Wouldn't you need two summations, one with 'i' for 'x sub j' and one with 'j' for 'y sub j'? Otherwise you're calculating the volume of a diagonal series of prisms. To calculate the rectangular grid, wouldn't you need two parameters (one for x, one for y)?
My lecture give me a homework for this topic and its question doesn't have any limits for x and y. It just said x>0 and y>0. For this case, will I get exact number or new equation? Sorry if my english is so bad. I will be very grateful to see your response. Thank you!
You should be given some sort of award by TH-cam. Thank you for uploading these videos.
I owe you my life.
That 1 dislike is from my lecturer , because he doesn't know how to explain like you -_-
@sifrael I don't see an error? Once we integrate with respect to x, when then evaluate at 2 and 0 and the inner integral is gone.
thank u so much... u helped me in my exams !!!.. keep it up :-)
When we sub in 3, we get 3 cubed divided by 3, giving us 9.
"WE TAKE A LOOK AT JUST 1 BOX!"
This is an introduction video. I have several example only videos that you can find in sequence at mathispower4u.com
Who else is watching during COVID-19 quarantine?
is there any reason you didn't change the limits at the end to the corresponding u?
So organised, thank you!
10:16 meant to say "2 over pi"
Yes, I sorry about that.
It must be the change in the Domain when you performed U substitution right ??
0:27 Loud, why?
Wouldn't you need two summations, one with 'i' for 'x sub j' and one with 'j' for 'y sub j'? Otherwise you're calculating the volume of a diagonal series of prisms. To calculate the rectangular grid, wouldn't you need two parameters (one for x, one for y)?
At 6:20,after you sub in the limits, shouldn't the 9x have been divided by 3 giving us 3x?
My lecture give me a homework for this topic and its question doesn't have any limits for x and y. It just said x>0 and y>0. For this case, will I get exact number or new equation? Sorry if my english is so bad. I will be very grateful to see your response. Thank you!
At 3:19 the limit of integration differs. Shouldn't it be [0,2] all the way when integrating with respect to x?
understood in 10 min what my teacher tried to explain in 4 hr
Thank you for making this video!
OMG you're on fireee thank you
3^3=27 you right 9 but thanx you are great sir
At the end you say pi over two, but mean two over pi.
You are the best
Lovely Winston Churchill quote.
like the way you explain
It bugs me how you say "with respects to" instead of "with respect to."
My friend Dis Ray got new specs
@@jeremykrans Does this work for you?
good effort
good shit fam
joe mahoney thanks fam
I like your voice
thank you!
U
uper bounder and lower bounder should be changed
good video!!!! thanks
thank you so much
Power
nice one
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after you done the u-substitution dont you have to change the limits of integration?
No because he plugs u value back into equation. If he left it as u he would have to change bounds.
Thank you!