Tension Force Physics Problems
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- เผยแพร่เมื่อ 18 ก.พ. 2021
- This physics video tutorial explains how to solve tension force problems. It explains how to calculate the tension force in a rope for a object descending with a downward acceleration using newton's laws of motion. it also discusses how to use free body diagrams and the weight force to calculate the tension force in two ropes at different angles. There's another tension force physics problem that asks you to calculate the tension in two cables / ropes where one rope is in the horizontal direction and the second rope is at an angle.
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Is it okay for you to add the full video here too for those who have TH-cam membership?
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At least for me, it's all in being able to replay the video and go back if you didn't understand the first time.
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Thanks a lot man you are a saviour. I was literally finding this topic difficult to comprehend but after watching this video it became so easy to solve tension problem.
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What the heck. I was literally going to search up this practice problem and then I see that you uploaded it 2 hours ago...H-how did you know that I needed this exact video? LOL, even the question I got wrong (which is why I'm searching it up) is almost identical to JG's first question. xD
Finally I found a video on force tension. Thanks!
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Fr
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thanks for this video! I usually see the video that's made by you and I benefit from it. In this video I stopped worrying about tension problem because of you. thank you so much once again my teacher.
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Thank you once again for another excellent video on Tension Force in Physics.
Really appreciate the thoroughness:>
In my school they just taught me the formula of tension force which is T = M(g+a) but they never taught me how it was interacting with y axis.. and like Sum-of-F(y) or those. Actually formula just enables us to do maths tht are capable of solving with just that formula. If u know one formula then you can do just one type of math. But we need to learn the root of it. The basis of it. Thanks to your teaching I can understand formulas better and I dont have waste my energy in memorizing them. I can just create my own favourable formula if I have to. Thanks a lot. You deserve a lot more recognition.
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This video just simplified this a whole bunch for me !!
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closer to the end, with the last free body diagram, that made a lot of sense how it works since you lose the track when working with equations and numbers and taking a look at the picture helps a lot to clarify whats going on
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I am literally in 11th grade and this is in my math textbook. thx man.
9.8 is a downward acceleration so it must be -9.8 and because of this we calculate 2.3 - 9.8 which is equal to 5.5 and then multiply it by 50 and that is equal to 275
yes i was thinking that too. It confused me to get 275 for the tension because then the box would not be lifted. I don't understand why he added the accelerations together for 1a and then subtracted the accelerations for 1b if both the accelerations in b are going in the same direction ?
The acceleration is 9.8 due to gravity. Upward acceleration will be -9.8 because it is going against the gravity.
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at 2:24 , shouldn't we use -9.8 as acceleration because gravity acts downwards and we are taking the upwards direction as positive?
Late answer, but here's the explanation:
It's because on 0:57 he set the sum of the forces to be ΣF = T - W, so he already put the minus sign here on the weight force where gravity is. You could set it to be ΣF = T + W, so it would be ΣF = T + (50 * (-9.8))N, as adding a negative number is the same as subtracting, the result would be the same.
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Can you do a video on Jointed Rods and its related equilibrium? , thanks
Hi, i genuinely am lost. If the accelerations are in different directions, aren't we supposed to subtract and if in the same direction, add?(first example)
Chai
yeah if you use gravity which goes down as a positive vector then he should have done 9.8-2.3 in the first example
In the first problem, wouldn't gravity be negative here since you used up as positive and down as negative?
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equilibrium, find the tensions T,, T2, and T, in the ropes.
the ropes make angles unknown with the horizontal. If the system is in
A bag of cement of weight 300 N hangs from three ropes as shown in the figure below.