Your content is helping the engineers of our future. Thank You for the extremely well produced video, I was able to grasp the material very well compared to what I hear in lecture.
Straight to the point. I was able to grab the main concept within just the duration of this video. Very helpful. Thanks man keep producing more videos.🙏🔥💯
hey! once again to your channel on my new semester. some of your videos are amazingly helpful for understanding the basics. please make more videos about solid mechanics and fluid mechanics.
Thank you very much, really glad to hear these videos helped you out. I have the topics you mentioned on my to do list, though I don't know when I will get to them. I'll do my best!
Had a good sleep (first time in a while), waking up, feeling great. Open TH-cam, see this on recommended, try it out. Feels even better cause now i understand everything on how and why they are like that ! 100% Approve from Mechanical Engineering Student. 100% efficiency on the video! Great job!
This statics playlist is amazing. You did a fantastic job 👏. First, you give the concept and then follow up with solving examples that completely clears up the topic. I just wanna ask that you didn't upload any video on dry friction. Isn't it part of engineering statics?
I think this depends on the curriculum. Some courses cover friction as a first year course, others cover it more in dynamics, and some in second year courses. I didn't cover it because I was going to make more videos in the future, just not yet for statics.
this legit the best video on this topic. Seen so many videos regarding this topic but some or the other end up not explaining some bit of crutial information in between so I have to find another video to watch. This video itself covered everything I need to know for my assignment. A big thank you for explaining the content thoroughly.
I'm really happy to hear everything you needed was said in the video. Thank you taking the time to write your comment, I appreciate it. I wish you the best with your studies!
This is my go to channel whenever i need a refresh on statics and dynamics From solids to structure analysis i come here every few months. Keep up the good work sir. 💜
Hello. I don’t know who you are but thank you for existing and making life easier for a stupid engineering student like myself. I don’t think I’ll pass my statics class without your channel. Thank you, hope you’re doing well.
I am just gonna let you know that if you made it into an engineering course at a university, you're definitely not stupid. Statics will get easier, I promise, as long as you get the fundamentals right. Do as many practice problems as possible, try to solve the problems I solve in these videos without seeing the solution first, and if you get stuck, go through how I solve it. Don't beat yourself up, keep up the hard work and it'll get easier for you. I believe in you! You got this, and I wish you the absolute best with your studies :)
Thank you for your kind words, I really needed it right now. I will definitely remember your advice and this channel. I hope I can help you too someday when I become successful, although I don’t know how. Thank you again. Keep safe.
@@fruitpunch7361 Do your best, you got this! Thank you also for your kind words and let me know if you need clarifications on any part of the videos. I'll do my best to help.
Hello! I just want to thank you again. I’ve just received my second statics assessment results and I got 100%. I really can’t imagine how I’d be able to get that without your videos. Thank you!
@@fruitpunch7361 AWESOME!!! You did really well and I am very happy for you :) Keep up the great work and let me know if you need any clarifications on the videos.
THANK YOU VERY MUCH SIRRRR!!! AREA MOMENT METHOD IS SO MUCH BETTER since most of us are struggling with the equation methond cause we always assume all the time that x(length) is just equal to distance from the origin to the cut section and we put value in it. and that's why we have wrong results. Thank youuuuuuuuuuuuuuuuuu
I WISH you were around when I took Statics (Mechanics of Solids) hahaha Much better than my professor. I'm almost graduated now but if I may suggest something, please make videos on the stress tensor, equivalent loads, yield criterion (tresca and von mises) and beam deflection/slope/moment/shear/load for the future generation of students. That way you'd have more or less the whole mechanics of solids class for them 😊
amazing content. I do have a concern, though. When you say clockwise moments are positive, this directly contradicts what my prof told me. He said to think of which way the beam bends due to the moment. If the beam makes a happy face then the moment is positive. So given a standard beam, if the moment is on the left side, a clock-wise moment is positive. If the moment is on the right side, a counter clock wise moment is postive. Can you explain your moment sign convention plz
Moments aren't positive or negative, they are either "clockwise", or "counter-clockwise" in 2D space, and in 3D space, you would use the right hand rule to determine the direction of the vector. Even in 2D space, the moment vector is still determined using the right hand rule. If it's a counterclockwise moment, then the moment vector would be straight of the screen towards you, and vice versa. This is why people usually pick counterclockwise to be positive. I don't like counterclockwise being positive, it's just a personal preference. It makes no difference to the answer. In fact, I encourage you to try it both ways, you will still get the same answer. This is what is important: -If you pick counterclockwise to be positive, and your answer is positive, then your moment is counterclockwise. -If you pick counterclockwise to be positive and your answer is negative, then your moment is clockwise. -If you pick clockwise to be positive and your answer is positive, then your moment is clockwise. -If you pick clockwise to be positive and your answer is negative, then your moment is counterclockwise. You can pick whatever side you want to be positive, like when you pick up to be positive, or down to be positive. It's just an assumption. As a convention, people generally consider positive moments as counterclockwise since they are directed along the positive z axis (out of the screen/page). It's completely up to you.
Thank you very much for the videos! Can I ask, for the first method used, how do you know when you need to solve shear and moment forces forth both pieces cut? I have seen examples in my notes where only the shear force and moment for one half of the cut member is solved, and used for the whole Shear force and moment diagrams.
If it's just 2 pieces, or easy to figure out in your mind, you only need to solve for one half, since you can figure out what comes next, they all have to come back to their return points on the graph. If you do enough questions, you can see what comes next without going through the steps. If you're new to this though, I think its better to solve for all the pieces :)
Hi, I understand everything clearly. My only issue is: how do you know what sign convention to use when assigning internal loading directions during sectioning? If you use a positive shear (V), the equation for internal shear turns into a positive slope. The equation would be: V=40x-133.75 which is incorrect, since at x=0, V= -133.75. Yet, when using the method of sections, a positive shear is the correct sign convention. Im at a loss, any clarification would be appreciated, thank you.
Hi there! I appreciate the videos a lot they are truly a life saver and blessing. I do request that you make a similar video to this on method of integration. Although not hard, I personally don’t understand how to get the constants in the integrals, if this could be explained for others, it would be greatly appreciated. Thanks
Thank you for the feedback! I will add that topic to my list of things to do in the future. I can't say when I can get around to it, but I will do my best :)
You'are just amazing.i hope that you talk about mechanics of materials for the next people who will want to know about it. this course needs your explanation and I know what I'm talking about haha!. thank you again
Is it possible you could make a video using x as a length in your problems and having to solve in relation to x to find the shear force and moment diagrams?
I am not entirely sure of your question. Is there an example you can give me so I can take a look to see what type of problem you're talking about? Many thanks!
@@arthurbosch9041 I don't know which question that is, but is it something like the length represented as a variable instead of a fixed length? If so, the process is the same, you'd just have your graphs as a function of x.
Thank you for this wonderful video, I was able to grasp the topic. I was wondering if you plan on creating videos about strengths of materials or mechanics of deformable bodies, it will be a great help.
At 7:20 when you were finding V, is there a reason you used -40x and didn’t use -320 for the distributed load? Would it be wrong to use -320 instead of -40x?
So we want these equations in terms of length. We don't want fixed values. A fixed value would only give us the shear force at a specific length, but if we write it with respect to "x" then we get it as a function of length.
Thanks a bunch! It is helpful! However, I don't know how to use the second method if a distributed load gas a triangular shape... It is still ambiguous.
Yes, I agree, I will probably cover a example like that in the future, but the general idea is the same, your textbook/ course material should have an example with a triangular distributed load.
Question! On your example three, there is a moment with a magnitude of 1200 N*m. It’s turning clockwise and you treat it as positive, the very next example, there is a moment with magnitude 20 N*m, which is also turning clockwise but you treat it as a negative. Could you explain what is going on there? Im with the impression that counterclockwise is positive and negative for clockwise. Anyhow, great video!
You can pick whatever direction you want to be positive. Depending on the number of negative signs you deal with, you should pick a clockwise or counter-clockwise direction that gives you the least amount of negative signs. That makes your life easier, but if it doesn't, you can always just keep clockwise or counter-clockwise to be positive, it's really up to you. It makes no difference to the answer, because moments aren't positive or negative, they just have directions. So I change the positive side based on what makes the math more simple. It's the same as when you deal with forces. Imagine you have 10 forces down and 2 forces up. It's easier to make down positive and up negative, then you deal with less negative signs. That's why we always establish a coordinate system first, saying which sides will be up or down. In the end, our answer will indicate whether the resultant force is up or down, not whether it's positive or negative. I hope that makes sense.
4:00 why is the shear force drawn upwards? Is this the same as having it drawn the other way but flipping the sign? If it is wouldnt this still effect calculations?
So, if I'm needing to find a generalized equation to demonstrate forces at any point along a beam, or cable, or some other rigid body, the moment and force diagrams are how you get there?
Hmm, I guess you can sort of say that, but simply put, shear force and moment diagrams are there to help us understand the effects happening on an object at any given point.
Hi again professor I have a question here. I realised that all shear and moment diagrams' values come to zero at the end. Firstly, is my observation true? Secondly, if so why it is like that? I really appreciate it
Yes, that's right. If you look at the equations we write, you can see that by plugging in the full length, it ends up at 0. The beam is in equilibrium, so it starts at 0 and ends at 0.
my statics course uses counterclockwise moment as positive, my equations result in the same magnitude just opposite signs. when drawing my shear force and moment diagrams would i draw it the opposite way?
I have some questions about the last class. In the first example, when x=2 shows two separate regions, it is obvious that v is in the same direction. However, why are the regions of v different when drawing, one is 20 (the upper half axis of x) and the other is -10 (the lower half axis of x)? Is the final shape of the graph different for everyone (because everyone's initial assumptions are different)
we don't consider x = 2, we consider 0 =< x < 2, and 2 < x = 2, we have a shear force of -10. The difference between the two parts, so 20 - (-10) = 30 kN, that is the applied force of the beam. The diagram will look the same for every student, there shouldn't be any difference. There are no assumptions when drawing these diagrams.
@@JessicaColin-vc1uf For the first question, please see this video first: th-cam.com/video/LPd4vW8f9Ac/w-d-xo.html For the second question, we need the values with respect to distances. If we use 320, we will get one single point of data. If we use x, we can write an equation that allows us to plot a whole set of data points.
i have 2 questions. The 1st one is, when we are calculating the separate sections, why aren't we drawing and calculating the x-forces? is it because the x-forces acting on the whole beam are equal to 0, or is there different reason? And the 2nd one is, in the 2nd example when we are finding the moment about A, there is this moment 150kNm and it is positive, but why are the 320kN and 20kN forces positive and By is negative? I thought the By is gonna be positive since it is acting upwards and the 2 other forces are gonna be negative
For the first question, there are no x-forces acting upon the beam, so there isn't anything for us to consider. For the 2nd question, it depends on the direction you chose the moment to be positive. So for the 2nd example, we chose clockwise as positive. So looking at 6:16, look at the 320 kN force. It's pointing down, and imagine the beam is free to rotate about point A, which way would the beam rotate? If you push down at the location where the 320kN force is applied, it will turn clockwise about point A, so it's a positive moment. The same is true for 20 kN force. But look at the BY force. If you imagine using your finger to push up at that location, which way would the beam rotate? It would rotate counter clockwise, so it's a negative moment.
@@QuestionSolutions okay, thank you very much! your answer made everything clear for me. btw thanks for all your videos, i always watch them before any test!
Is the shear force diagram continuous or there is jump discontinuity at the point loads ( like we have placed the cut either immediate left or immediate right of the point load but not exactly at the point load) so does that mean the sf diagram is discontinuous at the point load
Shear force diagrams are drawn continuously. They show a big jump whenever an external force is applied but it's still continuous. You can google "shear force diagrams" to get a better example too.
Thank you for the reply 🙏 I have one last doubt Timestamp 4.45 at the point where 30 KN load is applied in the shear force diagram there is a vertical jump Doubt - what is the value of shear force exactly at the point where 30 KN load is applied because on the immediate left of 30 KN point load I am having a shear force of 20 KN positive. But on the immediate right of 30 KN point load i am having a shear force -10 KN. But what is the value of shear force exactly at the point where 30 KN point load is applied Thank you and great work 👍
I have a question: When exactly is it absolutely necessary to split the beam into sections (i.e: using x for length, etc) when making shear/moment diagrams? Is there a way to tell which method to use when given a problem?
If you're referring to the 2 methods I show in this video, then you can do either one to get the same answer. Its faster to not split the beam and use method 2, especially when you become comfortable with the relationships between shear and moment diagrams.
So the 1200 N•m is an external moment applied to the beam. It's like someone randomly trying to turn it about that point. That needs to be accounted for in our graph. Clockwise means it needs to be added, counter-clockwise means it needs to be subtracted.
That's the first request of this type :) Unfortunately, that's not really something I teach, you should have counselors and career center administrators that teach those sorts of things. Even if I were to make a video on it, I probably wouldn't do that great of a job 😅 Sorry!
Question Solutions no worries! Thank you for the solid mechanics’ videos though! I have shared with Mechanical Engineering students. Have you considered Fluid Mechanics, Thermodynamics, Heat Transfer, etc courses?
@@rehanrashid9296 I have gotten a lot of requests for thermodynamics, which could be what I cover next. These days have been busy, but I hope to start that series soon as well. If you don't mind me asking, what books do you use for those subjects? I am asking this question from a lot of people to get a rough idea of what is being used 👍
Question Solutions For Thermodynamics 1,2 we use: Thermodynamics: An Engineering Approach (9th Edition) Yunus A. Cengel and Michael A Boles For Fluid Mechanics/Fluid Dynamics: Fluid Mechanics by Frank M. White, 8th Edition, McGraw Hill For Heat & Mass Transfer: Heat and Mass Transfer, Fundamentals and Applications by Yunus Cengel and Afshin Ghajar, 5th edition, McGraw Hill these are the books for those courses used at YorkU, and no worries, take your time :)
Is the 40x(x/2), thats just the distributed load but you put it as a point load in the centroid of that load? is that how you get the integral of the shear load? sorry my brain is tired
this guy explains things better in 16 min than my professor does in 1.5h
Thank you very much, glad to hear the explanations are good 👍 Best wishes with your studies!
No doubt you said the bitter truth.
Better than 99.9% of SFD and BMD diagram tutorial videos out there, you explained the method very clearly.
Thank you very much :)
Your content is helping the engineers of our future. Thank You for the extremely well produced video, I was able to grasp the material very well compared to what I hear in lecture.
Really glad to hear that :) Thank you for your kind comment! Best wishes with your studies.
exactly! we need more educators like you
Life saving. I haven't been able to understand these in years.
I am glad this helped you. Best wishes with your studies :)
Single handedly pulling me through my statics class🙌🏽
Thank you 🙏🏽
That's awesome to hear! Keep up the great work and best wishes with your studies.
Honestly clearest explanation I’ve heard all month
Thanks! I hope it was helpful.
Thank you so much, you took my exam anxiety and taught me the basics! Make more mechanics and elastostatics videos please :)
Really happy to hear that. Keep up the awesome work and best wishes with your exams! :)
I can’t thank you enough, quick, accurate, detailed and sharp 😍♥️.
Thank you very much for your kind comment! :)
This explains everything I had been seeking for a long time ago. This is marvelous!
Thank you and I am really happy this is what you were looking for. Keep up the great work and best wishes with your studies.
Statics becomes more easy with you. Animations are perfect to understand the concept. I wish you success.
Thank you, glad to hear it helps :) I also wish you much success in everything you do!
Straight to the point. I was able to grab the main concept within just the duration of this video. Very helpful. Thanks man keep producing more videos.🙏🔥💯
Thank you very much! Glad to hear you understood the concept for a short video, keep up the great work. Best wishes with your studies. 🔥
wow!! two days of lecture in 16 minutes! Thank U!!
Glad it was helpful! Keep up the good work.
Literally my paper is in 2 hours and this is the only topic left to cover. You're the best man!
I hope you did well on your exam and everything went smoothly!
hey! once again to your channel on my new semester. some of your videos are amazingly helpful for understanding the basics. please make more videos about solid mechanics and fluid mechanics.
Thank you very much, really glad to hear these videos helped you out. I have the topics you mentioned on my to do list, though I don't know when I will get to them. I'll do my best!
Had a good sleep (first time in a while), waking up, feeling great. Open TH-cam, see this on recommended, try it out. Feels even better cause now i understand everything on how and why they are like that !
100% Approve from Mechanical Engineering Student. 100% efficiency on the video! Great job!
Well, I hope you get many good sleeps in your future! And thank you, glad this video was helpful :)
This statics playlist is amazing. You did a fantastic job 👏. First, you give the concept and then follow up with solving examples that completely clears up the topic. I just wanna ask that you didn't upload any video on dry friction. Isn't it part of engineering statics?
I think this depends on the curriculum. Some courses cover friction as a first year course, others cover it more in dynamics, and some in second year courses. I didn't cover it because I was going to make more videos in the future, just not yet for statics.
thanks for this! I just understood a month-worth of lectures in minutes
I am really glad to hear that. Keep up the awesome work! :)
Best channel for Engineers.
Thank you.
Go ahead.
👍
this legit the best video on this topic. Seen so many videos regarding this topic but some or the other end up not explaining some bit of crutial information in between so I have to find another video to watch. This video itself covered everything I need to know for my assignment. A big thank you for explaining the content thoroughly.
I'm really happy to hear everything you needed was said in the video. Thank you taking the time to write your comment, I appreciate it. I wish you the best with your studies!
This is my go to channel whenever i need a refresh on statics and dynamics
From solids to structure analysis i come here every few months.
Keep up the good work sir. 💜
I am glad these videos help you out :) ❤❤
Thank you for helping a foreign student studying in Germany. Keep on posting engineering stuffs.
You're very welcome. I wish you the best with your studies!
Hello. I don’t know who you are but thank you for existing and making life easier for a stupid engineering student like myself. I don’t think I’ll pass my statics class without your channel. Thank you, hope you’re doing well.
I am just gonna let you know that if you made it into an engineering course at a university, you're definitely not stupid. Statics will get easier, I promise, as long as you get the fundamentals right. Do as many practice problems as possible, try to solve the problems I solve in these videos without seeing the solution first, and if you get stuck, go through how I solve it. Don't beat yourself up, keep up the hard work and it'll get easier for you. I believe in you! You got this, and I wish you the absolute best with your studies :)
Thank you for your kind words, I really needed it right now. I will definitely remember your advice and this channel. I hope I can help you too someday when I become successful, although I don’t know how. Thank you again. Keep safe.
@@fruitpunch7361 Do your best, you got this! Thank you also for your kind words and let me know if you need clarifications on any part of the videos. I'll do my best to help.
Hello! I just want to thank you again. I’ve just received my second statics assessment results and I got 100%. I really can’t imagine how I’d be able to get that without your videos. Thank you!
@@fruitpunch7361 AWESOME!!! You did really well and I am very happy for you :) Keep up the great work and let me know if you need any clarifications on the videos.
One of the Most Crystal Clear Video Regarding SFD & BMD. ❤❤❤
Thank you very much ❤❤
Keep up the good work man you are underrated
:) Many thanks!
Thank you for this was panicking as about to take a statics final and forgot how to do this and this made it easy to understand thanks
You're very welcome! Best of luck on your final 👍
i can't believe i've been struggling with this for months and I've only watched this video and understood the concept
I am really glad to hear this video helped you out. Keep up the great work and I hope you do amazingly on your courses.
nothing but remarkable.....truly .....😇god bless you
Thank you very much, I appreciate it.
You are the best teacher i ever seen before in my life thank you❤😍
You're very welcome and thank you for your kind compliment :)
my deepest thanks for your quick and detailed lectures, you made a big impacts for engineer students around the world
You're very welcome! Thank you for the really nice comment. :)
thanks you you presentation is clear and well understandable
Glad to hear that :) Thank you!
You're a legend man.Thanks for the video.
Thank you and you're very welcome!
Oh my !ur video truly save the all students of mechanical department
I am really glad to hear this video is helpful to you. Keep up the great work!
awesome video for recap just before exams, very clear concepts .
Glad it was helpful! :)
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And may God bless you!
You're very welcome! Keep up the good work and best wishes with your studies.
YOU ARE BECOMING SO IMPORTANT TO ME.NO NEED OF ATTENDING MY FAKE LECTURERS.
😅 Glad to hear these videos are helping.
Finally after 3 weeks i found this video and finally got it. thank you dude.
😀
Glad to hear that! Best wishes with your studies :)
Brother, Cant thank you enough. May Allah bless you...
You are most welcome!
Your contents are amazing. Its way better than what the lecturer had taught us in the university.
Thank you very much! I wish you the best with your studies.
Thanks sir, the concept is very clear.
I am happy to hear that! Keep up the good work.
THANK YOU VERY MUCH SIRRRR!!! AREA MOMENT METHOD IS SO MUCH BETTER since most of us are struggling with the equation methond cause we always assume all the time that x(length) is just equal to distance from the origin to the cut section and we put value in it. and that's why we have wrong results. Thank youuuuuuuuuuuuuuuuuu
You are very welcome!
Thank you so much, it really did help. Because you made this easy for me, people will also make it easy for you. Thanks a lot.
Glad to hear that and you are very welcome! :)
very helpful, while i was reviewing my course
Glad to hear that :)
I WISH you were around when I took Statics (Mechanics of Solids) hahaha
Much better than my professor.
I'm almost graduated now but if I may suggest something, please make videos on the stress tensor, equivalent loads, yield criterion (tresca and von mises) and beam deflection/slope/moment/shear/load for the future generation of students.
That way you'd have more or less the whole mechanics of solids class for them 😊
Thank you very much, for the kind comment and the recommendations on topics to cover. :)
Thank you for the video, a very good explanation of the concepts
You're very welcome! :)
amazing content. I do have a concern, though. When you say clockwise moments are positive, this directly contradicts what my prof told me. He said to think of which way the beam bends due to the moment. If the beam makes a happy face then the moment is positive. So given a standard beam, if the moment is on the left side, a clock-wise moment is positive. If the moment is on the right side, a counter clock wise moment is postive. Can you explain your moment sign convention plz
Moments aren't positive or negative, they are either "clockwise", or "counter-clockwise" in 2D space, and in 3D space, you would use the right hand rule to determine the direction of the vector. Even in 2D space, the moment vector is still determined using the right hand rule. If it's a counterclockwise moment, then the moment vector would be straight of the screen towards you, and vice versa. This is why people usually pick counterclockwise to be positive. I don't like counterclockwise being positive, it's just a personal preference. It makes no difference to the answer. In fact, I encourage you to try it both ways, you will still get the same answer.
This is what is important:
-If you pick counterclockwise to be positive, and your answer is positive, then your moment is counterclockwise.
-If you pick counterclockwise to be positive and your answer is negative, then your moment is clockwise.
-If you pick clockwise to be positive and your answer is positive, then your moment is clockwise.
-If you pick clockwise to be positive and your answer is negative, then your moment is counterclockwise.
You can pick whatever side you want to be positive, like when you pick up to be positive, or down to be positive. It's just an assumption. As a convention, people generally consider positive moments as counterclockwise since they are directed along the positive z axis (out of the screen/page). It's completely up to you.
Thank you very much for the videos! Can I ask, for the first method used, how do you know when you need to solve shear and moment forces forth both pieces cut? I have seen examples in my notes where only the shear force and moment for one half of the cut member is solved, and used for the whole Shear force and moment diagrams.
for both pieces *
If it's just 2 pieces, or easy to figure out in your mind, you only need to solve for one half, since you can figure out what comes next, they all have to come back to their return points on the graph. If you do enough questions, you can see what comes next without going through the steps. If you're new to this though, I think its better to solve for all the pieces :)
@@QuestionSolutions Thank you for the explanation! :)
After watching this finally I understood this. thanks a lot
I am glad to hear that :)
Thanks a lot for this. Much understood now
Glad to hear :)
Hi, I understand everything clearly. My only issue is: how do you know what sign convention to use when assigning internal loading directions during sectioning? If you use a positive shear (V), the equation for internal shear turns into a positive slope. The equation would be: V=40x-133.75 which is incorrect, since at x=0, V= -133.75. Yet, when using the method of sections, a positive shear is the correct sign convention. Im at a loss, any clarification would be appreciated, thank you.
Please watch this video first, and then if you still have the same concern, send me a comment, thanks! th-cam.com/video/LPd4vW8f9Ac/w-d-xo.html
Thanks, this is very helpful.
You're very welcome!
You are godsent. Thank you!
You're very welcome :)
Hi there! I appreciate the videos a lot they are truly a life saver and blessing. I do request that you make a similar video to this on method of integration. Although not hard, I personally don’t understand how to get the constants in the integrals, if this could be explained for others, it would be greatly appreciated. Thanks
Thank you for the feedback! I will add that topic to my list of things to do in the future. I can't say when I can get around to it, but I will do my best :)
@@QuestionSolutions
Good day! How do you find the vertex of the parabola of the shear moment diagram using the 2nd method mentioned in the video? Thank you!
You can find the x-coordinate using b/2a. The maximum bending moment occurs at the location where the shear force is 0. See 9:40.
You'are just amazing.i hope that you talk about mechanics of materials for the next people who will want to know about it. this course needs your explanation and I know what I'm talking about haha!. thank you again
That's on my list of things to do. I will do my best to do a series on that subject as well! :)
Goated youtuber thank you so much I love you
Thank you very much! Keep up the good work :)
Hi, in the last diagram how did you know when drawin the moment diagram, that the area under the 3 and 5 graph was 44,6 KN/M
22.3 x 2 = 44.6. It's a rectangle, so it's base times height. Base is 2, height is 22.3. I hope that helps!
You blew away all my doubt for BM SMD
Thank you very much, really glad to hear!
Thank you again for another great explanation ⭐
Glad you liked it!⭐
Y made my nightmare a cake thanks ❤️
That's awesome to hear! Keep up the great work ❤
You are doing great job man 👏👏👏 Thank you so much
You're very welcome! Keep up the great work and best wishes with your studies.
Is it possible you could make a video using x as a length in your problems and having to solve in relation to x to find the shear force and moment diagrams?
I am not entirely sure of your question. Is there an example you can give me so I can take a look to see what type of problem you're talking about? Many thanks!
@@QuestionSolutions I mean I'm not sure if you use this book or not but for example 7-9 in the engineering mechanics statics by hibbeler in SI units
@@arthurbosch9041 I don't know which question that is, but is it something like the length represented as a variable instead of a fixed length?
If so, the process is the same, you'd just have your graphs as a function of x.
You're like the Engineering Plug. Thanks
You're welcome!
thankk you so much, this video was very helpful!
Glad it was helpful! Keep up the great work.
amazing explanation 🖤
Thank you very much! ❤️
Great job. I need to know which programs were used to plot the diagrams. Thanks
The diagrams were drawn on illustrator.
sir your explanation is very good
Thank you very much :)
Thank you for this wonderful video, I was able to grasp the topic. I was wondering if you plan on creating videos about strengths of materials or mechanics of deformable bodies, it will be a great help.
You're very welcome. I do have plans on creating videos about strengths of materials, but probably not for some time. Best wishes with your studies!
@@QuestionSolutions Looking forward into that. Thank you!
At 7:20 when you were finding V, is there a reason you used -40x and didn’t use -320 for the distributed load? Would it be wrong to use -320 instead of -40x?
So we want these equations in terms of length. We don't want fixed values. A fixed value would only give us the shear force at a specific length, but if we write it with respect to "x" then we get it as a function of length.
Thanks a bunch! It is helpful! However, I don't know how to use the second method if a distributed load gas a triangular shape... It is still ambiguous.
Yes, I agree, I will probably cover a example like that in the future, but the general idea is the same, your textbook/ course material should have an example with a triangular distributed load.
This guy is a hero 👏🙌❤.
Many thanks!
awesome video, this really saved me!
Glad it helped :)
Question! On your example three, there is a moment with a magnitude of 1200 N*m. It’s turning clockwise and you treat it as positive, the very next example, there is a moment with magnitude 20 N*m, which is also turning clockwise but you treat it as a negative. Could you explain what is going on there? Im with the impression that counterclockwise is positive and negative for clockwise. Anyhow, great video!
You can pick whatever direction you want to be positive. Depending on the number of negative signs you deal with, you should pick a clockwise or counter-clockwise direction that gives you the least amount of negative signs. That makes your life easier, but if it doesn't, you can always just keep clockwise or counter-clockwise to be positive, it's really up to you. It makes no difference to the answer, because moments aren't positive or negative, they just have directions. So I change the positive side based on what makes the math more simple. It's the same as when you deal with forces. Imagine you have 10 forces down and 2 forces up. It's easier to make down positive and up negative, then you deal with less negative signs. That's why we always establish a coordinate system first, saying which sides will be up or down. In the end, our answer will indicate whether the resultant force is up or down, not whether it's positive or negative. I hope that makes sense.
Wow this was impressive I don’t really comment this types of videos but well done keep up the good work!
Thank you very much :)
Thank you for these videos!
You're very welcome!
you are a legend man
Thank you!
Thank you for this video, but I have a question: What program do you use for drawing and explaining?
I use illustrator to draw these diagrams.
very clear , thanks
Thank you! Best wishes with your studies :)
This video helped me a lot thank you so much
You're very welcome!
4:00 why is the shear force drawn upwards? Is this the same as having it drawn the other way but flipping the sign? If it is wouldnt this still effect calculations?
Please see this video first: th-cam.com/video/LPd4vW8f9Ac/w-d-xo.html
So, if I'm needing to find a generalized equation to demonstrate forces at any point along a beam, or cable, or some other rigid body, the moment and force diagrams are how you get there?
Hmm, I guess you can sort of say that, but simply put, shear force and moment diagrams are there to help us understand the effects happening on an object at any given point.
you're the best. thank you
👍 Many thanks!
Hi again professor I have a question here. I realised that all shear and moment diagrams' values come to zero at the end. Firstly, is my observation true?
Secondly, if so why it is like that?
I really appreciate it
Yes, that's right. If you look at the equations we write, you can see that by plugging in the full length, it ends up at 0. The beam is in equilibrium, so it starts at 0 and ends at 0.
my statics course uses counterclockwise moment as positive, my equations result in the same magnitude just opposite signs. when drawing my shear force and moment diagrams would i draw it the opposite way?
What does your professor want?
I have some questions about the last class. In the first example, when x=2 shows two separate regions, it is obvious that v is in the same direction. However, why are the regions of v different when drawing, one is 20 (the upper half axis of x) and the other is -10 (the lower half axis of x)? Is the final shape of the graph different for everyone (because everyone's initial assumptions are different)
we don't consider x = 2, we consider 0 =< x < 2, and 2 < x = 2, we have a shear force of -10. The difference between the two parts, so 20 - (-10) = 30 kN, that is the applied force of the beam. The diagram will look the same for every student, there shouldn't be any difference. There are no assumptions when drawing these diagrams.
Good afternoon Professor, on minute 3:55 when drawing the shear forces, how do we know which way they point? Or is this just an estimate? Thank you.
Also another question, in minute 7:07, why wouldn't be contemplate the force 320 KN instead of using 40x?
@@JessicaColin-vc1uf For the first question, please see this video first: th-cam.com/video/LPd4vW8f9Ac/w-d-xo.html
For the second question, we need the values with respect to distances. If we use 320, we will get one single point of data. If we use x, we can write an equation that allows us to plot a whole set of data points.
Thanks sir for thé explanation . pleace which software do you for drawing and animations 🙏
Animations are done using after effects and drawings are done using illustrator. 👍
i have 2 questions. The 1st one is, when we are calculating the separate sections, why aren't we drawing and calculating the x-forces? is it because the x-forces acting on the whole beam are equal to 0, or is there different reason? And the 2nd one is, in the 2nd example when we are finding the moment about A, there is this moment 150kNm and it is positive, but why are the 320kN and 20kN forces positive and By is negative? I thought the By is gonna be positive since it is acting upwards and the 2 other forces are gonna be negative
For the first question, there are no x-forces acting upon the beam, so there isn't anything for us to consider. For the 2nd question, it depends on the direction you chose the moment to be positive. So for the 2nd example, we chose clockwise as positive. So looking at 6:16, look at the 320 kN force. It's pointing down, and imagine the beam is free to rotate about point A, which way would the beam rotate? If you push down at the location where the 320kN force is applied, it will turn clockwise about point A, so it's a positive moment. The same is true for 20 kN force. But look at the BY force. If you imagine using your finger to push up at that location, which way would the beam rotate? It would rotate counter clockwise, so it's a negative moment.
@@QuestionSolutions okay, thank you very much! your answer made everything clear for me. btw thanks for all your videos, i always watch them before any test!
u saved my life
😅 Well, I'm really glad to hear that!
Is the shear force diagram continuous or there is jump discontinuity at the point loads ( like we have placed the cut either immediate left or immediate right of the point load but not exactly at the point load) so does that mean the sf diagram is discontinuous at the point load
Shear force diagrams are drawn continuously. They show a big jump whenever an external force is applied but it's still continuous. You can google "shear force diagrams" to get a better example too.
Thank you for the reply 🙏
I have one last doubt Timestamp 4.45 at the point where 30 KN load is applied in the shear force diagram there is a vertical jump
Doubt - what is the value of shear force exactly at the point where 30 KN load is applied because on the immediate left of 30 KN point load I am having a shear force of 20 KN positive. But on the immediate right of 30 KN point load i am having a shear force -10 KN. But what is the value of shear force exactly at the point where 30 KN point load is applied
Thank you and great work 👍
I have a question: When exactly is it absolutely necessary to split the beam into sections (i.e: using x for length, etc) when making shear/moment diagrams? Is there a way to tell which method to use when given a problem?
If you're referring to the 2 methods I show in this video, then you can do either one to get the same answer. Its faster to not split the beam and use method 2, especially when you become comfortable with the relationships between shear and moment diagrams.
@@QuestionSolutions Thanks for the quick response!
@@bagaboiebailey You're very welcome!
Well explained 😊
Thank you very much :)
At 11:58, why was the 1200 N•m moment added in the diagram? Whats the reasoning behind it and why wasnt it subtracted?
So the 1200 N•m is an external moment applied to the beam. It's like someone randomly trying to turn it about that point. That needs to be accounted for in our graph. Clockwise means it needs to be added, counter-clockwise means it needs to be subtracted.
lifesaver thanks a lotttt
You're very welcome!
Could you do an Engineering resume review and tips/advice for applying to internships? I know its something much different, but it is really helpful
That's the first request of this type :) Unfortunately, that's not really something I teach, you should have counselors and career center administrators that teach those sorts of things. Even if I were to make a video on it, I probably wouldn't do that great of a job 😅 Sorry!
Question Solutions no worries! Thank you for the solid mechanics’ videos though! I have shared with Mechanical Engineering students. Have you considered Fluid Mechanics, Thermodynamics, Heat Transfer, etc courses?
@@rehanrashid9296 I have gotten a lot of requests for thermodynamics, which could be what I cover next. These days have been busy, but I hope to start that series soon as well. If you don't mind me asking, what books do you use for those subjects? I am asking this question from a lot of people to get a rough idea of what is being used 👍
Question Solutions
For Thermodynamics 1,2 we use: Thermodynamics: An Engineering Approach (9th Edition) Yunus A. Cengel and Michael A Boles
For Fluid Mechanics/Fluid Dynamics: Fluid Mechanics by Frank M. White, 8th Edition, McGraw Hill
For Heat & Mass Transfer: Heat and Mass Transfer, Fundamentals and Applications by Yunus Cengel and Afshin Ghajar,
5th edition, McGraw Hill
these are the books for those courses used at YorkU, and no worries, take your time :)
@@rehanrashid9296 Wow, thanks for taking the time to write this reply. Really appreciate it! I will look through all of them. :)
Is the 40x(x/2), thats just the distributed load but you put it as a point load in the centroid of that load? is that how you get the integral of the shear load? sorry my brain is tired
That is correct, please see: th-cam.com/video/lI5klge2GlM/w-d-xo.html
@@QuestionSolutions thank you, I've subscribed
You're very welcome :)@@tturi2
Well done, thank you.
Thank you very much!
Thank you so much!
You're welcome!
how did you start with -28.6 for the last example when drawing the moment diagram
-14.3 x 2 = -28.6 (I show this at 15:04, with a red box on the shear force diagram)
@@QuestionSolutionsI'm confused on why you had to multiply it by 2
can we still use the equations when there are 3 regions of interest?
Of course, you'd just have 3 sections.
THANK YOU SO MUCHHH!
You're very welcomeeeee :)