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Should the 2/4 not be 3/4 in the second part of the equation as are they not independent. Ie 2 different scenarios that we are adding as possible probabilities? at 21 min 31 sec
Please check the second Trial 2 on the left. 2 Red and 2 Black, hence 2/4. Hope it helps.
@@prosmartanalytics thanks man makes sense :)
Should the 2/4 not be 3/4 in the second part of the equation as are they not independent. Ie 2 different scenarios that we are adding as possible probabilities? at 21 min 31 sec
Please check the second Trial 2 on the left. 2 Red and 2 Black, hence 2/4. Hope it helps.
@@prosmartanalytics thanks man makes sense :)