3 x 3 eigenvalues and eigenvectors
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- เผยแพร่เมื่อ 25 ก.ค. 2024
- In this video, I showed how to find eigenvalues and eigenvectors of a 3x3 matrix
Watch detailed explanation of eigenvectors here
• Eigenvalues and Eigenv...
The other eigenvectors are:
for lambda = 2, [ 2 1 0 ]
for lambda = 3, [ 1 2 1 ]
where have you been all my life ?
That’s what I’m saying
You have got way too much style to be this good of a math teacher
It has been so long since I have taken, or even used, most of the math in your videos, but I watch them every time you post one. Thank you for giving me exercises to keep my brain in shape!
Ul
this has to be the most helpful video for this subject, thank you so much
by far the most easy to understand explanation of this subject.. thank you.
i appreciate the way of explaining , thanks 🙏
Love this man.
Love the Explanation !! very clear
I really appreciate your explanation and your videos 🖤🌠
Thankyou sir ,great explanation cleared all my doubt.
Great video, so helpful!
finally, perfect teacher
Lovely video!!! Thank you brother!!
Prime Newtons makes this topic clear as a bell! 😊
Absolutely amazing
Thank you soo much. You solved my problem
evaluate the integral of I = ∫[1,0] (x + y) dx from point A(0,1) to point B(0,-1) along the semicircle y = √(1-x²),
nice presentation thank you
Exact same question i saw in my past questions 😮
Hello Sir...
How do you factorize???😢
what shall we do when we plug in one of the eigen values then one of the column of the chxcs polynomial becomes zero?
thank you for your help.
Nice example
I like your video a lot
You're the man
You are great thanks guys so much 10Q a lot
Thanks Sir 🙏
Good video thank you
In some sources, we need to convert it to echelon form after lambda placement. What is the difference?
Thanks !!
Keep it up bro
Excellent
Love ur smile sir❤
please more linear algebra
I love you man. I owe you my degree
Legend
Why do you not use calculater to find eigenvalues
Maybe case when we dont have full set of eigenvectors
If |P|=1 and D=diagonal matrix and A=(invP)DP then we can construct as many square matrix as we want whose eigen values all integers
Not the best video to post on but would you consider doing a lecture series on differential equations more to the tune of how a class would look?
I am planning long classroom-videos but not now. I need to get some things out of the way first. I promise, many series are in the making.
@@PrimeNewtons I look forward to it!
Does it matter which order we put the eigenvalues? For example if we did λ1 = 3, λ2 =2 , λ3 =1? I know how to answer this but my lecturer always has a different order of eigen values, which also changes the order of the eigen vectors
Did you figure out if the order matters or not, I'm also stuck on the same issue. Cause if we change the order of eigenvalues, i think we get different eigenvectors as well
@@sarasaleem7420 yes the order matters when you are checking for diagonalization
Thanks prime newtons
Like the new profile picture very much
i need some help, for lamda=2 i got [1 2 0] all of x are in term of x1, my ans isnt same as sir, if lamda=2 , in term of x2 i will get[ 2 1 0] which will be same as sir. does that mean for every diff Vector i can choose diff x to be in term of? or for example i choose x1,x2,x3 to be in term of x1 for lamda=1, lamda=2and lamda=3, all x have to in term of x1, sir did mention at the end of the video but just wanna double confirm which is the right one
or i calculate wrongly, not sure
I dont often coment but great video
I appreciate the comment
thats why hIs the GOAT!
❤❤❤😊
12:27
Yeah I got a big fat F in linear algebra. I started trying to reduce this to reduced row echelon form.
Now you know
man the past 2 year i was doing it by GUASSIAN ELIMINATION.
Never stop learning
Those who stop learning stop living
You cooked
Yes 😂
How could it be like that? When we make the first determinant of lambda 2, X3 = 0, then we put 2(X2) instead of X1, and how come the vector [2 1 0] is obtained when lambda = 2? I don't understand, is there anyone who can explain it to me?
A (matrix) * [2 1 0] (Eigvector lambda2) = [4 2 0] = 2 (Eigval lambda2) * [2 1 0]
A (matrix) * [1 2 1] (Eigvector lambda3) = [3 6 3] = 3 (Eigval lambda3) * [1 2 1]
A is a matrix (an operator) that works on a vector to become a VALUE times that vector. That's the way to do a measurement in quantum mechanics.