Thanks for explaining where different formulas come from, as well as going at a fairly quick pace through the videos. That way if you get it its not to drawn out, but if you don't, all you have to do is pause it for a second : ) I love your videos!
Regarding Example 2, An octant is an eighth of the circle, so we should be using the outer limit as 0 to pi/4. Whereas, in the question, it is given as a quarter of the circle and so the limit from 0 to pi/2 is wrong.
The first octant would be an 1/8 of a sphere, but as you can see from the 2nd trace provided is would be 1/4 of a circle to accumulate the volume or 1/4 of 2pi which is pi/2.
please i need a quick answer i have a final after few hours in the second examples its stated in the question above xy plane so d0 must be from 0 to pi/4 is that right ? taking into consideration the (+ve x and +y plane ) ?
Dude you're literally saving me tonight!! Thanks for helping me as well as countless students in the world!!
Thank you for your kind comment. Glad I could help.
you r the best math teacher i have ever listened!! you really saved my GPA. please dont stop to share ur marvelllous videos.. thanks again :)
Thank you so much I was gonna cry in math class today cuz I had no idea what was going on. You my friend are a LIFE SAVER 😭
this channel deserve Millions of Millions subscribers!
Thank you for the comment. Please spread the word. :)
Thanks for explaining where different formulas come from, as well as going at a fairly quick pace through the videos. That way if you get it its not to drawn out, but if you don't, all you have to do is pause it for a second : ) I love your videos!
very detailed, and helpful! Also appreciate the quotations at the end of your lectures!
Great lecture. Needs more views!
Thank you so much sir watched so much videos only yours made sense
dude you're the best, thank you
Thanks for watching! I'm glad I could help.
Christiana Nogaliza damn you cute, hope you passed lol
Is it just me or did he use the first quadrant instead of octant in the second example?
you are right; but that would be for cartesian coordinates; here we are using Polar coordinates.
@@aladdinkayqubad1645 so how does it change?
@@c.o2307 you can convert the coordinates bro!
Regarding Example 2, An octant is an eighth of the circle, so we should be using the outer limit as 0 to pi/4. Whereas, in the question, it is given as a quarter of the circle and so the limit from 0 to pi/2 is wrong.
The first octant would be an 1/8 of a sphere, but as you can see from the 2nd trace provided is would be 1/4 of a circle to accumulate the volume or 1/4 of 2pi which is pi/2.
Thanks bro, this is very clear and very useful.
please i need a quick answer i have a final after few hours in the second examples its stated in the question above xy plane so d0 must be from 0 to pi/4 is that right ? taking into consideration the (+ve x and +y plane ) ?
Idk
At the first example is saying "above xy plane" so theta limits should be from 0 to PI
What program do you use to write on the screen?
Note :
In the second example, I think you forgot to include the addtional " r " that comes along with ( r dr d theta )
Notice that du = r dr, which contains the extra factor of r. As a result, I think everything is okay. Thanks for watching.
thank you! It helped me understand more :D
I'm glad.
When you let u = 9-r^2, shouldn't the bounds for r changes as well?
Because r^2 = x^2 + y^2 and the region of integration is x^2+y^2=1 -> r^2=1 -> r=1 and x^2+y^2=4 -> r^2=4 -> r=2.
Good explanation
keep up the good work!
Good Content
Bless your soul
Really nice thank you!
thanks a lot man. really helped
Thank you for the comment.
thank you so much man
We alwayse use x=rcost and y=rsint
we too
ur awesome !!!!! thank you
good shit bruh
u need to slow a bit mate
love u