But that formula is taken from P=U*I and assumes U and I to be in phase, the actual formula for AC power is P=U*I*cos(phase), which can be rewritten as P=cos(phase)*(U^2)/R, you are lacking therefore the cosine factor and the power is actualy weaker. Am I correct?
@@Centar1964 it's been a long time since I posted this, I think my concern was that the actual power delivered to a speaker is going to be less since it's a reactive load
I have a water heating resistor that has 4 ohms (alarmingly accurate 4 ohms), could I use it to do the test instead of the 100w resistor or could it interfere with the test because it can vary the resistance as it heats up?
The multimeter used "Fluke 17B" does NOT measure true RMS, so the figure calculated is not accurate. Also the current-voltage phase difference is also NOT factored in the calculations, again giving a poor calculated reading.
Cheap multimeters even the yellow one can measure "relatively" accurate RMS in this case because the wave was sine in nature, I agree another wave-like a triangle, arbitrary waveform it cannot measure the true RMS. Talking about Current-voltage phase, the load was resistive, not inductive, i.e no speaker was connected at the output so this test was fair I think
Really nice work there, my friend! Pretty interesting! 😃
Very informative Love this video
Useful video
Great video. Thanks
Love your channel :)
I can see a business opportunity in Australia with JLPCB!
Very use full video I like very much!!!
Thank you 👍👍👍👍
can you make dc short protection,for diy bench power supply
Reminds me of college. ,back in the day..lol
But that formula is taken from P=U*I and assumes U and I to be in phase, the actual formula for AC power is P=U*I*cos(phase), which can be rewritten as P=cos(phase)*(U^2)/R, you are lacking therefore the cosine factor and the power is actualy weaker. Am I correct?
Very good observation.
Voltage and current are in phase through a resistive element so the volts^2/resistance will be correct. Same as D.C.
@@Centar1964 it's been a long time since I posted this, I think my concern was that the actual power delivered to a speaker is going to be less since it's a reactive load
Very useful thnzz
I have a water heating resistor that has 4 ohms (alarmingly accurate 4 ohms), could I use it to do the test instead of the 100w resistor or could it interfere with the test because it can vary the resistance as it heats up?
By the way, great video, well explained. I would definitely send the link to this video in case a friend needs a more detailed explanation.
Yes actually better than a resister...
Can you make diy esc
Sheeeet! I can't even buy a coffee for $2 !!
Good video man😀. I have same amp i will make a portable 6" subwoofer(amp is realy good, like your vids.☺)(my English is realy bad)
"allowd up to 26V" those caps are only 25V rated
And she even mentions the 25 volt rating at one point but then goes on suggesting that 26 volts could be tried...doesn't make sense...
👍👏
*Once*
i found 1W resistor
Inside of a 10W resistor
💀💀💀💀💀💀💀
The multimeter used "Fluke 17B" does NOT measure true RMS, so the figure calculated is not accurate. Also the current-voltage phase difference is also NOT factored in the calculations, again giving a poor calculated reading.
Cheap multimeters even the yellow one can measure "relatively" accurate RMS in this case because the wave was sine in nature, I agree another wave-like a triangle, arbitrary waveform it cannot measure the true RMS. Talking about Current-voltage phase, the load was resistive, not inductive, i.e no speaker was connected at the output so this test was fair I think
power factor...
Is 1 in this case. Resistive element....
kasyan : kasihan : kacian
I didn't understand anything bro .😂😂😂😂😂😂
can you make dc short protection,for diy bench power supply