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This was obvious after the FIRST math sentence : k⁶ = 2⁶ !!!! Are you maths idiots ?!?

Eh???! It’s 2 or -2.

just waste the time and your brain

Formidable

Excellent problem

Вот нагородил. Все извилины заплел.

For k²-2k+4=0, it is faster to use the supplementary formula ak²-2b'k+c=0⇒k=[-b'±√{(b’)²-ac}]/a, and use k=[-(-1)±√{(-1)²-(1)(4)}]/1=1±√-3=1±√3i. If b is even (b=2b') and a is 1, not using this formula is a loss. The same applies to k²+2k+4=0 In addition, since complex solutions cannot be expressed on the real plane of the x-y axis, if we want to consider them graphically, we must use the complex plane (Gaussian plane).

This is ridiculous. +2,-2 stop and immediately

k=2×cos(n×pi/3)+2i×sin(n×pi/3), n=0, 1, ... , 5 So roots are ±2, -1±(sqrt3)i, 1±(sqrt3)i

1

The second method is just stupid

What rediculous overkill

I haven't the time but draw the graph of Y - 2 to power 6 and Y = k to power 6 Where they meet is the solution I think as someone said the answer is 2 or -2

I this applying log base 5 from the second step (step of Factorisation) will be faster to find the solution

√x=√3-√2 Sq.b/s (√x)^2= (√3-√2)^2 x= 3-2√3.√2+2 (a-b)^2 = a^2-2ab+b^2 x= 3-2√6+2 x= 5-2√6

a-2

؟؟؟؟؟؟؟!!

X doesn't have the value 5+2(6)^-2.... If you have doubt in this statement.... Substitute this valuve for x in the equation

It's wrong

5 und gut isses

Thats a lot of work when simple deduction tells us k= (2, -2) 🤔

A =3

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Nice video ❤🎉 a= 2⁴÷7

X=.101020516

А =логарифм 20 по основанию2

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Tomi নিজে ও বোজো এই

Tomi ki baler math করলা

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From 4 to the power of (x + 5) equal 11 to the same power, it follows that x + 5 = 0, so, x = -5.

5×5x5=125 That is: 5×5=25 25x5=125

infinity is not an nomber

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125

If u kust assign a = 3, then 5x5x5 + 5x5x5 = 150. Why do you have to make complicated tbink that result in some thing different.

Решаем методом устного счета. (a√a√a) ^4=2^4 a^(4+2+1)=2^4 а=2^(4/7) Good luck!

1

Meaningless question.x+1=x implies 1=0

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I had no idea how to solve that equation, but the way you used I consider a masterpiece.

10

X= -4 or X=10

8^×=6× 2^3×=2(3×) =>(1/2)=(2/4)2^3×=3× =>(-2)ln2.e^ln2(-2) =(-3×)ln2.e^ln2(-3×) On application of Lambert W-function =>W{(-2.ln2.e^ln2(-2)} =W{(-3×.ln2)(e^-3×)} =>-2.ln2=-3×.ln2 =>×=2/3* To check .(8)^2/3=4=6(2/3)..ok

darn 5 x 5 x 5=75 75+75 =150 totally confused my this guy

a = 2

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5^a(1+1)=100 5^a=100/2=50=5×10 log5^a=log5×10=log5+log10=log5+1 a=log5/log5+1/log5 a=1+1/log5

Nonsense