I solve all type of questions. We never skip "hard" questions. If you have any question in CSIR-NET papers which is not solved by me and it is hard for you then please mention the question number with year. I will try to solve those question.
@@SBTechMath Sir, I really like the way you teach. yes you do have covered hard questions , Can you make the same lecture series based on hard PYQ of real analysis and also include those which can feel tricky while facing them in the exam??
@'1:31:59 ' sir V can never bhi written as union of two proper ko kevel {0} and W( proper) se union se kaise keh rahe ....this two proper can be different from {0} subspace ... Please expain🙏
Take different dimensions and then consider 2 proper subspaces in which one is fix {0} zero-subspace and other is non-zero. Then you will get the answer.
Sir, union of subspaces is subspace if one is contained in another. But we are writing in last question V to be union of proper subspaces. Where am I making mistake 😶
Bhai, thoda piche karke dekho..agar Aw=0 hogeya to w€ker{A} hoga. Aur karnal mein ek vector aa geya matlab uska rank 2 se kam hoga (kyunki A 2x2 ka matix hai). Aur rank 2 se kam hai matlab det(A)=0 hoga. Aur det(A)=0 hai to 0 ek eigenvalue nehin ho sakta
Best Teacher 🙏🙏
बहुत अच्छा था sir ji
Thank u sir...❤
Nice teaching 😊😊
Adbhoot ❤️
Nice questions but I want hard ones...
Can please make a video on hard qhestions.
Also, we need this type of lecture series on hard questions
I solve all type of questions. We never skip "hard" questions. If you have any question in CSIR-NET papers which is not solved by me and it is hard for you then please mention the question number with year. I will try to solve those question.
@@SBTechMath Sir, I really like the way you teach. yes you do have covered hard questions , Can you make the same lecture series based on hard PYQ of real analysis and also include those which can feel tricky while facing them in the exam??
1:10:08 sir isme agar matrix indefinite ho gaya tab invertible nehi hogi na
[1, 0; 0, -1] is indefinite and invertible. So invertibility and indefinite have no relation
@sab tech sir , mujhe Q2 ka first option kaisse correct hua nhi smmjha
Please watch again and check this statement is marked as correct or incorrect. I discuss all the options very clearly. And option a is false.
❤❤
Sir apne question 4 mein minimal polynomial ki power gm se kyu compare ki ?.
Minimal polynomial se size pata chalta hai and wahan se possible number and size of Jordan Block ka pata chal jaata hai
@'1:31:59 ' sir V can never bhi written as union of two proper ko kevel {0} and W( proper) se union se kaise keh rahe ....this two proper can be different from {0} subspace ... Please expain🙏
Take different dimensions and then consider 2 proper subspaces in which one is fix {0} zero-subspace and other is non-zero. Then you will get the answer.
Sir {0} ko fix kyun kr rahe yahan toh any two proper bola h n
Sir, union of subspaces is subspace if one is contained in another. But we are writing in last question V to be union of proper subspaces. Where am I making mistake 😶
@@PragatiiThisSIDE reason is finite field.
Sir esme first option me three dimensional le to
@@accountstaxdigitalsolution4907 try kriye
@41:15 'A cannot have 0 eigenvalue', woh samajh nahi aaya acche se.
Bhai, thoda piche karke dekho..agar Aw=0 hogeya to w€ker{A} hoga. Aur karnal mein ek vector aa geya matlab uska rank 2 se kam hoga (kyunki A 2x2 ka matix hai). Aur rank 2 se kam hai matlab det(A)=0 hoga. Aur det(A)=0 hai to 0 ek eigenvalue nehin ho sakta