Tension force in strings (Easy method + Numerical) - two mass in an elevator | Newton's laws
ฝัง
- เผยแพร่เมื่อ 28 พ.ย. 2017
- Without using any tension formula, we will learn how to calculate the tension in a string using Newton's laws of motion. We will also solve problems elevator problems in finding tension in strings in two masses hanging.
You sound like Chatur Ramlingan 😂 thanks tho
OMG! That's so like him!Nice observation
Wohi comments karne aya tha
Dil ki baat cheen li😂😂
Oh wow kya observation ha bro....😁😁😁
OMG I JUST REALIZED THAT BAHAHAHHAHAHAHAH
ily, without you i cant got off with my doubts.
at first i was wonderring why a body has two tension forces, but now i cam to know there is an tension forces by the body to the string and other by the string to the body
Absolutely! Glad that it helped!
Thank you, very clear.
Thank you, it was well explained :)
That's what I was looking for. Thanks...
Same !
Hello i wanted to ask a question, is there a way where i can send the question to you, it's okay if you dont want to
Thank you, super useful information)
Thanks BRO for this video:)
Thankyou sir...can u give me clarification on why its not (m1+m2) g down there....that Fake contradiction always 😢 makes me underconfident to solve que.
Thanks really !
At 7:07...sir i didnt understand..why u added g and 9/2...plz reply sir🙏🙏🙏🙏
At 7:00, why did you not also write the tension force acting downwards from the ceiling? Just prior to that, you explained how the tension force from the ceiling can result in the ceiling collapsing if the ceiling is not strong enough (in extreme cases of course) but then you never wrote down this force so it seems contradictory and confusing. You wrote all the other up & down tension forces so why are you "allowed" to not include this one? This just makes it more confusing. How come 1 of the 4 tension forces does not have to be taken into account?
Dude-
This was the exact same question I asked my physics teacher, i was like "why do we only include the forces acting on the block in an fbd and not the ones the block applies in the opposite directions and then make equations out of them? " He didn't even have a reasonable answer and then when I tried asking one more time, he just got mad at me. I still don't have the answer. But hey, it's been a year since u commented so did u get the answer?
@@ibetudkmahnameb4114 There is a downward tension force acting on the ceiling, but ceiling is NOT my object of interest. Since my objects of interests are the two masses, we only consider the forces acting on them.
But, if we considered the ceiling as the object of interest, then we could consider the T2 tension force acting downward!
@@ibetudkmahnameb4114 Allah be merciful on your idiotic brain! You have to first define which system you are considering forces and draw the FBD FOR THAT SYSTEM and then draw forces on THAT SYSTEM. Allah be merciful on this idiot.
Whats the formula for tension if the rope has a mass?
there’s no specific formula for tension; you’re meant to find it by looking at your diagram.
sir, if we are drawing a freebody diagram for a body with mass m1, then which tension do we need to consider (tension by body to string) or (tension by string to body) ?
Since we are interested in the 'body' and not the string, which one do you think it is?
@@Mahesh_Shenoy body to string am I right?
@@arulvel96 If you consider the tension force applied BY the body TO the string, we are making string as our object of interest, right?
@@Mahesh_Shenoy oh ok i got it, if we take the tension of body to string then it means the force by body to string (force on string).
so we need to calculate all forces on body which means i have to take force exerted by the string to the body
But why do we put the g\2
This was so good
Thank you so much sir , you are a great person
Gee, thanks!
op bro love from india
Thx bro
sir, can we also say that the direction of tension is same as the direction of pulling
Yes!
Music in background?
Thankyou:)
What if it is downward? Will it still be +g/2?
if the elevator is going downwards, it will be -g/2 i believe
@@timnoskill yes
why is g+g/2 instead of g-g/2? They are in oppo direction aren’t they?
Shouldn't the tension forces in each part of the string cancel out since each part experienced tension both upwards and downwards, and thus the resultant tension on the string should be zero?
They do cancel out. That's why the string pieces feel no net force and, hence, no net acceleration!
The forces are balanced.
And the magnitude of one of these forces is what we call tension!
@@Mahesh_Shenoy So why do we say that the tension is T throughout the string? Shouldn't we talk in terms of the net force on the string?
@@anjaligarg8709 since we consider massless strings, the net force on it is always zero :)
Yet, the string will exert pulling forces on its ends, right? So, I think that's what we try to communicate!
@@Mahesh_Shenoy So if I have two blocks tied by a string such that the string is not lying loose between them, I say there is a tension T throughout the string. By saying so, I am emphasizing the fact that the string is pulling both the blocks with a force equal to T, and not that the net force experienced by the string is T, am I right?
@@anjaligarg8709 Yes, absolutely!
Even though the block and the string are accelerating, the net force on the string is zero! Because of its zero mass!
You are amazing
Aren't you the Khan Academy guy? And I don't mean Sal Khan but the Indian teacher who teaches physics and chemistry Indian syllabus
Yes, I am the non Sal, Khan Academy guy.
@@Mahesh_Shenoy You are amazing, sir. Your videos are of extreme help and importance to me..
Chatur Ramlingam is on fire🔥
😂
Thank you..
1:57 he flipped us all
Pls why you add g/2
It is the acceleration of the elevator. You should think that the elevator goes upwards with acceleration g/2
Thanks
Msttt
why is t1 not pointing downwards too?
Because it is the opposite force of that block's weight (mg)
Why wouldn't the force be the same throughout the string if it had mass?
The pieces of string on the top would have to carry the weight of the entire piece of string below it!
nice
I'm seeing 2 hours before test... 😂
Sir please help
u sound exactly like the guy from khan academy
he is
Ilove my india
I also