Can somebody explain me why here g is taken negative even though we can't find the acceleration of whole journey like while going upwards its negative but while going downwards it's positive :/
Vertical component become 0 at the top... That is theit is no motion vertivally at top.... So, vertical displacement is 0.but horizontal disppacnot equal to 0.
Displacement will not become zero, it is vertical velocity which becomes zero at highest point for momentarily, because it's velocity changes from upward direction to downward direction.
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Can somebody explain me why here g is taken negative even though we can't find the acceleration of whole journey like while going upwards its negative but while going downwards it's positive :/
While going up velocity decrease and while getting down velocity will be increase
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What is the path of projectile
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This is angular or horizontal ?
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sir you should do that suscribe one first because after getting the ans no one will see it or do it between the lecture when half part is explained
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Sir 2:16 pe u kyu usin theta hai.. Why not ucos theta Or simply 'u'
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how displacement will become zero at the top of trajectory?
Vertical component become 0 at the top... That is theit is no motion vertivally at top.... So, vertical displacement is 0.but horizontal disppacnot equal to 0.
Displacement will not become zero, it is vertical velocity which becomes zero at highest point for momentarily, because it's velocity changes from upward direction to downward direction.
i am not understand anything from here😢
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Sir please use theta not Alpha
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