhhh721]

I'm not sure I understand, in Mesh 1 you have -(I1-I2) but in Mesh 2 you have -(I2-I1), I'm confused about the signs, and the polarities. I thought we care about the voltage polarity. If we assign the resistor in the middle to be positive at the top and negative at the bottom, then wouldn't Mesh 1 be -(I1-I2) and Mesh 2 to be +(I2-I1)?

[@shreyadas9189]

plz explane how could you get the value of I2...

[@TheRisingSun-INDIA]

Sir you say I3 direction clockwise but you draw it anticlockwise direction

[@Stekaren]

5:15 mesh 3 how did you get -(i3-i1)? the resistor 1 ohm has polarity according to its current direction + -. you're going from - to +, thats +, so 1*(i3-i1) = i3-i1 = +I3-I1?? im thinking at resistor 1 ohm you're doing KVL from the middle essential node and going to the left, with the mesh current not against it so why is the mesh current i3 negative and not positive?

[@bableekumari3143]

Nice sir

[@gonepavankumar207]

Tnqq sir

[@sathviknandyala8413]

What if current direction chamged plzz reply

[@hamzausmani8015]

Shouldn't the equation for mesh 1 be -4i+i2+i3=+2 instead of -2 since the KVL indicates the direction to be negative for the voltage source of 2V.

[@parikalpsingh9231]

its +VE since its going from -ve towards the +ve

[@vasemantwist]

Was taught this too, I’m pretty sure you’re right

[@corpliner1506]

No, you are completely wrong. It is flowing from negative to positive so its a positive voltage gain. If there current was reversed then it would be a voltage drop, therefore it would be -2v, but that is not the case.

[@shivasrivastava721]

Very nice sir

[@ibrajeem]

How do I find the voltage across the current source?

[@harshavardhan9399]

current * equivalent resistance of that mesh

[@vishnuvamshi2927]

Super

[@anitalayal9171]

If current source is given ,, then there is no need to convert it into voltage source? Can u plz tell me when we need to convert the current source to voltage source

[@shex9002]

Only if the question says to, else, it's easier with current sources

[@syedismail1849]

🔥🔥🔥

[@sreekanth2339]

Yes sir

[@munireddy3600]

Determine loop current and power delivered by voltage source, Use mesh analysis

[@munireddy3600]

Answer tell me

[@munireddy3600]

Fast

[@TB-my5ij]

How did you find 12/11 ? I don't understand

[@eg9418]

2 equations, 2 unknowns

[@jatinkohli4279]

Did not get the same

[@kaus05]

Multiply eq by 4 to eliminate I1

[@lbu5543]

@@kaus05 im getting 14/11 can you help

[@kaus05]

What is I1? - 11/12?

[@ShashiKumar-fh3pc]

Sir final answer I not understand

[@kirandevanga6344]

How we will get I2= 12/11?

[@tekkemteja2003]

How sir

[@pierrefabela]

excellent video but the little logo gets in the way...

[@the_indian4606]

👍👍

[@s.m.senses7199]

🙏❣

[@mahendradabgar8107]

Sir ...I can understand very well ...bcz your method is great ..I am student of engineering . I have a equation = what is the use of mesh analysis in real life ,? Means ..any example for device which has this type of circuit and is there use in industry ? Sir please answer .....

[@MrMineHeads.]

Mesh analysis has wide applications and is primarily used when analyzing circuits for voltages and currents. However, saying anything more specific than that is difficult since it is so widely used. It is as similar as calculus to the field of engineering. Fear not, these have a lot of uses when designing circuits and machines, so you are not wasting your time learning it.

[@temngum48]

thanks prof it took me days untill i found this

[@temngum48]

very easy

[@subhasishmallik5603]

Thanks sir

[@powerofpriceaction91]

Why I2=I

[@mosesraja1234]

yes i2=1A

[@priyanshigupta1117]

Should not we perform source transformation here

[@MuskanKhan-xu2gi]

.

[@Ancestor_kcd]

Shouldn't your equation 1 be
-I1 + 4I2 - 1I3 = 2?

[@nimitgarg2531]

No the eqn is correct only

[@shex9002]

No it's 4i1 - i2 = 4

[@mohammadfurqanbutt6867]

Do mesh analysis on circuit having a load resistor and two batteries.

[@davalasabnadaf767]

sir how to calculate I3

[@krzysztofbera7089]

it's current from current source- 2 A

[@RajeshKumar-ot4er]

I=5/4

[@rajeshverma9246]

sir ji please Z-transform finish kar dijiye...please

[@abdullahalrakibalif3420]

i1=14/11 ,kindly check

[@dipeshkumar4001]

I1 will be 14/11

[@shex9002]

And i2 12/11

[@techwithjoe8636]

you did the first mesh in the wrong direction... it should start with -2V + 2*I1 ...

[@nhitc6832]

He used the other sign convention. But it doesnt matter. If you take your equation (whatever you had) and multiply both sides by -1, you'll get the same equation as his

[@immanuelbasil806]

shouldn't i be 12/10 rather?

[@pavankata6099]

i2=12/13

[@naveensatyadurgatadicherla9877]

How I2= 12/11

[@shortzz220]

aaaaai 1 aaaaai 2 aaaaai 3 💩💩💩💩

[@kavithav9656]

This sum was not correct.

[@rajdeep2105]

Thanks Sir