Mr Six Sigma.. Thank You. I am a male person, 81 yrs, and living in Holland. Your guidance in Bayes Theorem was astonishing clear and helpful. Hats off for your channel and expertise !!! Have a nice day
@@sarcasticboy4507 Good afternoon.. I Rest..when I finish my Golfgame (Play HC 4)..or after My Tennis-game with the buddies..and then enjoy the "talks" afterwards. These buddies are still very challenging. so with Bayes I remain "sharp" sometimes. Enjoy your life..!
Very well explained, I was going mad trying to understand this, finally I get it clear in my head after watching this video. Thank you Six Sigma and ofcourse TH-cam platform
Thank you for your immediate response. Let me be more specific with my question. QN:: A bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn from the bag which is found to be red. Find the probability that the ball is drawn from the first bag. How this trick can be applied to solve this problem?
@@LathaLatha-bo3kl 0.5*(4/8) red ball from first bag where 0.5 is prior and 4/8 is the event of choosing a red ball given it is bag1. Likewise, for the second bag 0.5*(2/8). Question is p(First bag|Red) which is 0.5*(4/8)/[0.5*(4/8) + 0.5*(2/8)]. In the table we can replace 0.5 with any value say 'n' but if bags have equal chance of being selected then this value will be one and the same for both the bags. Once the bag is chosen, we look for occurrence of a specific event of interest, you can calculate that number by multiplying n with 4/8 for bag1 and multiplying n with 2/8 for the second bag. Now, add these two and you find the total number of red balls. The question is asking the prob of Bag1 given the ball is Red so n*(4/8)/[n*(4/8) +n*(2/8)]. If the chances were unequal say 70% chance of choosing bag1 and 30% chance of choosing bag2, you would have done 7n*(4/8)/[7n*(4/8) +3n*(2/8)]
Thx for your explanations it was quite clear about both the topics conditional and bayes, however I am confused where I can apply the bases theorem and I should use the conditional probability
To calculate the shortcut form, problem-1: how take you total products is 700? And also in problem-2: how take you total vehicles is 1000? If I take a random value, I can't get the exact answer.
Give it more time to understand it from the beginning. Try to do it yourself. You'll always get the same answer (as in probability) because the assumed values of totals no matter what you take will get cancelled while calculating the probability as it participates both in numerator and denominator.
![ทุกครั้งที่หลับตา (Lucid Dream) - AYLA's [ Official MV ]](http://i.ytimg.com/vi/4i1OBAQyv58/mqdefault.jpg)
Mr Six Sigma.. Thank You.
I am a male person, 81 yrs, and living in Holland.
Your guidance in Bayes Theorem was astonishing clear and helpful.
Hats off for your channel and expertise !!!
Have a nice day
Glad you liked our content. You too have a blessed day.
what are you doing with baye's theorem in 80s? isn't time to rest and see the life?💞geniunely interested what do you do
Why do you want Bayes theorem in your 80s?
@@sarcasticboy4507 Good afternoon..
I Rest..when I finish my Golfgame (Play HC 4)..or after My Tennis-game with the buddies..and then enjoy the "talks" afterwards.
These buddies are still very challenging.
so with Bayes I remain "sharp" sometimes.
Enjoy your life..!
By far, the best explanation of Bayes Theorem. Thank you, sir.
great video, explained 10x better than my lecturer
I hope our respected school teachers look at this video and understand how to teach a complex topic so easily. Thank you for this video!!
Very well explained, I was going mad trying to understand this, finally I get it clear in my head after watching this video. Thank you Six Sigma and ofcourse TH-cam platform
Glad it helped!
Excellent !! the best one on Bayes theorem I have watched/read so far . Thank you :)
you said no need to watch any other video and you were right !! 🔥🔥🔥🔥🔥🔥A gem video for baye's theorem
great explanation. Like u mentioned in the video, u covered the topic 100% and people do not need any other resource.
Thank you for the appreciation. Means a lot to us.
awesome.as you said no other reference is required.please keep up your great content.
Thank you! 😊
Thank you Sir. You are an awesome teacher. Wish I had such an excellent teacher like you during my school days. 👍❤️
Thankyou sir!
I was really confused in this concept...But now it is crystal clear
Bayes Theorem explained in a superb way. Thank you very much sir
This video was amazing, I used this on my exam yesterday and crushed it. I know this theorem inside out and backwards now ! Thank you so much
Awesome! Glad it helped 😊
Awesome! Glad it helped 😊
Thank you. I've been struggling to understand the root of Bayes' theory. It's very clear to me now
I have taken 3 stats classes and never really understood this till I watched the video. Thank you so much.
Glad you found it useful. 👍
By far the best explanation I have heard.
Thank you! Glad it helped.
Honestly struggled with this for so long 😭thank you so much for helping
Glad you found it useful.👍
The best video for bayes theorem
amazing video. very easy to understand. Thank you so much.
Thank you so much Sir
Honestly I don't need any other explanation howsoever about Baye's Theorem ❤
Thank you! 😊
Excellent video on the topic!!!!
Glad you liked it!
Hello sir i'm from ethiopia thank's alot for your explanation!!
Thank you! Glad you found it useful. 😊
Trick is verymuch useful. Can we apply the trick, for all the problems? For example, 2 bags, coloured balls problems, how can we apply the trick?
Hint: Think of bags as priors such as A and B, and the color of the ball as the event happening once the bag is chosen like Pass/Fail.
Thank you for your immediate response. Let me be more specific with my question.
QN:: A bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn from the bag which is found to be red. Find the probability that the ball is drawn from the first bag.
How this trick can be applied to solve this problem?
@@LathaLatha-bo3kl 0.5*(4/8) red ball from first bag where 0.5 is prior and 4/8 is the event of choosing a red ball given it is bag1. Likewise, for the second bag 0.5*(2/8). Question is p(First bag|Red) which is 0.5*(4/8)/[0.5*(4/8) + 0.5*(2/8)].
In the table we can replace 0.5 with any value say 'n' but if bags have equal chance of being selected then this value will be one and the same for both the bags. Once the bag is chosen, we look for occurrence of a specific event of interest, you can calculate that number by multiplying n with 4/8 for bag1 and multiplying n with 2/8 for the second bag. Now, add these two and you find the total number of red balls. The question is asking the prob of Bag1 given the ball is Red so n*(4/8)/[n*(4/8) +n*(2/8)].
If the chances were unequal say 70% chance of choosing bag1 and 30% chance of choosing bag2, you would have done 7n*(4/8)/[7n*(4/8) +3n*(2/8)]
Thank you so much
Thank you ..................🤩😍Simple and clear
thanks man so for the best explanation i have seen
thoroughly explained !!
Clearly explained, Thank you
Glad it helped 😊
subscribed! very good explanation!
Thank you! Glad it helped.
Excellent explanation
Thank you! Glad it helped.
Great explanation
Thank you! 😊
thank you mr six sigma tommorow is my exam iam going to pass becuase of you
All the best 👍
Thankks, great content
In problem 2nd,you put the value of 5% into decimal
0.5 but it will be 0.05 of 5%
Really! Thank you for watching our content so diligently. Feedback always helps.
Useful❤
Thank you!
thank you for this sharing
Best one ...
thanx for explanation it's very helpful ❤❤😊😊
Glad it helped 😊
Thx for your explanations it was quite clear about both the topics conditional and bayes, however I am confused where I can apply the bases theorem and I should use the conditional probability
Bayes' Theorem is an extension of the conditional probability concept. You may need more practice, it would help.👍
This was so helpful thankss
To calculate the shortcut form, problem-1: how take you total products is 700?
And also in problem-2: how take you total vehicles is 1000?
If I take a random value, I can't get the exact answer.
Give it more time to understand it from the beginning. Try to do it yourself. You'll always get the same answer (as in probability) because the assumed values of totals no matter what you take will get cancelled while calculating the probability as it participates both in numerator and denominator.
Hi, I wonder if in the 3rd problem, False Negative is not mentioned, so in our calculations, we dont have to care about False Negative right?
Right, we need to formulate as per the specific problem statement.
this is awesome
Thank you so much sir
God bless you dawg
Excellent 🎉🎉❤
Thank you!
Excellent!
Thank you!
You fulfilled your promise
Always 😊
Slick and useful.
Thank you!
Thankyou
U re so good in accents of
Speaking English for Indian to enjoy
Pls share contact no
Excellent!