THANK YOU SO MUCH FOR THIS VIDEO! I have a test on this today and my teacher doesn't teach (or do anything but get paid) but now I know not only what a cantilever is but how to solve a problem with one!
You did a great job defining cantilever beams and free body diagrams at the beginning of the video. It’s super helpful that you went into detail about each step. One thing I noticed is that you didn’t explain the moment equilibrium equation. For example, you could explain why you chose to take the moment about point A and also explain why the 300 lb force is multiplied by 12 feet. The way that you presented how the force creates a moment and the direction of that moment around point A is a great trick that’s not taught as much as it should be! Thanks!
+Audrey Fyock Good point. It doesn't matter which point you take the moments about -- the answer will come out the same. However, some points make the math easier. For instance, taking it about point A gives Rv a lever arm of zero, thus removing it from the equation and allowing you to solve for Rm directly without back substitution.
Same process. Sum of the moments about any point would have to equal zero, so the reaction moment would be M CCW. Since no horiz or vert forces, reaction forces would be zero.
If I wanted to know how much weight could be applied at the free end of the beam before it fractures, what would be the variables to consider and equations to answer that question?
Im making a cantilevered pullup bar from steel tube and trying to owrk out what steel tube i need, would love it if you could do a worked example for this. The vertical pole will be 1.35m high from the highest wall bracket and the horizontal pole will be 1m wide, the load will be around 100kg
I have a question: if we don't have a force applicated on the free extreme of the beam, then Rv=weight of the beam???? And Ma=Weight of the beam• 6'????? Thanks!!!
A cantilever beam has one free end and one fixed end........ When a point load is applied at the free end............Does its still called a cantilever beam? Because now one end is fixed but the other is not free.......
the applied point load at the 'free' end does not change the support conditions (tip remains 'free' to displace under load), so, yes, it is still a cantilever.
I believe you've made a mistake when calculating the reaction forces in the Y direction, where you never multiplied them by their respective distance. Correct me if I am wrong, but you state it yourself when talking about the Moment force, which doesn't need to be multiplied by the distance away from the point of calculation.
+artherj327 The reaction forces are correct. You only need to multiply forces by distances when summing moments. For this case, since there is only one vertical reaction, the vertical forces are summed directly
Great video I learned more in 8 minutes then I did in a week, thanks John
THANK YOU SO MUCH FOR THIS VIDEO! I have a test on this today and my teacher doesn't teach (or do anything but get paid) but now I know not only what a cantilever is but how to solve a problem with one!
we must have the same prof.
You did a great job defining cantilever beams and free body diagrams at the beginning of the video. It’s super helpful that you went into detail about each step. One thing I noticed is that you didn’t explain the moment equilibrium equation. For example, you could explain why you chose to take the moment about point A and also explain why the 300 lb force is multiplied by 12 feet. The way that you presented how the force creates a moment and the direction of that moment around point A is a great trick that’s not taught as much as it should be! Thanks!
+Audrey Fyock Good point. It doesn't matter which point you take the moments about -- the answer will come out the same. However, some points make the math easier. For instance, taking it about point A gives Rv a lever arm of zero, thus removing it from the equation and allowing you to solve for Rm directly without back substitution.
Thanks for the nice description.
I see a fellow named Saima Awan has uploaded this same video just recently.
Excellent example and well explained. Thank you for this.
Informative Channel
Same process. Sum of the moments about any point would have to equal zero, so the reaction moment would be M CCW. Since no horiz or vert forces, reaction forces would be zero.
John Tingerthal please how I can solve this problem by numerical algebraic equation
If I wanted to know how much weight could be applied at the free end of the beam before it fractures, what would be the variables to consider and equations to answer that question?
Im making a cantilevered pullup bar from steel tube and trying to owrk out what steel tube i need, would love it if you could do a worked example for this. The vertical pole will be 1.35m high from the highest wall bracket and the horizontal pole will be 1m wide, the load will be around 100kg
Do you have any videos that show how this BMD diagram differs from a beam supported on both sides?
Video is super..but the audio is low pitch to hear sir..pls increase the sound of audio sir
i want to create a cantilever stairs for in my house, is this equation applicable to it?
and why it 300 lb?
thx
I have a question: if we don't have a force applicated on the free extreme of the beam, then Rv=weight of the beam???? And Ma=Weight of the beam• 6'????? Thanks!!!
yes you are correct, assuming the beam has a uniform weight per length.
Thanks you , your video will help me.
What if you have a bending moment load in a diagram? can it simply be added to the equation Fy=0?
+Nicole Noyola
No, you would add it to the equation Sum M=0. Ry at support would stay the same, but moment at support would change.
+John Tingerthal Hey I forgot to thank you a few weeks back, so thank you! I got it now.
Thank you.. It is helping me
do you have one for an overhang beam?
A cantilever beam has one free end and one fixed end........
When a point load is applied at the free end............Does its still called a cantilever beam?
Because now one end is fixed but the other is not free.......
the applied point load at the 'free' end does not change the support conditions (tip remains 'free' to displace under load), so, yes, it is still a cantilever.
Ok......got it...Thanks a lot man
John Tingerthal but what about the direction is it anticlock or clock
John Tingerthal i.e if Ma is anticlock den moment at free end is also anticlock???
thankyou so much.
I believe you've made a mistake when calculating the reaction forces in the Y direction, where you never multiplied them by their respective distance. Correct me if I am wrong, but you state it yourself when talking about the Moment force, which doesn't need to be multiplied by the distance away from the point of calculation.
+artherj327 The reaction forces are correct. You only need to multiply forces by distances when summing moments. For this case, since there is only one vertical reaction, the vertical forces are summed directly
Sound is low
tnx
hahahaha americans use pounds and feet