Just came across your video, this is the first math video i've found on youtube that really helped me understand what I was learning! You are a great teacher thank you so much for your help and enthusiasm :)
Got this video in recommendation had a playback of first 30 seconds without clicking the video the great introduction made me open this in my other tab. Now I'm going To stalk your whole channel for Linear Algebra content 🤣
If you had to calculate 2^100 and 3^100 without a calculator, you would probably do exponentiation by squaring. That takes advantage of this exponentiation property: (a^b)^c = a^(bc). So by repeated squaring of your last result, you can compute 2^2 then 2^4 then 2^8 then 2^16 then 2^32 then 2^64. Once you have those, then you can do this operation to get 2^100: 2^64*2^32*2^4. That means that you can calculate 2^100 by multiplying 8 times! The first multiplication would be 2*2=2^2. The second would be 2^2*2^2 = 2^4. The third would be 2^4*2^4=2^8. The fourth would be 2^8*2^8=2^16. The fifth would be 2^16*2^16 = 2^32. The sixth would be 2^32*2^32=2^64. The seventh would be 2^64*2^32=2^96. The eighth and final would be 2^96*2^4=2^100.
This channel is a gem! Great video quality, great lecture, great teacher with a great sense of fashion! One question though, shouldn't the inverse of the matrix be (1/det)[ d -b over -c a]?
To raise anything to the 100th power, we multiply it by itself not 100 times, but 99 times. To square it, we multiply it by itself once. To cube it, we multiply it by itself twice... etc.
So for any nxn matrix there are n! sets, of numbers, of cardinality n^2, that lead to its diagonalisation. I didn't know that before :-) (just messing ... good video)
I was taught that for these kind of questions First do A², ³, ⁴... until you see a pattern in these Analyse that pattern and then put for the exponent asked And it works, atleast the questions I solved were right
when I think of maths, I think of a gentle man like him teaching. you really are the best
"Do not confuse yourself"
Great advice! 🙂👍
rapidly becoming one of my favorites chanels on youtube, thanks a lot for the great videos.
ive never watched such a relaxing math tutorial
Glad you liked it!
thank you for actually explaining every step, unlike my teachers
you are the mentor figure every aspiring young man need in their life. Love your enthusiasm and energy !
Just came across your video, this is the first math video i've found on youtube that really helped me understand what I was learning! You are a great teacher thank you so much for your help and enthusiasm :)
You are the best one on explaining a topic from what I have found. Thank you!
easily the best channel to learn certain math topics!
I went from failing linear algebra to getting 80s on my exams thanks to your videos... Thank you so much
i watced all videos in the palylist , have learned too much. Thanks
Glad to hear that
Thanks, Great teaching!!
Most informative TH-cam video ever!
This guy needs more popularity truly underrated
you actually make me smile even though linear algebra is my least favorite course. thank you a lot
This guy is a gem !!
You are amazing. Greetings from Sweden.
Got this video in recommendation had a playback of first 30 seconds without clicking the video the great introduction made me open this in my other tab. Now I'm going To stalk your whole channel for Linear Algebra content 🤣
I love your videos.
If you had to calculate 2^100 and 3^100 without a calculator, you would probably do exponentiation by squaring. That takes advantage of this exponentiation property: (a^b)^c = a^(bc). So by repeated squaring of your last result, you can compute 2^2 then 2^4 then 2^8 then 2^16 then 2^32 then 2^64. Once you have those, then you can do this operation to get 2^100: 2^64*2^32*2^4. That means that you can calculate 2^100 by multiplying 8 times! The first multiplication would be 2*2=2^2. The second would be 2^2*2^2 = 2^4. The third would be 2^4*2^4=2^8. The fourth would be 2^8*2^8=2^16. The fifth would be 2^16*2^16 = 2^32. The sixth would be 2^32*2^32=2^64. The seventh would be 2^64*2^32=2^96. The eighth and final would be 2^96*2^4=2^100.
Thanks
You’re a happy person.
This was SO SO helpful. Thank you!!!!
{{1,-1},{2,4}}^100={{2^101-3^100,2^100-3^100},{-2^101+2*3^100,-2^100+2*3^100}} It’s in my head.
This channel is a gem! Great video quality, great lecture, great teacher with a great sense of fashion! One question though, shouldn't the inverse of the matrix be (1/det)[ d -b over -c a]?
Didn't know kamaru usman was that good at matrices
I was thinking that I saw him somewhere else too
😂😂😂😂
To raise anything to the 100th power, we multiply it by itself not 100 times, but 99 times.
To square it, we multiply it by itself once.
To cube it, we multiply it by itself twice... etc.
very nice. Thanks a lot 🙏 Timely eg as I am learning this now.
Just perfect ❤
You are really best man
So for any nxn matrix there are n! sets, of numbers, of cardinality n^2, that lead to its diagonalisation. I didn't know that before :-) (just messing ... good video)
ty very much man!
Incroyable
I am now happy!
@ 0:07 Great bit of theatre! LOL
What a king
At this time 5:52 I thought you were digressing about pdiddy. I confused myself.
Than you so much
Thank You
❤❤❤
I was taught that for these kind of questions
First do A², ³, ⁴... until you see a pattern in these
Analyse that pattern and then put for the exponent asked
And it works, atleast the questions I solved were right
Smart!
@@PrimeNewtons yes Imagine without knowing this the question comes for a 3x3 Matrix to the power of 2023 (that was one question a remember)
never stop learning cze when you stop learning stop living clear mssg'''
Even without diagonalization you would only need to perform ceil(log2(100)) = 7 matrix multiplications.
We learn diagonalization but not aware of this type of application...
what about the power of 3 * 3 matrix?
Same process. Just longer
@PrimeNewtons by finding eigenvalues and applying that asked power would be correct?
Yes
Just to make sure, you did the inverse P wrong or not because you didn’t take into consideration the sign of the cofactors
Correct
thankyou sir
im pretty sure the eigenvalues of this matrix are 3 and 2 and not 1 and 2
💜💜
2^100 be casually having 30 digits lol
smile😁
🎉
You are handsome 😂
nigerians can relate