Supermesh Analysis Explained

This tutorial introduces and explains supermesh analysis for circuits. You must use supermesh analysis if you are trying to solve a problem with mesh analysis, but there is a current source between two loops (meshes). By following supermesh analysis, you’ll get an equal amount of equations to the number of unknowns that you have, and then you just plug and chug, as you have been trained to do, young padawan.
This video is part of a full free course on electric circuits. The course covers DC circuits, circuit laws, current & voltage sources, series & parallel resistors, nodal analysis, mesh analysis, and AC circuits.
Links to the course are here:
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Thanks for watching, I hope it helps!

[@Engineer4Free]

Scroll up and hit that 👍 button if you found this video helpful!
The full Circuits playlist is here: th-cam.com/play/PLOAuB8dR35ocf9Typ1iX9NRmX0V04UYfQ.html

[@michaelvangaasbeek6942]

It is the night before my exam at 3 in the morning and this video just got it all to click. Thank you and subscribed🙏

[@sjchxhtriskit3025]

2:19am but close enough lmao, hes so good

[@r7calvin]

How did you do?

[@hashirahmed6621]

lmaooo its 1 am rn and my mid semster exam is tomorrow too

[@Engineer4Free]

FULL POWER 😴⚡⚡

[@darshanvlogs3294]

Its 12 am and Even my mid sem exam is there today

[@asl1117]

explanation so good might salvage my academic comeback

[@masterkitcen.]

How'd it go?

[@azenginerd9498]

@5:54 shouldn't your Ib current have been written as 1.167A instead of 0.167A?
I enjoy your videos as a great basics refresher for things I haven't done since in school... which was quite a while ago.

[@HardwareNinja]

Hi Enginerd (loved the name!),
If you're interested in electrical/electronics engineering, we're building a channel to help students and professionals prepare for job interviews with real world questions. We'd love it if you could swing by.

[@mz2neat411]

i think he made a mistake but the idea is syill the same

[@SonTran-qc1pe]

yep The Ib must be 1.167A cuz of the KCL

[@LurkersCrib]

lot's of respect for the perfect explaintion

[@twilight7138]

Man's a legend 🙏🏻🙏🏻

[@lukendorf511]

Great explanation, thank you!

[@fredyguevara3304]

Thank you very kindly for your wonderful help!!!

[@HardwareNinja]

Hi Fredy,
If you're interested in electrical/electronics engineering, we're building a channel to help students and professionals prepare for job interviews with real world questions. We'd love it if you could swing by.

[@thecosmos7671]

Thank you,Sir 🌟

[@HardwareNinja]

Hi,
If you're interested in electrical/electronics engineering, we're building a channel to help students and professionals prepare for job interviews with real world questions. We'd love it if you could swing by.

[@shazimzafar923]

Ib = 1.167A. typo mistake in the end.

[@thomasblacker129]

Very helpful, Thank you

[@محمدباقرمؤيد-103]

Thank you.
y the best 👏

[@dominator1333]

Thanks broski

[@vbacz]

What if u have a voltage source in the middle do u just add it like normal

[@Kdiggity_Xx]

Why are you doing the negative and positive signs backwards? Everyone else I’ve seen do this has them the other way. Don’t you make the value negative or positive based on the sign that is on the side that the current leaves from? Just a lil confused.

[@tamayohannahmariela.575]

(2)

[@safwanshahriar4108]

It's his personal choice.

[@SeanStone-r9t]

what if there is a resistor value in the middle branch?

[@eejaaspk]

Instead of the current source? ( I presume that is what you mean ) then in this case it would only be a regular mesh analysis. You would have R*(i1-i2) for mesh 1 and R*(i2-i1) for mesh 2

[@lance4377]

​@jad8799 No, what if its BOTH current source in series with a resistor

[@sunnylau175]

Why is Ib 0.167A rather than 1.167A?

[@bulutbekdemir]

actually it is, he just done a mistake

[@benfuller3844]

Goat

[@TirthaRoyChowdhury-y3j]

your voice feels very asmr-ish please add bass

[@muhamadameen5690]

👍👍👍

[@Engineer4Free]

👌👌👌

[@yafesenessahiner4782]

great

[@danokennethedrianp.3658]

If there are three loops, and the current source is in between of two loops... Can you still use this method?

[@osheonamejere7342]

Yes

[@abdullrahman8027]

how the hell is it -2+4… the signs should be the opposite

[@GLOIREPUNGU]

i'm also confused

[@gpl3046]

Because he is using a convention inverse to yours its doesnt change anything because he puts the inverse signs to everything your convention would have been and so the signs cancels and you get the same answer eitherway

[@samueloliver7080]

Current entering voltage + terminal is + and current leaving voltage + terminal is -

[@240mains]

why re-draw Ib in red ?
100 % un-necessary.
and why not re-draw
the Green polarity as - +
across the 2 ohm resistor
to pretend the voltage is
+pos across the 2 ohm resistor ?
completely un-necessary
and
adds clutter to the diagram

[@arnavverma2461]

Well okay but you could be less rude , he's helping us during our exams

[@eren_yeager9927]

shut up