AC4LX here - I got my Amateur Extra ticket way back in like, '92 along with my FCC General Radio Telephone operator permit while in the USAF. Its good to get this refresher, and thank you for the video and clear and easy to understand presentation!
This was very good! One thing though... that negative sign out in front of the tangent operator. I think that instead of indicating a reciprocal, as in 1/tan or something, it's more appropriate to call it the inverse tangent, or perhaps, it means the angle for which the tangent equals what is in the parentheses.
Michael, thank you so much for your videos, this one included. Your presentations and lectures are great. There is a problem, however, at approximately 9:30 into the presentation as Michael describes the tan-1(x) function. Michael states, "tan^-1(x), the reciprocal of the tangent ...." Ooops, that is incorrect. The tan^-1(x) function is NOT the "reciprocal" of the tan(x) function. Both tan^-1(x) and tan(x) are "inverse functions" of each other, completely different than reciprocals of each other. A reciprocal is the "multiplicative inverse" of a quantity. The reciprocal of x is 1/x. Just as the reciprocal of 4 is 1/4. The reciprocal of the tan(x) function therefore, is 1/tan(x); the reciprocal of the tan(x) function is also known as the cotangent(x) function. Let's recognize that tan^-1(x) is the "inverse function" of tan(x). An inverse function, is completely different than a reciprocal. So then, what is an inverse function? We know how to take a number x, entering x into some function, where the outcome is f(x). For instance, let's use the number 4 as our x. We enter 4 into the function (x)^2, and we calculate (4)^2 = 16. We have started with some x, calculated, and obtained an f(x). But what happens if we start with f(x) and we need some function to find x? In this case, we may use the "inverse function" of f(x), known as f^-1(x), to obtain our x. So, lets use our trig example, starting with the tan(x) function. As in the video, if we have some angle x, and calculate the tangent function of angle x, we will obtain some number, tan(x). So let's do that. Let use negative angle -14.0362 and calculate tan(x). We calculate tan(-14.0362) and obtain the number -0.2500. Now, let's start with our number -0.2500, using the "inverse function" of tan(x), a function called tan^-1(x) and also known as arctan(x), to calculate our original angle. Working with the tan^-1(x), we calculate tan^-1(-0.2500), to obtain our angle, -14.0362. We have just used the "inverse function" of tan(x), also known as function tan^-1(x) or arctan(x), to start with some number, with the final goal to obtain an angle. The confusion with reciprocals and inverse functions often stems from confusing the accepted math notation. The reciprocal of x is 1/x. Great. We can also use exponents to represent the quantity 1/x, as x^-1. Just as 1/125 can also be written as 125-1. The reciprocal of tan(x) can be written as 1/tan(x). Using exponents, 1/tan(x) also can be expressed as (tan(x))^-1. Here, the negative exponent ^-1 applies to the entire quantity tan(x). 1/tan(x) is equivalent to (tan(x))^-1. Of course, the reciprocal of tan(x), can be written simply as cotangent(x). In math, we indicate the "inverse function" using a convention that appears like exponential notation, but it is NOT exponential notation! Instead, this notation indicates "inverse function." We may have function f(x). The "inverse function" notation for f(x) is f^-1(x); the ^-1 here is NOT exponential notation, but is simply a convention that indicates the "inverse function" of f(x). The inverse function notation for tan(x) is tan^-1(x). Again, the ^-1 here has NOTHING to do with exponents, it is simply the notation convention that indicates "inverse function" of tan(x). In contrast we can express reciprocals; f(x)^-1 means 1/f(x). Here, the ^-1 is a negative exponent. Likewise, if we have tan(x)^-1, we mean 1/tan(x). The "reciprocal" of f(x) is 1/f(x) or f(x)^-1. The "reciprocal" of tan(x) is 1/f(x) or tan(x)^-1. Choose your preference. So, we use the "inverse function" of tan(x), which is tan^-1(x), to get back to our phase angle. This minor attention to detail in math notation has real meaning. On calculator keys, the trigonometry "inverse functions" are often noted as asin, acos, atan. On some calculator keys, the trigonometry "inverse functions" can sometimes be noted as sin^-1, cos^-1, tan^-1. Whereas on a calculator, should you need to calculate a "reciprocal" of tan(x), you simply calculate 1/tan(x). Time for a coffee break. 73 to all. Many thanks for Michael's excellent work
Για να υπολογισουμε το αντιστροφο της εφαπτομενης (tanθ) δηλαδη το arctanθ η tan^-1(θ) χρειαζεται ολοκληρωτικος λογισμος δεν ειναι απλο. οποτε μονον με calculator
Hi. I tried to google tan-1 ((250-500)/1000) and its .3894. Can you please calculate step by step because I'm a little confused right now. Thanks. BTW I thought that tan is the opposite side divided by adjacent side.
Hi. Pull out your trusty TI-30XS and go to about 12:14 in this video. I show keypress by keypress how to solve this one. It's also covered on page 155 in the course. Good luck with your studies!
When we connect the resistor to Ac voltage source there is no phase difference angle in the circuit between current and voltage But when we connect an inductor to the same source the current delays from voltage by 90 phase difference angle because of the self induction in the inductor And when we connect a capacitor to the same source we find that the voltage delays from current by 90 phase difference angle because of charging and discharging process Give the reason
Hi, Ganesh. If current and voltage are out of phase, less power is transferred to the load. In fact, if they are 90 degrees out of phase, no power is transferred at all. The amount of power transferred to the load is calculated by taking the cosine of the phase angle, and that figure is known as the "power factor." In radio, we are concerned with transferring as much power as possible to the transmitting antenna. That is why when we adjust the impedance matching between the transmitter and antenna, we want a purely resistive impedance, with no capacitive or inductive reactance. Power distribution networks typically "see" large inductive loads -- all those inductance motors out there. That has the effect of causing the current to lag the voltage. Power companies correct the phase with large capacitors. Those are a couple of the applications of this important principle.
@@ganeshbhat7613 - in a purely inductive circuit, voltage leads current by 90 degrees. In a purely capacitive circuit, current leads voltage by 90 degrees. Neither of those "pure" circuits exists in the real world -- they are "ideal" circuits, so in the real world, we can never cause the current and voltage to be more than 90 degrees out of phase, because we can't actually even get them to exactly 90. I can't think of a way your example can exist in the real world, since the amount of "out of phaseness" available is only 90 degrees. On paper, the power factor of the situation you describe would be negative 100%, since the cosine of 180 is -1.
The Voice is too much. It sounds unnatural and is distracting. Sorry, I'm sure you do a good job of explaining the subject matter but its annoying. If your channel is growing so fast why do you have less than 3000 subscribers after 5 years. Delta between when this video was uploaded and when I watched it.
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Best teacher, you are great example of being a good teacher. You are enthusiastic and informative. Keep up the good work.
WOW, this is the best video I have ever watched. I can literally do the phase and phase diagram at ease
You've got a great voice for this.
wow...what a mind blowing narrative of the lesson? I like how this guy present with so much confidence and conviction!
Thank you! I'm not studying radios specifically, but this is the first video I've found thqt explains these concepts simply.
AC4LX here - I got my Amateur Extra ticket way back in like, '92 along with my FCC General Radio Telephone operator permit while in the USAF. Its good to get this refresher, and thank you for the video and clear and easy to understand presentation!
this man is an excellent teacher - 83 year old retired power EE
This was very good! One thing though... that negative sign out in front of the tangent operator. I think that instead of indicating a reciprocal, as in 1/tan or something, it's more appropriate to call it the inverse tangent, or perhaps, it means the angle for which the tangent equals what is in the parentheses.
thank you so much for the insightful, yet entertaining lesson. Well done!
Thank you for this lesson. It was as entertaining as it was educational.
THIS IS GREAT! I DEFINITELY LOVED IT, THANKYOU!!!
Sounded like the beginning of a Disney movie. Loved it
Cheers for the video, I love your narration, fantastic to listen to!
Thank you, that was a great video. I have subscribed.
very good narrative. patient and enthusiastic. thank you for the lesson.
Michael, thank you so much for your videos, this one included.
Your presentations and lectures are great.
There is a problem, however, at approximately 9:30 into the presentation as Michael describes the tan-1(x) function.
Michael states, "tan^-1(x), the reciprocal of the tangent ...." Ooops, that is incorrect.
The tan^-1(x) function is NOT the "reciprocal" of the tan(x) function.
Both tan^-1(x) and tan(x) are "inverse functions" of each other, completely different than reciprocals of each other.
A reciprocal is the "multiplicative inverse" of a quantity. The reciprocal of x is 1/x. Just as the reciprocal of 4 is 1/4. The reciprocal of the tan(x) function therefore, is 1/tan(x); the reciprocal of the tan(x) function is also known as the cotangent(x) function.
Let's recognize that tan^-1(x) is the "inverse function" of tan(x). An inverse function, is completely different than a reciprocal. So then, what is an inverse function?
We know how to take a number x, entering x into some function, where the outcome is f(x). For instance, let's use the number 4 as our x. We enter 4 into the function (x)^2, and we calculate (4)^2 = 16. We have started with some x, calculated, and obtained an f(x).
But what happens if we start with f(x) and we need some function to find x?
In this case, we may use the "inverse function" of f(x), known as f^-1(x), to obtain our x.
So, lets use our trig example, starting with the tan(x) function.
As in the video, if we have some angle x, and calculate the tangent function of angle x, we will obtain some number, tan(x). So let's do that. Let use negative angle -14.0362 and calculate tan(x). We calculate tan(-14.0362) and obtain the number -0.2500.
Now, let's start with our number -0.2500, using the "inverse function" of tan(x), a function called tan^-1(x) and also known as arctan(x), to calculate our original angle.
Working with the tan^-1(x), we calculate tan^-1(-0.2500), to obtain our angle, -14.0362.
We have just used the "inverse function" of tan(x), also known as function tan^-1(x) or arctan(x), to start with some number, with the final goal to obtain an angle.
The confusion with reciprocals and inverse functions often stems from confusing the accepted math notation. The reciprocal of x is 1/x. Great. We can also use exponents to represent the quantity 1/x, as x^-1. Just as 1/125 can also be written as 125-1.
The reciprocal of tan(x) can be written as 1/tan(x). Using exponents, 1/tan(x) also can be expressed as (tan(x))^-1. Here, the negative exponent ^-1 applies to the entire quantity tan(x). 1/tan(x) is equivalent to (tan(x))^-1. Of course, the reciprocal of tan(x), can be written simply as cotangent(x).
In math, we indicate the "inverse function" using a convention that appears like exponential notation, but it is NOT exponential notation! Instead, this notation indicates "inverse function."
We may have function f(x). The "inverse function" notation for f(x) is f^-1(x); the ^-1 here is NOT exponential notation, but is simply a convention that indicates the "inverse function" of f(x). The inverse function notation for tan(x) is tan^-1(x). Again, the ^-1 here has NOTHING to do with exponents, it is simply the notation convention that indicates "inverse function" of tan(x).
In contrast we can express reciprocals; f(x)^-1 means 1/f(x). Here, the ^-1 is a negative exponent. Likewise, if we have tan(x)^-1, we mean 1/tan(x). The "reciprocal" of f(x) is 1/f(x) or f(x)^-1. The "reciprocal" of tan(x) is 1/f(x) or tan(x)^-1. Choose your preference.
So, we use the "inverse function" of tan(x), which is tan^-1(x), to get back to our phase angle.
This minor attention to detail in math notation has real meaning.
On calculator keys, the trigonometry "inverse functions" are often noted as asin, acos, atan. On some calculator keys, the trigonometry "inverse functions" can sometimes be noted as sin^-1, cos^-1, tan^-1.
Whereas on a calculator, should you need to calculate a "reciprocal" of tan(x), you simply calculate 1/tan(x). Time for a coffee break. 73 to all. Many thanks for Michael's excellent work
Very well said. It's the comments like this that make them worth reading.
Thanks for the lesson. :) Cheers!
Great video, no bs and easy to understand. Thanks a lot!
Really, great video. Thank you.
Great explanation for all levels
God bless you!
simplest way to explain ever! Thank you!
His enthusiasm is amazing 😂
thank you. an art major trying to research for a electrical test tech exam.
Thanks for the lesson. Great voice. You should start doing audiobook narration!
Thanks! Too late to start, though --- all our license courses are already available in audio from Amazon and Audible.com.
Really pleasant voice and great explanation
This is SO GOOD!
What a teacher
Love the humor 😂
What is the best way to test and find the phase angle ???
what instrument can use to measure it ???.
Thanks.
Nice.Thank you.was wondering how i would remember Eli the ice man.Thank you
Great teaching.
Best explanation
Hi, I like your lecture. Thanks
thank s a lot for the ice cream sir
Wish you were my prof lol thank you
Thank you for this
ELI the ICE man
1.Voltage(E) leads current(I) in inductor
2.Current(I) leads voltage(E) in capacitor
good vedio
omg this is a great video
Very good video on the phase angle. Moreover, I could get the English pronunciation without turning on sub-titles😄
very good man
It feels like I am listening to the one of the TOEFL listening passages
Για να υπολογισουμε το αντιστροφο της εφαπτομενης (tanθ) δηλαδη το arctanθ η tan^-1(θ) χρειαζεται ολοκληρωτικος λογισμος δεν ειναι απλο. οποτε μονον με calculator
Hi I like your video
I'm not sure why but I'm getting -.2449 when I put this into my TI84+
EDIT fixed my own problem. Mode > switch Radians to Degrees... 🤦🏽😂
Hi. I tried to google tan-1 ((250-500)/1000) and its .3894. Can you please calculate step by step because I'm a little confused right now. Thanks.
BTW I thought that tan is the opposite side divided by adjacent side.
Hi. Pull out your trusty TI-30XS and go to about 12:14 in this video. I show keypress by keypress how to solve this one. It's also covered on page 155 in the course. Good luck with your studies!
Name of the channel is so strange.
AF7KB is my amateur radio call sign. I teach people to get their amateur radio license.
When we connect the resistor to Ac voltage source there is no phase difference angle in the circuit between current and voltage
But when we connect an inductor to the same source the current delays from voltage by 90 phase difference angle because of the self induction in the inductor
And when we connect a capacitor to the same source we find that the voltage delays from current by 90 phase difference angle because of charging and discharging process
Give the reason
👍👍👍👍👍👍👍👍
Its ELI the ICE man
What happens if current or voltage leads? Applications of this
Hi, Ganesh. If current and voltage are out of phase, less power is transferred to the load. In fact, if they are 90 degrees out of phase, no power is transferred at all. The amount of power transferred to the load is calculated by taking the cosine of the phase angle, and that figure is known as the "power factor." In radio, we are concerned with transferring as much power as possible to the transmitting antenna. That is why when we adjust the impedance matching between the transmitter and antenna, we want a purely resistive impedance, with no capacitive or inductive reactance.
Power distribution networks typically "see" large inductive loads -- all those inductance motors out there. That has the effect of causing the current to lag the voltage. Power companies correct the phase with large capacitors.
Those are a couple of the applications of this important principle.
@@af7kbfasttrackhamradio50 if 180 degree out of phase what happens sir
@@ganeshbhat7613 - in a purely inductive circuit, voltage leads current by 90 degrees. In a purely capacitive circuit, current leads voltage by 90 degrees. Neither of those "pure" circuits exists in the real world -- they are "ideal" circuits, so in the real world, we can never cause the current and voltage to be more than 90 degrees out of phase, because we can't actually even get them to exactly 90. I can't think of a way your example can exist in the real world, since the amount of "out of phaseness" available is only 90 degrees. On paper, the power factor of the situation you describe would be negative 100%, since the cosine of 180 is -1.
Tom Hanks brother?
I got a different answer for phase angle
salamat
Please explain it sir
You missed a set of parentheses. arctan((250-500)/1000)=-14.0
Tan‐¹(250-500/1000) = .26240.....
Ranjith, you missed a set of parentheses. arctan((250-500)/1000)= -14.04 degrees
The Voice is too much. It sounds unnatural and is distracting. Sorry, I'm sure you do a good job of explaining the subject matter but its annoying. If your channel is growing so fast why do you have less than 3000 subscribers after 5 years. Delta between when this video was uploaded and when I watched it.
Fortunately, all our license courses are available in paperback and e-book editions!
fasttrackham.com
Hi I like your video