How can I estimate the concentration of substance A and substance B in the mixture when the info given: absorbance at the same 2 wavelengths for and B, A concentration and B concentration are the same, absorbance of mixture?? It was on paper based exam, no access to excel whatsoever xx
@@Double0piI have tried to follow the steps and I am not sure where do I make mistake, my concentrations come up negative 😭. Absorbance at 238nm- Phenobarbital 0.551, Oxycodone 0.477, Unknown 0.652 At 280nm- Phenobarbital 0.07, Oxycodone 0.05, Unknown 0.493. Both samples Phenobarbital and Oxycodone are at 5.20x10^-5 M concentration. The molar abs that I calculated ( molar abs= A/C ) are at 280nm- Phenobarbital 1346, Oxycodone 962. At 238nm- Phenobarbital 10596, Oxycodone 9173. step 1 result: 0.652-9173 Coxycodone/ 10596= Cpheno step 2) 0.493= 1346 (0.652- 9173 Coxy/ 10596) + 962 Coxy Step 3) 0.493= 0.0828- 1165 Coxy + 962 Coxy 0.4102= -203 Coxy Coxy= -0.002 Step 4) 0.652- 9173 (-0.002)/ 10596= Cpheno Cpheno= -17.694/ 10596= -0.00167 😭😭😭
It's just an example. You can do this for literally any set of two wavelengths. Heck, you can do it for three if you are willing to wrestle with the math.
Thank you so much!!! This helped me to make my lab report!
Always glad to help!
So helpful thank you and very easy to understand
This video was awesome. You saved me!
Amazing explanation
Very impressive explanation..Thanks from India
Glad I could help!
what is the method's name, and how can I reference it?
How did you get the absorbance to be A= 0.72 and B=0.77?
You get those from measuring the sample under the UV spectrophotometer
@@aishaomar11 Exactly.
How can I estimate the concentration of substance A and substance B in the mixture when the info given: absorbance at the same 2 wavelengths for and B, A concentration and B concentration are the same, absorbance of mixture?? It was on paper based exam, no access to excel whatsoever xx
The video literally walks you through how to do this
@@Double0piI have tried to follow the steps and I am not sure where do I make mistake, my concentrations come up negative 😭.
Absorbance at 238nm- Phenobarbital 0.551, Oxycodone 0.477, Unknown 0.652
At 280nm- Phenobarbital 0.07, Oxycodone 0.05, Unknown 0.493.
Both samples Phenobarbital and Oxycodone are at 5.20x10^-5 M concentration.
The molar abs that I calculated ( molar abs= A/C ) are at 280nm- Phenobarbital 1346, Oxycodone 962. At 238nm- Phenobarbital 10596, Oxycodone 9173.
step 1 result: 0.652-9173 Coxycodone/ 10596= Cpheno
step 2) 0.493= 1346 (0.652- 9173 Coxy/ 10596) + 962 Coxy
Step 3)
0.493= 0.0828- 1165 Coxy + 962 Coxy
0.4102= -203 Coxy
Coxy= -0.002
Step 4) 0.652- 9173 (-0.002)/ 10596= Cpheno
Cpheno= -17.694/ 10596= -0.00167
😭😭😭
very helpful, thanks.😊
Why did you pick 550 nm
It's just an example. You can do this for literally any set of two wavelengths. Heck, you can do it for three if you are willing to wrestle with the math.
@@Double0pi Thank you! You have (hopefully) saved my lab report. Idk if I did it right but I trust your lesson 😭😭
You saved my ass I can't thank you enough
Glad to help.
Amazing explanation