An Olympiad Exponential Equation: Find X

[@jimohibrahim2089]

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[@Alamaths]

Thank you so much. Are you a maths teacher ?

[@MathMasteryMinds]

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[@Alamaths]

Thank you so much.

[@AdegbeyeArafatOluwaseun]

Excellent 🎉

[@Alamaths]

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[@Alamaths]

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[@JPTaquari]

Easy,
5^X * ( 1 + 1 ) 150
5^X ( 2 ) = 150
5^X = 2,68261 ( by log )
Bingo from Brasil !

[@Alamaths]

Wow 😮 , thank you so much. Are you a professor of maths?

[@ronaldnoll3247]

Correct calculation, but much too complicated... but it works like this too... with the approach
5^x =75;
x=LOG(5) 75;
x= 2.6826

[@Alamaths]

Wow 😮, thank you so much. Are you a professor of maths?

[@walterwen2975]

5^x = 75 = (25)(3), 5^(x - 2) = 3, x = 2 + log3/log5 = 2.683

[@Alamaths]

Thank you so much. Are you a professor of maths?

[@walterwen2975]

@@Alamaths
No, my major is physical chemistry. Math is my fun.

[@Victurf]

75 = 5 ^2.6826

[@Alamaths]

Wow, thank you so much. Are you a professor of maths?

[@Victurf]

@@Alamaths Statistical Engineer

[@hongphuc9286]

*x=log5(3)+2*

[@Alamaths]

Wow 😮, thank you so much. Are you a maths teacher?

[@anestismoutafidis4575]

5^x+5^x=150 5^2+5^2=50
5^3+5^3=250 [150÷250=0,6];
2×(5^2+0,6)=131,3
2×5^2,683=150 x=2,683

[@Alamaths]

Thank you so much. Where are you watching from?