Hi, good job, but one query is there in linear equation y=mx+c, the intercept is C and slope is m. So in the pseudo-first-order reaction interscept=lnqe and slope will be equal to -K1, not K1T, I think so. thanks in advance.
Thank you very much for the wonderful explanation. However, if I am dealing with industrial wastewater treatment using batch adsorption and the concentration is constant in the wastewater, where I cannot perform 'the effect of different concentrations on water treatment, how can I get the value of qe?
Thanks for sharing the calculation step by step. I am just curious if the k1 would be positive in this case (k1= - slope/t)? What does it mean if I got a negative k1?
Sir you have done a great series of videos on kinetic models and adsorption isotherm. I request you to please find some time and do a video on Elovich kinetic model, and Lamgmuir-Freundlich adsorption isotherm.
Hi, could you perform data plot using pseudo-first order model? Preferably with the regression (linear), I would like to check how you find the values of qt, to perform the plotting of the graph with the experimental and theoretical data.
@@AsifResearchLab bro may I get your email or any other contact to learn in advance? I really need to fit my data into the nonlinear fitting asap for my paper needed as my graduation requirement... if you dont mind tho :)
Helpful video. I have one question. I have time 0 to 720 minute and qt for each (for 0 qt 0). for calculation which qe I should use? How I get qe form this data.
@@AsifResearchLab actually I used 720 min as equilibrium. so in kinetics study the time length is 0 to 720 min. The data says highest capacity found in 60 min. so I have to use qt at 60min as qe? If i subtract others below and upper from 60 min I will get positive and negative values but what about the qt at 60? if i subtract this result will be 0 and ln0 is indifinite. That is the confusion.
Hi, How did you calculate the other 4 from ln(qe-qt) when you got qe and 10 from qt? And my experiment has five concentrations and ten hours. How do you calculate this? I'm so confused... Please reply..
Can I draw only qt instead of ln(qe-qt) on the first pseudo graph? Also, can I use the values of intercept, slope, qe, and r2 of the graph drawn with qt? Please answer me..
good morning sir, sir I'm doing project on dye adsorption kinetics and isotherms I'm facing problems while applying values in the graph, need to submit my report by end of this month ... i need your help sir how could i contact you sir??
Why the Ce value is not included in the contact time experiment , , , as you have taken Ce as 14.6 but in your contact time experiment your Ce values are 14.7
Mujhe help chehiye. Kindly help me. Meri condition theek nahi hai. Job k liye bhi apply nahi karne de rahe hai gundee. Help chahiye. Snehlata katheria.
Türkiyeden yaızyorum videonuz çok faydalı oldu benim için fakat anlayamadığım bir yer var cevaplarsanız çok mutlu olurum. Ci değerini neden 50 mg/l sectiniz
Sir can you please do videos related kinetic fittings using BET CO2 adsorption .I have done my last paper work related to adsorption of lead with the help of your videos...kindly help me sir
Finally found very useful video. Thanks ! Keep doing and stay healthy 🙂
Thanks dear
can i know why for ln (qe-qt), you take the value of qe of 23.6?
Hi, good job, but one query is there in linear equation y=mx+c, the intercept is C and slope is m. So in the pseudo-first-order reaction interscept=lnqe and slope will be equal to -K1, not K1T, I think so. thanks in advance.
i have also same doubt. sir please give answer to these query
same doubt.
see dr amirul video, he use -k1/2.303 for log(qe-qt) vs t. but for ln (qe-qt) vs t he also use the same with this video@@nut-kutcracker7011
Can you please elaborate on how to calculate experimental and calculated value of qe ?
you really helped me thank you lots of time
Glad I could help!
Great job bro, really appreciated,,hope we get more
Thanks dear
you are doing a great job, sir keep uploading such helpful videos
Thanks
Excellent. Thank you so much, very trainer. It's very helpful for my diploma project.
Very elaborate
Thanks for sharing
Tnx dude, but you did a big mistake here. Solpe=k/t??? really? the slope is "k" itself, not "k/t".
yes
It seems to me that there is an error
Very Nice and adorable work. Dear please also go for non-linear fitting models. We want to learn about non-Lin models and equations.
Thanks. Yeah sure,
thanks bro, appreciate the good tips...🙌🙌👌👌
Welcome
Great and intresting job
Thank you very much
thank you very much for this, I just started a research grant this is great help.
Welcome
Fantastic teaching 😢😢😢😅😅😅 thanks teacher
Thank you! 😃
good explanation, thanks
Thank you Sir. It was really helpful
can i ask something? does the Qe value is gotten from different experiment? is it from equilibrium time experiment ?
Yeah you can ask any question. yeah qe is determine through different experiments at different initial conc of metal ions
@@AsifResearchLab what if you have only one experiment that was run for a long period. How would you calculate qe, it will become the same as qt ?
Thank you for this tutorial, it is a great job. Question, why choosing the value Ci=50mg/L?
see answer in lagmuir vedio comment sections . answered many times. thanks
When calculating Qe, I wonder which minute's value is the Ce value of 14.6? Do we always take Ce as 0.1 point less the maximum removal? thank you
Thank you very much for the wonderful explanation. However, if I am dealing with industrial wastewater treatment using batch adsorption and the concentration is constant in the wastewater, where I cannot perform 'the effect of different concentrations on water treatment, how can I get the value of qe?
Thanks for sharing the calculation step by step. I am just curious if the k1 would be positive in this case (k1= - slope/t)? What does it mean if I got a negative k1?
jamais ..car le temps varaible
Sir you have done a great series of videos on kinetic models and adsorption isotherm. I request you to please find some time and do a video on Elovich kinetic model, and Lamgmuir-Freundlich adsorption isotherm.
Langmuir and Freundlich available on channel
@@AsifResearchLab Sir i am talking about
Langmuir-Freundlich model. This one is different from Langmuir or Freundlich model.
Very soon, in sha Allah
@@AsifResearchLab jazakAllah
can we get a negative rate constant value even when the R2 is almost equal to 1 and following a specific model?
Thank you so much sir/madam
Please do vedios on Flory-Huggins and Dubinin kaganen radushkenich isotherm models
Thanks...dear v soon above mentioned videos will be available
@@AsifResearchLab thank you so much
Great job❤❤ thank u
Hi, could you perform data plot using pseudo-first order model? Preferably with the regression (linear), I would like to check how you find the values of qt, to perform the plotting of the graph with the experimental and theoretical data.
Ok
Sir, if qe-qt =0, then ln 0= undefined. Please, guide how to proceed with data then???
i also need answer to this question
@@noorulain2224 still i haven't get the answer
Bro really apreciate it! Can you do the non linear fitting too?
Yeah sure.. V soon
@@AsifResearchLab bro may I get your email or any other contact to learn in advance? I really need to fit my data into the nonlinear fitting asap for my paper needed as my graduation requirement... if you dont mind tho :)
@@khoirianuratikaputri2093 you may contact me at: asifayub871@gmail.com
Can you show how to perform this by the modle builder function in Origin
The Ce value is 14,6... the value after 60 mins of adsorption is 14,7...are these values slightly different everytime or they can be identical? Thx
Maximum adsorption take place at initial few minutes then take some time to establish equilibrium.
Helpful video. I have one question. I have time 0 to 720 minute and qt for each (for 0 qt 0). for calculation which qe I should use? How I get qe form this data.
qe ...when equilibrium established and no change in qt
@@AsifResearchLab actually I used 720 min as equilibrium. so in kinetics study the time length is 0 to 720 min. The data says highest capacity found in 60 min. so I have to use qt at 60min as qe? If i subtract others below and upper from 60 min I will get positive and negative values but what about the qt at 60? if i subtract this result will be 0 and ln0 is indifinite. That is the confusion.
@@mdjamaluddin5440 exactly em facing the same issue...
@@mdjamaluddin5440 dear if u get answer ti this question,e.g qe-qt=0 so ln0= undefined. please do share me. Thanks
Sir could u tell me how to draw photodegradation graph of C/C°.. vs time .
as we obtain data from UV which include Absorbance vs time....
Great work............ we expect more
Which article use
thank you for this tutorial. Could you make same videos for nonlinear forms?
Thanks. Sure
why choosing the value Ci=50mg/L ?
I also have the same question. have you come across any answer for this ? as much a read in the literature can't seem to find a clear answer
@@caranorb5203 me too. May I know that if you have come across it?
i guess that is the optimum concentration
whose first pseudo-order did you use? lagergeen or ho mc kay? or who?
This is ur task..search it.
@@AsifResearchLab lagergren is for pseudo first order
Above all else,embrace your flaws..👍
the equation is t/qt = 1/k2qe2 + t/qe u miss the x value that is t
Great job
Why we choose Mg/L ?
Hi, How did you calculate the other 4 from ln(qe-qt) when you got qe and 10 from qt? And my experiment has five concentrations and ten hours. How do you calculate this? I'm so confused... Please reply..
Can I draw only qt instead of ln(qe-qt) on the first pseudo graph? Also, can I use the values of intercept, slope, qe, and r2 of the graph drawn with qt? Please answer me..
Please make a video on the intraparticle diffusion model on the origin.
Sure
Sir can u tell me how to find out the n value for pseudo first order reaction
Good video .. What was the adsorption time to calculate qe, in the case of ci = 50 mg / L?
It depends, equilibrium can establish at any time may b in 60 min or in 24 h
thanks
thanks ur new subscriber
Bro could u made lecture about pseudo first order kinetic graph Ln C/C° vs time .. related to reductive degradation of dyes ie. MB .
yeah sure.
@@AsifResearchLab thank u so so muchh
good morning sir, sir I'm doing project on dye adsorption kinetics and isotherms I'm facing problems while applying values in the graph, need to submit my report by end of this month ... i need your help sir how could i contact you sir??
asifayub871@gmail.com
❤
Why the Ce value is not included in the contact time experiment , , , as you have taken Ce as 14.6 but in your contact time experiment your Ce values are 14.7
how to get qe value (expermental) ??
Maybe you should use an other fittng.. you have a value of -0.4 and your standard error is 0.3.
Do you have an other option ?
thank you
how can I find the theoretical pseudo-first order qt using the data obtained from the regression? In all time range 0 to 60 min.
Find it experimentally
Mujhe help chehiye.
Kindly help me.
Meri condition theek nahi hai.
Job k liye bhi apply nahi karne de rahe hai gundee.
Help chahiye.
Snehlata katheria.
Sir ky lagergren pseudo-first order kinetics ka kab manual mill sakta hai ky. Plz sir
Sorry i don't have.
Nice
Türkiyeden yaızyorum videonuz çok faydalı oldu benim için fakat anlayamadığım bir yer var cevaplarsanız çok mutlu olurum. Ci değerini neden 50 mg/l sectiniz
Thanks . But could not understand ur language
hey! nice efforts, but the adsorption capacity calculation involves (co-ce)/co*v/m
Thank you for video. I have aquation I have Qt grand for qe because I have the concentration in high time grand can I do because ln(qe_qt) unfunded.
What happend on the video it is not visible
why selecting that qe value ?
that was calculated not selected.
Why you choosen 50
Sir can you please do videos related kinetic fittings using BET CO2 adsorption .I have done my last paper work related to adsorption of lead with the help of your videos...kindly help me sir
thanks
Welcome
Why didnt u choose the R2 COD AND U CHOSE THE ADJ R2
How to ce .. from whr it is found
Via UV Visible or AAS
@@AsifResearchLab and qe?
What will be weight and mass...
If I take 200ml of dye solution (of 10mg/l dye ) and adsorbet is 10mg..
Formula reported in literature
Sir, why chose Ci value 50mg/L
optimized value
From what i calculate qe
You're mistaken with your graph and your constants. Check them again
K1 ne doit pas être négative k1=slope*(-2.303)
Great job, brother may I have your email please
the slop is K directly not K*t, this is incorect
??
can i know why for ln (qe-qt), you take the value of qe of 23.6?