How to apply the Pseudo Second Order Kinetic Model on experimental data using Origin Software

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  • เผยแพร่เมื่อ 10 ธ.ค. 2024

ความคิดเห็น • 13

  • @RollinsTM
    @RollinsTM ปีที่แล้ว +2

    the equation is t/qt = 1/k2qe2 + t/qe u miss the x value that is t

  • @belal22001
    @belal22001 9 หลายเดือนก่อน

    Is it possible to apply this model to a fixed-bed column experiment?

  • @muthusaru3527
    @muthusaru3527 3 ปีที่แล้ว +2

    I have the absorbance value from the uv data for dye degradation.. I don't have the concentration value.. Can you help me to know how to calculate the kinetic from the absorbamce value for the dye degradation

    • @hope2633cu
      @hope2633cu ปีที่แล้ว +2

      Use calibration curve from standard and calculate concentration

  • @talitavalverdeferreiradasi8444
    @talitavalverdeferreiradasi8444 ปีที่แล้ว

    I didn't understand how you found the value of 23.6 to be able to calculate qe². can you explain me ? I've done all the calculations so far.

  • @issakasikpaamalhassan4422
    @issakasikpaamalhassan4422 2 ปีที่แล้ว +1

    Hello, I think you may want to consider pinning all your videos under each video. This would help increase your viewership and likes. For example, I need to watch other fittings like W-m Intraparticle mass transfer, etc but I can't find it. I am wondering if you have done a video on it.

  • @harry-ho9ti
    @harry-ho9ti 3 ปีที่แล้ว

    Pls make a vdoi how to do curie Weiss law fitting after phase transition from dielectric constant vs temperature graph data. In addition calculate burn temperature from d same.

  • @bhatmash7315
    @bhatmash7315 2 ปีที่แล้ว +1

    I think u have missed t in the last part of the equation

  • @bhatmash7315
    @bhatmash7315 2 ปีที่แล้ว +1

    why are u plotting t/qe vs t and not t/qe vs 1/qe

    • @NanoencryptionSKP
      @NanoencryptionSKP  2 ปีที่แล้ว

      Sir, please go through the reference, which I have mentioned in the description box.
      🙏

  • @sorodhonipotshangbam1716
    @sorodhonipotshangbam1716 2 ปีที่แล้ว +1

    hello sir, the rate constant k for my experimental data is very large, it comes ..k2 = 96.35146442 . Is it possible?