you have literally just helped me understand and complete my chemistry coursework the night before it is due. you have saved my life (and my grade) thanks!
this guy is so helpful and i dont know why u complain guys if u didn't like it just leave he is using his precious time to make videos for FREE for students like us be grateful please lets see if u can do any better His videos are so helpful
You are a literal saint. This was so confusing but after much searching this is the first video I have found to explain this well enough for me to be able to progress, thank you for uploading this.
I've been struggling with this for a couple weeks now...and thought i would NEVER *get* it. But after just 4.5 minutes on TH-cam; i've got it! WHAT DID COLLEGE STUDENTS DO BEFORE TH-cam?!
thanks! you are way better then my prof! teaches way to fast and went to his office hours for help and he would give me less then 5 word explanation. Being bad at chem I need a more in depth and slow teaching method like the prof I had last semester he was VERY helpful I could have gotten a B- or maybe a B if I didn't mess up the last test and the first test I got a 56 on! I hope I get him next semester because I don't think I will be coming close to passing this class.
Thanks so much for the easy explanation with great presentation of how to solve the rate constant. Appreciate the effort you put into all your videos so keep up the good work!
in my chemistry lesson today we were making ethanal from ethanol and to make it you have to use a highly corrosive acid, which is an exothermic reaction and so it heats up. As a result we had to keep it in ice so it didn't get to hot and once the reaction is complete we had to seal it with a bung for which were supposed to use later. Unfortunately the group next to me forgot the cooling process and so sealed it while it was still reacting causing the pressure to build.
the beginning threw me off, so you did the crunching and then how did you determine which is what rate over? I tried rewatching a couple times & still haven't seen anything that shows it
How do you find the concentration of the reactant? Because I want to design an experiment to find rate constant, but I don't know how to measure concentration of the reactant as the experiment goes along. Help here?
You don’t mention the units of the rate constants. It varies For zero-order it is: mol per liter per second ( mol/L.s) For first-order it is: per second (1/s) For second or more-order it is: liter per mol per second (L/mol.s)
A lot of people pronounce the individual letters instead: "ell en". Probably a regional thing. But his way kind of makes sense when I think about what ln stands for.
haha thought I misheard him at the start of the vid til I read the comments, to undo exp, you have to mow the lawn. He isn't shy about it either he really leans into that lAWWWn.
READ BOTTOM BEFORE THIS ONE As a result the acid went everywhere, and the person who was holding the glass container had conc sulphuric acid all over his face and it destroyed his shirt
you have literally just helped me understand and complete my chemistry coursework the night before it is due. you have saved my life (and my grade) thanks!
this guy is so helpful and i dont know why u complain guys if u didn't like it just leave he is using his precious time to make videos for FREE for students like us be grateful please lets see if u can do any better His videos are so helpful
"There's no exponent there, that was me being uh...a loser" hahahah
You are a literal saint. This was so confusing but after much searching this is the first video I have found to explain this well enough for me to be able to progress, thank you for uploading this.
"little math trick here.... ACCEPT IT." Hahahaha! This guy's awesome
Only place i could find and explanation of this, thank you man earned my subscription.
You don’t even know how much I needed this holy Christ thank you
This is the best thing I've seen on you tube today.
thank you. It helps me a lot for my physical chemistry midterm test tomorrow! :) God bless you.
natural log = lawn
lawn = law of nature
🤭
this was mad beneficial in a major time-considerate way.
That form of the integrated rate law is so much better than the one I learned in class for finding K! Thanks for writing it that way!
Thank you so, so much! I was stuck on a similar problem like this for almost an hour.
You're ALMOST right, except for 2nd order.
second order: L/mol.s
third order: L^2/mol^2.s
fourth order: L^3/mol^3.s
and the powers keep increasing...
this man is heaven-sent.
I've been struggling with this for a couple weeks now...and thought i would NEVER *get* it. But after just 4.5 minutes on TH-cam; i've got it! WHAT DID COLLEGE STUDENTS DO BEFORE TH-cam?!
i wish you were my teacher, thank you so much
Thank you so much....after so long time.am able to solve numericals on rate constant... thank you sir
you just saved my chem grade. THANK YOU!
Great video. Very clear and easily understandable steps. Thanks
thanks! you are way better then my prof! teaches way to fast and went to his office hours for help and he would give me less then 5 word explanation. Being bad at chem I need a more in depth and slow teaching method like the prof I had last semester he was VERY helpful I could have gotten a B- or maybe a B if I didn't mess up the last test and the first test I got a 56 on! I hope I get him next semester because I don't think I will be coming close to passing this class.
Duuuude finally! This is the only video that will help me!
Thanks so much for the easy explanation with great presentation of how to solve the rate constant. Appreciate the effort you put into all your videos so keep up the good work!
omgz, you are the man! i cant believed i learned this from a youtube video!!!! GREAT!!!
Thank you so much! You were so helpful~! And entertaining lol.
You're not a loser :33
Read in Reddit that dudes of Canada call it lawn. They've picked it up from high school. But we Indians too are taught like that.
Very helpful. The video provided the exact information i needed.
perfect! i'm learning this in ap chem right now :) thanks!
Wow, I love your videos. They really help me. I just want to ask how do I finde the average rate constant?
This helps a bunch! Thanks so much :D
Thanks for these videos, you're really great at explaining chemistry!
in my chemistry lesson today we were making ethanal from ethanol and to make it you have to use a highly corrosive acid, which is an exothermic reaction and so it heats up. As a result we had to keep it in ice so it didn't get to hot and once the reaction is complete we had to seal it with a bung for which were supposed to use later. Unfortunately the group next to me forgot the cooling process and so sealed it while it was still reacting causing the pressure to build.
0:32 how do you know it is first order reaction
Getting this printed on a shirt immediately
"its a math trick.. ACCEPT IT!"
very informative , it solved my problem , thank you
you are the best craic ever, fair play
Thanks a lot! This has been very helpful. :)
this helps a lot however is there another video after this one to continue this lesson
Chemist Nate you are the sickest
funniest chem video I've seen
This was super useful!
Great video! Thanks for the help!
"Little Math trick there; ACCEPT IT!"
great job. Lots of help
You are a saint
What if it's a second order? How would you figure out the rate constant?
can we use this formula or method for irreversible 1st orde rexn
Wow, thanks for posting! This really helped!
Thank you so much this really helped me!
hahahaha "that was me being a LOSER"
I rarely laugh out loud watching videos, but that was awesome hahahah
To get t, do we subtract the final time with the initial? Or is it just the final time?
Really helpful! Thank you so much :)
Omg saved my life thx for this
How do you find the rate constant if the reactions looks like
A+B+C---->D+C
Or does it even mater how many reactants we have?
How would you do this problem if you were asked to find the concentration of a time that was not on the table for example 90 seconds?
the beginning threw me off, so you did the crunching and then how did you determine which is what rate over? I tried rewatching a couple times & still haven't seen anything that shows it
Logs and Lawns. A perfect match.
WHERE ARE YOUR UNITS FOR K????????? ILL GIVE YOU 60/100 FOR THIS
THE TRUTH for a first order reaction, the units are per second (/s). The units also cancel out if you plug them in, and you're left with (/s).
14bdl I took that course last semester. Back then I didn't know that
THE TRUTH I’m about dumb as crap and this is making sense now.
Man I love you!!!
lawn? never heard of that before
How do you find the constant if it were zero order ?
I love this guy lol
what about finding the rate constant for a second order?
1/[A] - 1/[Ao] = kt
you are the man!
Do the units of the rate constant or the time matter?
super helpful! Thx！
great video. thank you
How do you find the concentration of the reactant? Because I want to design an experiment to find rate constant, but I don't know how to measure concentration of the reactant as the experiment goes along. Help here?
tq! it's really helpful :)
helpful video, thank you!
Beautiful. Thanks.
Super video!!!!! :D
You don’t mention the units of the rate constants. It varies
For zero-order it is: mol per liter per second ( mol/L.s)
For first-order it is: per second (1/s)
For second or more-order it is: liter per mol per second (L/mol.s)
How to know the order tho using that concept?
THANK YOU SO MUCH! :D
the unit of rate constant,k is Lmol s then the order of reaction
awesomeeee i love it
you are amazing
omg this helps so much!
I assume the "LAAWN" is the same as a natural log??
how can u tell its first order?
What if you don't have the concentration? I was given the time and figured out the rate, but I have nothing else. I'm lost.
what if it just gives me an initial rate of mol.L^-1.s^-1
How to find rate of rxn at given temperature
You call a natural logarithm a "lon"???
+StrangeQuark100 At first, I heard it as 'lawn'.
+StrangeQuark100 That's the term for it. What would you call it?
A lot of people pronounce the individual letters instead: "ell en". Probably a regional thing. But his way kind of makes sense when I think about what ln stands for.
its log naturalis. so ell enn would make more sense than lawn :D
We pronounce it lin.😂😂 so funny how it's different for everyone 😂
haha thought I misheard him at the start of the vid til I read the comments, to undo exp, you have to mow the lawn. He isn't shy about it either he really leans into that lAWWWn.
pls add the unit of k as second inverse
You add all of the orders of each reactant together.
thank you :)
how u came to know that those are 1st law and 2nd law?
valid
Pearson ain't got nothing on me
This UNZA advert for ABSA😭
goat
I've literally never seen a more confusing video
"I lost my number."
nice rolex fam
That's just how most people pronounce ln, it's quicker to say than natural log.
I tried to do chemical kinetics but I kept getting distracted by the lawn.
READ BOTTOM BEFORE THIS ONE
As a result the acid went everywhere, and the person who was holding the glass container had conc sulphuric acid all over his face and it destroyed his shirt
Chemistry, for people who can't do calculus.