Deriving the SUVAT Equations of Motion - A Level Physics
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- เผยแพร่เมื่อ 9 เม.ย. 2015
- This video explains deriving the equations of motion (SUVAT equations) for A Level Physics.
You know the equations of motion, but where do they come from? This video shows how to derive the suvat equations using a simple velocity-time graph. Remember the gradient is equal to the acceleration and the area is equal to the displacement.
Thanks for watching,
Lewis
This video is recommended for anyone studying A Level Physics in the following exam boards:
AQA
CIE
Edexcel
Edexcel IAL
Eduqas
IB
OCR A
OCR B
WJEC
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Is nobody going to mention the ridiculously perfect line he drew?
Samuel Barnes Skills
Big thank you from a student who is weak at maths (who is doing physics)
Beautiful video that just gave me a really nice grip on those equations; I REALLY REALLY want to thank you very much for this!
+Mohamed Khaled Thanks
+A Level Physics Online Is it okay to say s=∫vdt? Also, in an exam would calculus methods gain full credit?
Compared to A Level Maths the work you do in Physics is quite straight forward and anybody marking your work should understand the calculus you use.
Not a physics student, but this really helped for my A level mechanics. Thanks!
0:22 that line was utterly _perfect._ I am seriously impressed.
Brilliant video, it should be in every A level Physics class when they teach SUVAT equations.
Best video on the SUVAT equations hands down. Short and insightful!
studying a level as a self study course and this video is a total lifesaver
That line went up better than my grades
Very helpful video! Clear and to the point.
thanks a lot!!! love the way you explained it.
youre a legend
thanks helped me a lot!
Brilliant explanation
wow great explanation 🙌🙌
This is perfect for my exam in a month
thank you i understand how to use them now
You're awesome.
Thankyouu so much!
bro might be the only reason I understand physics
U r legend
Thanks helped a lot
np habibi
dude my teacher is bad, she's been teaching this for the past 2 weeks and i didnt understand anything, and you taught me everything in 5 minutes..
Hey!
I searched up an explanation for these equations and came upon this one, in my book the second equation is “ S= ut + 1/2at^2 “
Can you please explain this to me ?
This considers a situation of an object moving in a straight line, with the origin defined at the initial position. The object can move in either direction on this line, and is assumed to an infinite length of runway available to it, in both directions. One direction, we assign as positive, and the opposite direction, we assign as negative. It is convention to assign east/north/right/up as positive, and west/south/left/down as negative, but you can assign it any way you want as long as you are consistent.
S stands for displacement. Since d has another full time job in calculus, we opt to call this s, for the second consonant in the word displacement. I recommend writing a cursive s, so you don't confuse it with a 5. You may also see this called x, y, or z, depending on the context of the problem.
u, the alphabet neighbor of v, stands for initial velocity. Some people opt to keep the v, and use subscripts to tell them apart. Others use u and v for initial and final velocity respectively, so they don't need subscripts.
a is acceleration, the rate of change in velocity
t is time elapsed since the object was at position s=0 and velocity = u.
This comes from drawing a graph of velocity as a function of time for constant acceleration. It will look like a trapezoid with base t, height on the left u, height on the right v (v = u+a*t), and slope a. The area of the trapezoid is the area of the rectangle of base t and height u, which is u*t, plus the area of the triangle of height a*t and base t, which is thus 1/2*a*t^2. Put it together, and get s=u*t+1/2*a*t^2.
Do you work for Uplearn??
No, but they are using my videos for their Physics course.
@@PhysicsOnline ohhh
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could u send all u note to us？
Are you allowed to derive them via calculus?
Why you divide it by 2 in second equation
The total displacement is the area under the curve, the shape he has drawn is a trapezium. The formula used to calculate the area of a trapezium is 1/2(a+b)h if you were to sub in the values u v and t you would get 1/2(u+v)t.
sorry but this doesn't explain anything at all! Why bother deriving equations when you expect the viewer just to assume that S = the area under the curve without any explanation whatsoever?
You're just dumb!
Assuming you know the formula average velocity = displacement / time, you can rearrange to: displacement = average velocity * time. What he does is create a rectangle with average velocity as the height and time as the base. Since the formula for the area of a rectangle matches the formula for displacement, finding the area of a rectangle gives the displacement.