can i just take a minute to say how much ur amazing? cuz yeah my beloved teacher did not tell us ANY of this and had it not been for u, guess who would have failed yet another chemistry quiz?
thank you. I understand if the differences are same it would confirm the order. However, plotting the graph and finding the R^2 value compares directly and whichever is closer to one shows that it is that order. In this case, when I plotted the graph using your data, I get the R^2 value of 0.9999 for Time Vs ln[A], so it is First order.
Can't we just plot the [A], ln[A] or 1/[A] vs time to determine the order? If any of these plots yield a straight line, we can determine the order. Also, the negative of slope yields the rate constant. Correct me if I am wrong.
A= Aoe^-kt is the first order reaction. my question is it would be the same to say LnA = -kt +LnAo and thus since the slope is -k then half time might be found by 0.693/K?
Once you have found the order of the reaction, eg if its first order, there will be a specific formula you can use. For first order its ln ([A]/[A]o) = - kt. therefore if you plot ln conc on the y and time on the x axis, you get -k for the gradient of the straight line on the graph.
Basically you calculated everything to plot a graph then what is the point of trick..... You plot the graph or calculate difference whichever gives constant difference is the linear graph, which is the funda of linear graph
Im having problems crunching my numbers. My data is given into in mols, and I get each value into Molarity and I'm using those numbers. However when I'm doing it for ln[A] all of my values are negative????
Dennis Chiu Thanks Dennis, my values for for ln[A] are going up and down up and down, so does that mean I can omit the first order since the values aren't going downwards (-k)? Sorry if my terminology isn't making any sense.
Jereme leBourgeois Check your values for [A]. As [A] decreases over time (and it should do so during a chemical reaction), ln[A] should decrease as well. If your values for ln[A] are fluctuating as you say, that probably means the original values for [A] are incorrect.
this doesnt make any sense , the ln[A] decreases at about the same rate as [A] , nothing stays ''about the same''' , how do we find what order the reaction is scientifically? (i.e with maths)
The overall order is the sum of the order of each reactant so just say A was first order and B was second order, you add 1 and 2 together and it's third order. I think this is correct anyway
Your inputs on the calculator are hilarious. Thanks for the laugh while studying :)
Yeah 😂😂😂
Was just thinking that 🤣
I actually freaked out😂😂😂
@@epicmoments1964 HE BASHED IN RANDOM SHIT
Love the way he uses the calc! It's on fire. 😂 The video was really helpful. Thanks!
Might be good to note that the difference in time should also remain constant when calculating differences in concentrations.
can i just take a minute to say how much ur amazing? cuz yeah my beloved teacher did not tell us ANY of this and had it not been for u, guess who would have failed yet another chemistry quiz?
let me just take the lawn of 5
How do you use the calculator like that, make a tutorial on that please.
your calculator typing skills are out of this world
MAKES SO MUCH SENSE. God Bless you.
lol why is he tapping random buttons, we get that you are calculating something
thank you. I understand if the differences are same it would confirm the order. However, plotting the graph and finding the R^2 value compares directly and whichever is closer to one shows that it is that order. In this case, when I plotted the graph using your data, I get the R^2 value of 0.9999 for Time Vs ln[A], so it is First order.
lol! you are the only person i know who can actually make me crack up while doing chemistry...unnnbelieve able!
Took all day trying to understand this thank you sir🎉
My pre-lab makes sense now. Thank you, thank you, thank you!
fam really? LAWN?
thanks for the video though
That's what it's really called!
I YAWN instead
LMFAOOOOO when he hits random buttons instead of just saying he already calculated them
Can't we just plot the [A], ln[A] or 1/[A] vs time to determine the order? If any of these plots yield a straight line, we can determine the order. Also, the negative of slope yields the rate constant.
Correct me if I am wrong.
yes, you can and I prefer that too. thank you for adding your points to the comments.
You saved the day bro. Many gratitude !!!
thank you for being the professor that mine could never be
Do you use the same method of you are given Pressure instead of Concentration?
what if the time intervals arent constant?
Great tips by the way :)
Awesome video, it was very helpful and saved me time on my first Pchem exam!
It took me forever to find this thank you
what if none of the 3 work out?
Third order
yeah i was actually stuck with a problem whose answer key is 1.5 order. This clip is amazing but still doesn't cover that.
Now, this is how u explain a topic! Thanks! It helps a lot :D
Thank you so much for this vid, it helped me a lot!!
This vedio is titled how to solve your homework in 5 minutes.
Super thanks
So nice of you
This was a very helpful video, thank you!
A= Aoe^-kt is the first order reaction. my question is it would be the same to say
LnA = -kt +LnAo and thus since the slope is -k then half time might be found by
0.693/K?
How do you determine the rate constant after your calculations?
Once you have found the order of the reaction, eg if its first order, there will be a specific formula you can use. For first order its ln ([A]/[A]o) = - kt. therefore if you plot ln conc on the y and time on the x axis, you get -k for the gradient of the straight line on the graph.
Thank You! :)
Mohammad Sukkar no problem. Message me if you have any more questions
Will do!
Basically you calculated everything to plot a graph then what is the point of trick..... You plot the graph or calculate difference whichever gives constant difference is the linear graph, which is the funda of linear graph
this is straight up calculator abuse lmao thanks for the quick info and good laugh!
Does this apply to [B] as well?
Wow thanks man you are super skilled
So what happens if none of the first differences are linear?????
Emmanuel Makume choose best fit or redo experiment
hey thanks for this video....really helped me to understand some concepts :)
Taught me better than my college professor
but when time intervalls are not steady?
rainman doing calculations in his mind
So helpful! Thank you!
excellent calculator work! skillful..
i wish i could give you 1000 more likes, thanks a bunch !!! :D
thanks aloooot man u r awesome
. soo helpful
What if your time is not going by 20 seconds? The time given to me is not constant, damn this problem really wants me to graph it doesn't it :/
How to calculate for 3rd order reaction?
what does approximately constant mean what is your definition of that
hahaha! so cool:) i love you man....thanks for the extremely clear presentation and explanation!
Why in the world my professor did not tell me this tip? Ugh... thank you so much kind sir
i legitimately thought he was really doing the calculations that fast guys
Best video🎥
You are so good thank you so much
damn how do you calculate like that breh, strong fingers
Thank you very much for this straight forward explanation..... :)
Im having problems crunching my numbers. My data is given into in mols, and I get each value into Molarity and I'm using those numbers. However when I'm doing it for ln[A] all of my values are negative????
ln[A] will come out negative if [A] is between 0 and 1. I think the technique shown in the video should still apply for negative ln[A] values as well.
Dennis Chiu Thanks Dennis, my values for for ln[A] are going up and down up and down, so does that mean I can omit the first order since the values aren't going downwards (-k)? Sorry if my terminology isn't making any sense.
Jereme leBourgeois Check your values for [A]. As [A] decreases over time (and it should do so during a chemical reaction), ln[A] should decrease as well. If your values for ln[A] are fluctuating as you say, that probably means the original values for [A] are incorrect.
That dude got a mean trigger finger
best explanation
how will you know if it has 3 or more order of reactions
Very Helpful indeed **Thanks a lot
lol. I had no clue what you were talking about until half way in the video.
How to graph method sir this calculation
hahahahaha you're great! love your inputs on the calc so funny
that means ,in calculation time doesn't take part??
nice one bro!😄😄😄😄😄
Thank you so much
but how do you get the k from that?
Thank you so much!!
this doesnt make any sense , the ln[A] decreases at about the same rate as [A] , nothing stays ''about the same''' , how do we find what order the reaction is scientifically? (i.e with maths)
thanks teacher god keep u
very interesting
Are you Canadian?
"Turns Ouuut to be..... "
vervy very very very very very very well!!
You know how to use a calculator so well that it doesn't make sense to untrained eyes.
Could you show how to do it the proper way?
Thank you!!
not me using my own calculator to check the values cause he punched in the values waaayyyy to fast lol
The problem is calculator is not allowed in entrance exams.
You have to graph it
thank you
3rd order??
how do you do for 3 order
It only goes up to 2
I'd assume that if none of these fit then it is the third order
REALLY?!?! I don't think anyone else noticed that!
jefbord: I think you have to graph them.
Ok so really people that others were fools 9 years ago!?
what if you have more than 1 product :/
The overall order is the sum of the order of each reactant so just say A was first order and B was second order, you add 1 and 2 together and it's third order. I think this is correct anyway
Wow this was bam😂😊
The lawn? You mean natural log? Lol
You seemed to be much fast😂
thanks :)
বিদেশী......পাগল 💂💂💂💂💂💂💂💂💂👲👲👲👲👲👲👲👲👲👲👲👲👲👲👲👲👲👲👲👲👲
Okay but why does he pretend to press the calculator?💀
love this! haha
cool man,
Your difference explanation isn't clear...
Am I the only one getting Harlem shake and Kpop?
jizuz you saved my ass bro
اعجبني
whoops not product i meant to say reactants
noy good very tedious snd time taking. m an mbbs aspirant from india we r not allowed any calculator there...
ahaahhahaha amazing
thank you!
thanks teacher god keep u