A comment I made elsewhere for readers' attention. This may solve the many difficulties Professor Eric Laithwaite and Sandy Kidd and others at Dundee University had, and recently a project on gyros made at Cambridge and Sydney University. The answer as to why the gyro performs what it does is due to the distributed masses within the gyro spinning wheel being subjected to the distributed three-dimensional accelerations existing in the voluminous cycloidal trajectory made by each mass particle spinning in the gyro. The whole integral of Integral of (mass ( x.y,x,t) reacting with acceleration (x,y,z,t)) contains all the miracles and elegance of the gyro which are summarised in the discussion shown below.
The gyro in the "floating " configuration, when placed at the end of an extension arm, DOES NOT LOSE ANY OF ITS WEIGHT, and that issue, is very misleading to many people, including many universities. I advise readers to proceed to read the manner in which it is being presented as it will not be found in any book or from no one else in this style, and readers, they are free to comment on how the four states within a gyro were explained. (The gravity balance) ...( The angular motion balance).... ( The gyro centrifugal forces).....( The reason why the gyro floats and moves forwards). This is presented so that any person interested in statics and dynamics can have a different perspective of the working of the gyro. Here are the details of what I think happens in a gyro. There are basically four states one needs to explain. I shall use what is seen in the video above showing a gyro appearing to be floating. To use these following videos for reference. th-cam.com/video/Pbb_RnxeYys/w-d-xo.html th-cam.com/video/xf1Nt3KLm-U/w-d-xo.html th-cam.com/video/jD_Q_J4GcQ8/w-d-xo.html 1. The vertical down weight of the gyro (mg) seems to be floating on air and how it is held up against gravity needs to be explained. 2. What forces the gyro uses to turn about itself with the dynamic precession (Wp and torque of I.Ws.Wp) needs to be explained. 3. Why the gyro, when not spinning but rotating as a pure mass m shows centrifugal force about its own center and about the pivot point and this later disappears when the gyro spins and precesses. 4. Why the mass m is basically forced to move slowly around the pivot point. One may consider this as a linear motion using a force Force = ma + air drag forces if Ra is larger large and then work it back into circular motion about the pivot point by knowing that a= (R arm)*d(Wp)/dt The above is achieved as follows. a. When a fast spinning gyro (Ws) is taken and allowed to move around a radial arm (Ra) with angular velocity (Wp), then the trajectory of one mass particle is a three-dimensional cycloidal curve containing different locations, different velocities, and different three-dimensional accelerations. Within the curves of this three-dimensional cycloid, there are ACCELERATIONS acting on the spinning and rolling mass particles which bring about two opposite acting centrifugal forces which vary their magnitudes, one acting inward on the upper horizontal half of the gyro, and the other acting outward on the horizontal lower half of the gyro. These two opposite acting centrifugal "horizontal" forces act at a slightly forward angle to the movement of the gyro, will create all the magic in the gyro as follows. Also, note that these two opposite acting forces also act on the forward vertical half of the gyro (the outbound force) while the ( inbound force) acts on the rear vertical half of the gyro. These centrifugal forces are basically horizontal in nature ( in this experimental configuration) and their horizontal and vertical separation between them and the slight tilting forward give all the requirement to make the gyro behaves as it does. This is how what was described above handles all there is to handle in a gyro as shown in the video. 1. The weight of the gyro (m.g) working in conjunction with the supporting arm operating as a pivot, and the extension rod (Ra) generates a gravity torque ( m.g.R arm) which tends to pull the weight down. This is opposed by the two opposite acting centrifugal forces being separated in a vertical manner by a distance x. This arrangement will give the following. The inbound force (Fin) is above the outbound (Fout) by a distance x and so these create a torque of about the axis of the gyro (F1+F1)*x = (mgR arm) and this is a balance in the gravitational state. 2. The flat face of the gyro spinning wheel at (Ws) with an inertial "I" is changing its orientation with respect to earth with angular velocity (Wp) as it circles around the pivot suspension point and this needs a torque = (I.Ws.Wp ) which is provided by the same two opposite centrifugal forces also separated by a horizontal distance x, acting on the front and back vertical halves of the gyro spinning wheel. Hence (F1+F2)*x) = (I.Ws.Wp) This means that the angular inertia characteristic of the gyro needs the torque action generated by the horizontal separated opposite acting centrifugal forces F1 and F2. This is the dynamic angular motion balance. Note the beauty of the relation between the ( Falling weight and torque ( m.g.Ra), and (the two opposite centrifugal forces, separated horizontally and vertically by distance x, and hence the torque ( F1+F2)*x) and needed by the gyro (I.Ws.Wp)).
vertical gravity balance = (m.g.R arm) = ( F1+F2)*x = horizontal angular torque (I.Ws.Wp)=( F1+F2)*x 3. Since the two opposite centrifugal forces are " almost parallel" with the gyro extension arm Ra, then conventional outbound Centrifugal force m.(Wp)(Wp)*R arm = (F1-F2) where F1 is the inbound centrifugal force which diminishes with the loss of spinning, of the gyro and so the normal outbound centrifugal force F2 takes over. Hence ( F1-F2)= m.(Wp)^2 (R arm) 4. The force that pulls the gyro forward may be looked upon as being a linear force and this is due to the slight tilt forward of both centrifugal forces which is (F1+F2)*sine (angle of forwarding tilt of the centrifugal forces) Hence this forward motion of the gyro may be looked upon as being Force= ma + drag force . This may be "adjusted" to fit the angular state as the linear acceleration is related to the (Wp) rotation of the gyro where a= d(Wp/dt) so (F1+F2)*sine( small forward tilt angle)= m.(R arm)d(Wp)/dt + Wp drag and other losses. If one watches other videos one sees gyros rising to the top by some unknown forces, and I do believe that this force may account for what one sees in other videos as shown in the following, The beauty of what was explained above means that at very high spinning speeds the reaction on the central pivot point is only the vertical weight of the gyro mg. th-cam.com/video/SEstkIF3U1Q/w-d-xo.html Apologies for the length of this explanation, but it needs to be commented upon by those who enjoy the magical and elegance of gyros. I preferred to look into the engineering details than describe the action with words as " the spinning gyro precesses when a torque is applied to it." It is fascinating what beauty and elegance exist hidden in silence and invisibility of physics which is never appreciated by many people. The above contribution should be followed by Universities in London, Dundee, Cambridge, Sydney, and others which in the past showed much interest in the working out and showing the performance of the gyros.
![HIWWHEE | OHM [Official MV]](http://i.ytimg.com/vi/OJJLtTLqLag/mqdefault.jpg)
A comment I made elsewhere for readers' attention.
This may solve the many difficulties Professor Eric Laithwaite and Sandy Kidd and others at Dundee University had, and recently a project on gyros made at Cambridge and Sydney University. The answer as to why the gyro performs what it does is due to the distributed masses within the gyro spinning wheel being subjected to the distributed three-dimensional accelerations existing in the voluminous cycloidal trajectory made by each mass particle spinning in the gyro. The whole integral of
Integral of (mass ( x.y,x,t) reacting with acceleration (x,y,z,t)) contains all the miracles and elegance of the gyro which are summarised in the discussion shown below.
The gyro in the "floating " configuration, when placed at the end of an extension arm, DOES NOT LOSE ANY OF ITS WEIGHT, and that issue, is very misleading to many people, including many universities. I advise readers to proceed to read the manner in which it is being presented as it will not be found in any book or from no one else in this style, and readers, they are free to comment on how the four states within a gyro were explained.
(The gravity balance) ...( The angular motion balance).... ( The gyro centrifugal forces).....( The reason why the gyro floats and moves forwards).
This is presented so that any person interested in statics and dynamics can have a different perspective of the working of the gyro.
Here are the details of what I think happens in a gyro. There are basically four states one needs to explain. I shall use what is seen in the video above showing a gyro appearing to be floating.
To use these following videos for reference.
th-cam.com/video/Pbb_RnxeYys/w-d-xo.html
th-cam.com/video/xf1Nt3KLm-U/w-d-xo.html
th-cam.com/video/jD_Q_J4GcQ8/w-d-xo.html
1. The vertical down weight of the gyro (mg) seems to be floating on air and how it is held up against gravity needs to be explained.
2. What forces the gyro uses to turn about itself with the dynamic precession (Wp and torque of I.Ws.Wp) needs to be explained.
3. Why the gyro, when not spinning but rotating as a pure mass m shows centrifugal force about its own center and about the pivot point and this later disappears when the gyro spins and precesses.
4. Why the mass m is basically forced to move slowly around the pivot point. One may consider this as a linear motion using a force Force = ma + air drag forces if Ra is larger large and then work it back into circular motion about the pivot point by knowing that a= (R arm)*d(Wp)/dt
The above is achieved as follows.
a. When a fast spinning gyro (Ws) is taken and allowed to move around a radial arm (Ra) with angular velocity (Wp), then the trajectory of one mass particle is a three-dimensional cycloidal curve containing different locations, different velocities, and different three-dimensional accelerations. Within the curves of this three-dimensional cycloid, there are ACCELERATIONS acting on the spinning and rolling mass particles which bring about two opposite acting centrifugal forces which vary their magnitudes, one acting inward on the upper horizontal half of the gyro, and the other acting outward on the horizontal lower half of the gyro. These two opposite acting centrifugal "horizontal" forces act at a slightly forward angle to the movement of the gyro, will create all the magic in the gyro as follows. Also, note that these two opposite acting forces also act on the forward vertical half of the gyro (the outbound force) while the ( inbound force) acts on the rear vertical half of the gyro. These centrifugal forces are basically horizontal in nature ( in this experimental configuration) and their horizontal and vertical separation between them and the slight tilting forward give all the requirement to make the gyro behaves as it does. This is how what was described above handles all there is to handle in a gyro as shown in the video.
1. The weight of the gyro (m.g) working in conjunction with the supporting arm operating as a pivot, and the extension rod (Ra) generates a gravity torque ( m.g.R arm) which tends to pull the weight down. This is opposed by the two opposite acting centrifugal forces being separated in a vertical manner by a distance x. This arrangement will give the following. The inbound force (Fin) is above the outbound (Fout) by a distance x and so these create a torque of about the axis of the gyro (F1+F1)*x = (mgR arm) and this is a balance in the gravitational state.
2. The flat face of the gyro spinning wheel at (Ws) with an inertial "I" is changing its orientation with respect to earth with angular velocity (Wp) as it circles around the pivot suspension point and this needs a torque = (I.Ws.Wp ) which is provided by the same two opposite centrifugal forces also separated by a horizontal distance x, acting on the front and back vertical halves of the gyro spinning wheel. Hence
(F1+F2)*x) = (I.Ws.Wp) This means that the angular inertia characteristic of the gyro needs the torque action generated by the horizontal separated opposite acting centrifugal forces F1 and F2. This is the dynamic angular motion balance.
Note the beauty of the relation between the ( Falling weight and torque ( m.g.Ra), and (the two opposite centrifugal forces, separated horizontally and vertically by distance x, and hence the torque ( F1+F2)*x) and needed by the gyro (I.Ws.Wp)).
vertical gravity balance = (m.g.R arm) = ( F1+F2)*x = horizontal angular torque (I.Ws.Wp)=( F1+F2)*x
3. Since the two opposite centrifugal forces are " almost parallel" with the gyro extension arm Ra, then conventional outbound Centrifugal force m.(Wp)(Wp)*R arm = (F1-F2) where F1 is the inbound centrifugal force which diminishes with the loss of spinning, of the gyro and so the normal outbound centrifugal force F2 takes over.
Hence ( F1-F2)= m.(Wp)^2 (R arm)
4. The force that pulls the gyro forward may be looked upon as being a linear force and this is due to the slight tilt forward of both centrifugal forces which is (F1+F2)*sine (angle of forwarding tilt of the centrifugal forces) Hence this forward motion of the gyro may be looked upon as being
Force= ma + drag force .
This may be "adjusted" to fit the angular state as the linear acceleration is related to the (Wp) rotation of the gyro where a= d(Wp/dt) so (F1+F2)*sine( small forward tilt angle)= m.(R arm)d(Wp)/dt + Wp drag and other losses.
If one watches other videos one sees gyros rising to the top by some unknown forces, and I do believe that this force may account for what one sees in other videos as shown in the following,
The beauty of what was explained above means that at very high spinning speeds the reaction on the central pivot point is only the vertical weight of the gyro mg.
th-cam.com/video/SEstkIF3U1Q/w-d-xo.html
Apologies for the length of this explanation, but it needs to be commented upon by those who enjoy the magical and elegance of gyros. I preferred to look into the engineering details than describe the action with words as " the spinning gyro precesses when a torque is applied to it." It is fascinating what beauty and elegance exist hidden in silence and invisibility of physics which is never appreciated by many people.
The above contribution should be followed by Universities in London, Dundee, Cambridge, Sydney, and others which in the past showed much interest in the working out and showing the performance of the gyros.
40 years on and nobody has translated this?
WARNING: Hungarian flag at 2:23
AAAAAAA SCARY NOOOOOOO
Yrs to catch for centre and gyrolect gravity array ieatative field on Mars earth moon lactate algorithm.
Ничего не понял, но однозначно круто
I ya nyet.
always balance
Watching in 2020. Infected year by Corona Virus.🦠
2019 vid cool
И нах это выкладывать в таком исполнении?