Lesson 2.1 Frequency Table, Tally, Midpoint, Relative Frequency and Cumulative Frequency
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- เผยแพร่เมื่อ 8 ก.ย. 2019
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Dr. Jae Ki Lee
its crazy how you managed to save our asses from failing in 10 minutes im gonna cry thank youuuuuuuuuuu
I am glad to see it helped you!! ^_^
Thank you so much! I was struggling trying to comprehend until I came across your video. You explained this so well.
Thank you! I am glad it helped!
Thank you so much, I’ve been searching for the right video and yours is perfect 👍
you have to use this formula in order to get number of classes, Number of class / k / = 1+3.332log of n, n means number of observation Then k = 1+3.332 log 50 , log50= 1.698 .Therefore, k= 1+3.332 x 1.698= 1+5.65 = 6.65. Finally, round this decimal number which gives us 7. So, number of class is 7
Thanks it saved me
This formula is failed in some places
Thank you! I perfected my quiz because of your lecture!
You are very welcome!
btw, kumain naba sila?
Thanks man this was a big help
Your video made my life easier, thanks!
You are welcome, please check our free website too, helpyourmath.com/150.5/mat150
Thank you man , you’re a life saver .
Happy to help
Very helpful! Thank you so much!
Glad it was helpful!
Thanks
You are welcome! Please check our free website, helpyourmath.com/150.5/mat150
I love you sir...
Perfect way of explaining
Glad you liked it
Thank You So Much
You are welcome! Please check our free statistics course, helpyourmath.com/150.5/mat150
great . I also appreciate you
You are welcome!
where does the 50 under the frequency column comefrom?
loved the video :)
☝️
add all frequency =50
Thank you
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Yessss thankyou so simple quick and easy keep teaching ⭐️🫶
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Well done it's very informative video ap ne jo sikhaya us se bhot help mili, me b statistics ki classes Leta ho online
I had another question for the classes on the last part how did you find the high number. I did not understand that part.
I will help u the last part frequency 4+ 8 =12 in cumulative frequency 4+8+14=26 4+8+14+8=34
I want to know how did you got the number of classes (7) please 🙏
Thanks so much! This helped alot
Glad it helped!
Thank you Man!
You are welcome!
Thank you so much!!!
You are welcome!
Thanks you so much sir!
You are welcome! Please visit our Free Statistics Class Website, helpyourmath.com/150.5/mat150
Thank you this video helps
You are welcome! :)
very helpful thank you sir
Happy to help
Thank you it's very helpful
Glad it was helpful!
very good! thank you
You are welcome!
Thank you Sir,
You are very welcome!
hi what if your numbers at the classes part are single values, how do you find the midpoint please
Then you can use a weight mean distribution. It means you organize each value with its frequency. In this case, you do not need to find a midpoint.
Thank you!!
You are welcome. Please check our new website: www.helpyourmath.com/freecourses/
Thanks very much🙏
You are welcome!
Omooo!!💜thank you so much😇
Wait am I the one here feel confused about the man speaking having a Korean accent of English??😁anyways good job really a life saver😇
Yes 😁
Thanks teacher, you really helped Thank you so much I am from Somalia🇸🇴 and I greet you with the most honor
You are welcome!
Thanks alot😊
Most welcome 😊
THANK YOU SO MUCH!!! I'm just a little curious I'm not trying or intending on making fun but how many of you think his voice sounds like Kim Taehyung from BTS? (again I'm not trying to sound rude, I'm just curious)
It really sounds like taehyung! his voice is amazing!
I noticed it too😇😁😁
tnx a lot!
You are welcome!
How about the number of classes, where did you get it Sir?
It's either given or you can decide.
Thank u its a big help 😍😍
You are very welcome!
How do we figure out that how many classes do we have to make if it's not mentioned in our question?
Please contact your teacher. You may need to set your own classes (5 to 20 classes, depending on your data set).
For the midpoint part you said the way you get the answer is you did 4+15 divided by 2 and when I insert that in the calculator it gives me 11.5 not 9.5.
Am I missing a step?
Please watch this video: th-cam.com/video/NxmgnmH2MYM/w-d-xo.html
I wonder how he counted by 12, some of people counted by 5 only how come he used highest number in Classes,plz someone explain ?🤧
Thanks bro 👏
Welcome 👍
Omg thank you so much
You're welcome!
How did you get that numbers on the top, my teacher only shown us class interval and frequency. Help!
It is from given data.
What a explain and magic😍❤
Thank you! Please visit our free website, helpyourmath.com/150.5/mat150
Can a class midpoint be a decimal or whole number or both?
both
thanks man
You are welcome, please check our new free course, www.helpyourmath.com/freecourses/
thanks for your help
You are welcome!
one question, when your figuring out the last class do you add 12 or 11 to 76? You said add 12 to 76 but instead you added 11. Please explain.
@@footz975 Let's count our fingers from 1 to 10. There are TEN fingers, but 1 + 10 = 11. We need to count the number 76, therefore, we add 11 to count 11 more numbers. There are a total of 12 numbers. Enjoy the holidays! - Prof. Xin
@@helpyourmathstat thank you so much, you too.
good job despite the pronunciation! thank you, sir!
how does this work? Midpoint column you said 4+15 / 2 = 11.5 (not 9.5 as you have ) ?
(4 + 15) / 2 = 19/2 = 9.5, thanks!
thank you soo much sir👍👍👍
You are very welcome! 😃
Vry helpful👏👏
How do you round off 6.35 to the whole number?
Depending on the course
Statistics -7
Mathematics -6
❤
thankyou your teaching made me pass my exam lol
WoW, You are very welcome! Please check our free website, helpyourmath.com/150.5/mat150 We hope you get an A for your class!
Thank you very muchhhhh
You are welcome! Please check our Free Website: helpyourmath.com/150.5/mat150
How did u get the number of classes
Either given or you decide
how we can calculate 1+3.322log of n?
That’s the formula for getting the CI the n in the formula means count all the numbers giving together which is 50 . Put this 50 where the n is and look for the LOG of 50
E.g
1+3.322(log50)
1+3.322(1.698)
6.64 round it up
7,,
Where did u get the 50?
That's the number of data
Here how to find tally l donot understand
❤❤❤❤❤
You are very welcome! 😃
how is the min 4 how do it look like 4 anybody help
Among the data, 4 is the smallest data, so it is the min data.
Hello how did you get 15?
The second-class lower limit is 16. So, the first-class upper limit must be 15 so that no confliction for data
very good and helpfu
l video
You are welcome!
wow Iam the statistics of student
why is the number of classes not 6?
The question is asking for 7 classes.
Off topic but can i ask why does your accent sound like Korean English accent ? Or just mind is still in SK.....
Hi, are you studying in the U.S?
@@helpyourmathstat No , India .
Are u from south Korea
Yes!
why your counting 12 ?
classes:
4-15
I thought we count by 5 only ?
It depend on the number of classes you need. Not always 5.
By any chance, are you a Korean?
Dr. Jae Ki Lee is from Korea. Thanks!
While calculating midpoint why aren't you are using class boundaries
Shouldn't it be the same? You get the same midpoints?
@@helpyourmathstat yeah we get the same but we were taught to do it with class boundaries.
@@vishalacharya5683 Follow your instructor. Please know that we can find midpoints without knowing the boundaries. Thanks! :)
I got one question why u have divided 7 its a stable nubmber to find out intervals i just confused? Thanks for replying i really wants to know that
It's just an example. Dr. Jae Ki Lee chose 7. You can choose any number from 5 to 20 (Suggested). However, homework problems may give you the number. Thanks!
Apprecaite it but donot u think it might it effects my intervals example u have chosen 7 but if i choose 9? Thank u for replying
@@imanomar1862 The intervals won't be the same. Therefore, instructors normally give the number, then all students will have the same answers.
Thank u so much
you have to use this formula in order to get number of classes, Number of class / k / = 1+3.332log of n, n means number of observation Then k = 1+3.332 log 50 , log50= 1.698 .Therefore, k= 1+3.332 x 1.698= 1+5.65 = 6.65. Finally, round this decimal number which gives us 7. So, number of class is 7
Thanks
You are very welcome!
❤
Thank you!
But, why did you uses 7, as a number of classes 🤔? Did you just selected any random number?