Thank you very much my sister ❤ you really help me😢 Tomorrow is my exam and you help me alot🎉....Anyways love from Fiji 🇫🇯.......Vinaka Vakalevu 🙏❤️🔥❤️🩹🙌🥹😘
You always subtract 1 from the value of the LCL of the 2nd interval to obtain the UCL of the first interval if the lowest place value of your data is 'ones' as it is here ... if the data looked like 4.1, 6.7, 9.2, 12.1 ... then you'd subtract the value of the lowest place value which in this case is one tenth in order to obtain the UCL of the 1st interval.
for some who doesn't get what the '# of classes' - the formula is k = 1 + (3.322 [Log(n)]) And for some, you need to know that the CLASS WIDTHs' formula is C = R/k where R = Max - Min divided by the k = k = 1 + 3.322 Log(n) Also, I would like to add in order to organize for huge data sets you can use the STEM & LEAF method, it's very easy and helpful when you utilize it for these ungrouped data
I think it's because if you look at all the numbers at the bottom of the polygraph they each have a gap of 11 so how she got the 39 was she did 50-11= 39 and the for 105 she added 94+11 to get that. Hopefully that helps :)
At the beginning, she got the class limits be adding and subtracting 11. And in frequency polygon, after drawing your graph, you make sure you draw a line back to touch the x-axis at beginning and end of the graph at an equal distance.
1:From the table, we know class midpoints are 50,61,72,83,94, which are also x coordinates for the polygon chart. 2:You may find out the gap between two consecutive midpoints is always 11; for example, 61-50=11, 72-61=11. 3: Therefore, we can conclude that the point before 50 is 39 ( 50-11=39).
The number of classes is determined by each question. This example demonstrates with 5-classes. But you can apply this for other number of classes, such as 6-classes, 7-classes, so on.
For Class Width, round up the dividend to the next whole number. If your dividend is 2(whole number), 2.1, 2.2, 2.3, 2.4, 2.5... 2.9, round it up to 3.
I dont remember how many times I refer back to this video. so helpful to me. thanks .
I'm glad it helped
Thanks I am Moses 💕🥰
Me, who was confused about an exam, which I will be taking next week,and God gracious, I discovered that video, and it really helpful and beyond ❤
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Thank you instructor. I love your pace and explanations as to which parameters to use for which graphical representation
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She really made me understand and learn new things about frequency
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thank you. this video is really help. i love how patient and clear you make sure to be in every step
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Thnku mam .. today is my exam really helpful .. God bless u mam...
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Wow! You've solved my problem with grouped data. God bless you
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Thank you Miss! That is very helpful, I ve been struggling with an exercise for days now I got some clue to solve it because of your explication.
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You are the best dear
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Thanx very much for this resourceful illustration, it really summarized everything for me on frequency distribution....
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This really helps me today in my exam God bless you.
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Thank you so much miss you were of great help to me i needed help with ogive and frequency polygon.
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Thank you very much my sister ❤ you really help me😢 Tomorrow is my exam and you help me alot🎉....Anyways love from Fiji 🇫🇯.......Vinaka Vakalevu 🙏❤️🔥❤️🩹🙌🥹😘
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i love this breakdown it really helpful...thanks so much
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this video very very very helhpful to me
love you from Pakistan
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This is perfect teacher
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Thank you for well explained
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Thank you very much you have made me understand more about statistics
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You always subtract 1 from the value of the LCL of the 2nd interval to obtain the UCL of the first interval if the lowest place value of your data is 'ones' as it is here ... if the data looked like 4.1, 6.7, 9.2, 12.1 ... then you'd subtract the value of the lowest place value which in this case is one tenth in order to obtain the UCL of the 1st interval.
Thank you mam 👏 👏this makes me to understand the introduction of statistics
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Your explanation is very clear mam.Thank you soo much❤.
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thanks so much mam helped alot ,love from pakistan
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Thank you so much for your help!
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Thank you ❤
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for some who doesn't get what the '# of classes' - the formula is k = 1 + (3.322 [Log(n)])
And for some, you need to know that the CLASS WIDTHs' formula is C = R/k where R = Max - Min divided by the k = k = 1 + 3.322 Log(n)
Also, I would like to add in order to organize for huge data sets you can use the STEM & LEAF method, it's very easy and helpful when you utilize it for these ungrouped data
again Thanks my sister and more loves
from pakistan
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thank you so much teacher was a great explaination.
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Thanks Maam :)
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This was very helpful .
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Thank you ma'am
You saved me
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Thank you for sharing this, it helps a lot :)
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Thank you well explained
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Thanks
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Very helpful but I don’t understand where the 39 comes from ... the 39 before 50
thanks a lot mam.this is really helpful
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Thank u so much!For me,it really summarized everything about frequency distribution. And You speak very nicely 😍.
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Thanks for your help
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Is there a decimal version?
thank you so much it helps me a lot
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Why am I lost. Where did 39 and 105 come from in the polygraph
I think it's because if you look at all the numbers at the bottom of the polygraph they each have a gap of 11 so how she got the 39 was she did 50-11= 39 and the for 105 she added 94+11 to get that. Hopefully that helps :)
@@itsmee1817thank you❤😊
Do i have to round for the class midpoint?
She is amazing!
Thank you! :)
thank you...its so good
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great walkthrough, thanks
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Thank you, very much 🙏
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This is very informative.
Thank you!
Thank you so much,
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Wonderful it is easy to understand
Thank you!
Ok teacher What is reduce formula class boundary
Also where does the 105 come from
so so so helpfull thanks all
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Impressive ma'am🥰
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eaisly defined
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Excellent
Thank you! Cheers!
thank u so much mam
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Thank you
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when I'm trying to find mid point on my own by adding lower limit 45 to upper limit 55 then dividing with 2 it's giving me 72.5
Can u plz tell me why?
You did 45 + 55/2 = 72.5. The correct way is 45 + 55 = 100, then 100/2 = 50. Or (45+55)/2 = 50. Thanks! - Prof. Xin from HelpYourMath
@@helpyourmathstat ohhh thnks I got it 😌❤️
What do I use if the number of class is not given.
Please someone should give me an answer
really i get all
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During Frequency polygon at the end where we took 39 and 105 ?
At the beginning, she got the class limits be adding and subtracting 11. And in frequency polygon, after drawing your graph, you make sure you draw a line back to touch the x-axis at beginning and end of the graph at an equal distance.
Thank You Ma'am
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Thanks you
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where did you get 39 for the polygon chart ?
1:From the table, we know class midpoints are 50,61,72,83,94, which are also x coordinates for the polygon chart.
2:You may find out the gap between two consecutive midpoints is always 11; for example, 61-50=11, 72-61=11.
3: Therefore, we can conclude that the point before 50 is 39 ( 50-11=39).
@@文军哲 oh my thank you so much for this as i have the same question.
@@wegotthis2345 You are welcome!!! I am glad my comment helped u.
@@wegotthis2345 You are very welcome!!! As a volunteer of helpyourmath, I am happy to help.
Tnx nice lecture mam
Where are you from?
Guess?
@@helpyourmathstat Cant determine from the accent😅 Maybe Philippines or Indo!!😌
@@beerviewmirrors4059 Chinese!
Why did she round the 10 to 11? Rounding is usually done to get a whole number. I am confused.
Please watch this video: th-cam.com/video/V-LHn7jPczs/w-d-xo.html
That's the rule... You round off wether it a whole number or decimal
It's because you always have to find the ceiling of a number in statistics, so you round up. Ceiling means to round up
😀ammizing teacher
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thank you!
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Please how did you get 39 and 105 on the frequency polygon, treat as urgent i have a test tomorrow by 9am😩😩
???
i miss physical class :((( this video help me so much
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Amazing
Thank you！
i think you have made mistake you are not supposed to ad the no. of class but the class width on thye class limit
Please watch this video, th-cam.com/video/V-LHn7jPczs/w-d-xo.html
Is it always 5 classes even if they didn't give you?
The number of classes is determined by each question. This example demonstrates with 5-classes. But you can apply this for other number of classes, such as 6-classes, 7-classes, so on.
is 10 not a whole number? why do you have to round up to 11?
Please watch this video: th-cam.com/video/V-LHn7jPczs/w-d-xo.html
1:05
10 is a whole number already. Why take it to 11?
I thought you only applied that rule when you have a decimal value🤔
Exactly my thought too
Why10 change to 11?
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hi
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Why did you add class width 10 +1 =11
For Class Width, round up the dividend to the next whole number. If your dividend is 2(whole number), 2.1, 2.2, 2.3, 2.4, 2.5... 2.9, round it up to 3.
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10 is already a whole number and why did you add 1 to make it 11..
Yabona istb
But i think you can leave it as 10 and you won't be punished.
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marry me shawty
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