i miss teaching my students face to face, sir. btw thank you for this! i'll be teaching it tomorrow to my grade 12 students and it's quite tricky and confusing. so far it's only your tutorial that i understood clearly.
It is actually 0.693/-k right? For half live Since first order is ln(1/2)=-kt Therefore will be [Ln(1/2)]/-k instead of k only? But that's kinda weird as if -k we will get negative value for time. Is it just we simply ignore the minus sign ?
You can only use that equation for 1st order reactants. The zero order and 2nd order reactants have different integrated rate laws. Now 1st order is the most common example you'll come across and all radioactive decay is 1st order, but you will still come across zero and 2nd order reactants here and there. Hope this helps!
I love you wholeheartedly, explained in 15 mins what took me watching 2 hours worth of lectures couldn't to understand.
Thanks Shahrob! Exactly the feedback instructors love to hear! Happy Studying!🙂
Finding your channel and website was a god send! Here’s to a successful chemistry semester!
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I am from India and this is the first time got something from chemistry, thanks to you for visualize me the concept so clearly
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You sir are a legend...wish my chem teacher was you
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Sir ,your teaching method is too good .my all doubt are clear by watching your video
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Next level of teaching! Concepts are as clear as a crsytal now, Thnks Chad :)
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Thank you so much sir, keep making these chemistry videos there amazing. Saves so much time.
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Thank you! My professor just skipped right over this in lecture
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i miss teaching my students face to face, sir. btw thank you for this! i'll be teaching it tomorrow to my grade 12 students and it's quite tricky and confusing. so far it's only your tutorial that i understood clearly.
You are welcome, eli - have fun teaching the grade 12 students!
Perfect job 🤍
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Taking the exam on Monday, definitely not cramming my review
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I just love 💘your teaching metho
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imagine getting formulas on exam:(
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You are such a chad.
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Wow he's so good
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It is actually 0.693/-k right? For half live
Since first order is ln(1/2)=-kt
Therefore will be
[Ln(1/2)]/-k instead of k only? But that's kinda weird as if -k we will get negative value for time. Is it just we simply ignore the minus sign ?
Its a decay rate.
So it's how much of something is going DOWN or being LOST over time.
So can you use the equation ln([A]/[A]o)=-kt for all integrated rate laws or is it limited to some Integrated rate laws?
You can only use that equation for 1st order reactants. The zero order and 2nd order reactants have different integrated rate laws. Now 1st order is the most common example you'll come across and all radioactive decay is 1st order, but you will still come across zero and 2nd order reactants here and there. Hope this helps!
Hello.
Is there A general relation of the integrated velocity law for each order?
Chad is SWEET lol
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Dependacy
I wish he wa my teacher 😢😮😮
Thanks!