As a thumb rule we can calculate the size of column for G+1F for residential building. First assume load per floor for residential building as 1.5 t/m^2. For max distance of column is 5m span. Total load on column = No. floors x tributary areax load intensity per floor. = 2x (5x5m)x1.5 t/m^2=75 t . Multiply by 10 to get kn= 750 kn. Breadth b assumed=23cm. Depth required= 750/23=32.61cm say 30cm or 38cm. Column size is 23x 30cm or 23 x38cm. If you provide less size steel will be more. If you assume higher size steel required will be less. Provide 6 nos 12mm with 8mm dis ties at 150 mm c/c
First decide load coming on column. Total load =No. of storeys x Tributary area xLoad per m^2 per floor. For residential building we assume 15 to 20 KN/m^2. For Pu=970 KN say (calculate load as per plan) Pu=0.40fck Ac+0.67 fyAsc For M20 and fy415 steel assuming 2.50% steel Pu=0.40 x20 (0.975 Ag) +0.67x415 x0.025Ag Pu=7.80Ag+6.951 Ag =14.75 Ag. In this Pu=16875 x10^3 =14.75 Ag Ag=970x10^3/14.75=65762.71 mm^2 Assuming square section side of column=256.44mm say 300mm . Provide 300 x 300 mm square column.. We can Tabulate the various percentage of steel for M20 concrete and fy 415 steel pt=0.80% Pu=8.16 1.0% Pu=10.70 1.50% Pu=12.05 2.0% Pu=13.40 2.50% Pu=14.75 3.0% Pu=16.10 For economical max percentage of steel may be 2.50% may be adopted. This is for simplication.
Hi, If the column is at corner side then should I use 4 16mm bar for 10" x 10"? And for the middle of the slab like near the stair... 6 16mm rod for 10" x 12"? Is it ok to go?
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As a thumb rule we can calculate the size of column for G+1F for residential building. First assume load per floor for residential building as 1.5 t/m^2. For max distance of column is 5m span. Total load on column = No. floors x tributary areax load intensity per floor.
= 2x (5x5m)x1.5 t/m^2=75 t . Multiply by 10 to get kn= 750 kn.
Breadth b assumed=23cm. Depth required= 750/23=32.61cm say 30cm or 38cm.
Column size is 23x 30cm or 23 x38cm. If you provide less size steel will be more. If you assume higher size steel required will be less. Provide 6 nos 12mm with 8mm dis ties at 150 mm c/c
Asalaam alaikum :AM WATCHING FROM UGANDA
First decide load coming on column. Total load =No. of storeys x Tributary area xLoad per m^2 per floor. For residential building we assume 15 to 20 KN/m^2.
For Pu=970 KN say (calculate load as per plan)
Pu=0.40fck Ac+0.67 fyAsc For M20 and fy415 steel assuming 2.50% steel
Pu=0.40 x20 (0.975 Ag) +0.67x415 x0.025Ag
Pu=7.80Ag+6.951 Ag =14.75 Ag.
In this Pu=16875 x10^3 =14.75 Ag
Ag=970x10^3/14.75=65762.71 mm^2
Assuming square section side of column=256.44mm say 300mm
. Provide 300 x 300 mm square column..
We can Tabulate the various percentage of steel for M20 concrete
and fy 415 steel
pt=0.80% Pu=8.16
1.0% Pu=10.70
1.50% Pu=12.05
2.0% Pu=13.40
2.50% Pu=14.75
3.0% Pu=16.10
For economical max percentage of steel may be 2.50% may be adopted. This is for simplication.
Grit sir g
Very Nice Sir! Love From Pakistan,.
Sir for example:1 column need rod 12mm no.6 or 16mm no.4 which is strong?
Good
Very use ful sir tq
Thanks For Teaching 👌🏻👍🏻✌🏻
Thanks for your kindness
Where you have observed this column size in residential building man?? You are incorrect…
Interesting ...
Thank you
Thank You sir...
Sir please teach us about roof steel truss
Give knowledge on commercial buildings
Ok sir
sir what if the pillar are circular
like the front column are circular
For this what is plinth beam
How to dicide
Please urdu may bola karey.
You haven't explained bro
Hi,
If the column is at corner side then should I use 4 16mm bar for 10" x 10"?
And for the middle of the slab like near the stair... 6 16mm rod for 10" x 12"?
Is it ok to go?
Not sufficient explaination, there is No Structural Computation, how did you. Get those results. And if ACI Code shall. Be Considered it. Will. FAIL.