By the definition of logarithm, it is directly 2^2 = x^2/(x+3); then this becomes quadratics equation. It ends up with x = 6 and x =-2; You are a great teacher. I wish I had the teacher like you in my high school, explaining everything clearly. Cheers!
Can someone help? Why did you reject the solution x=-2? I know logs can’t take negative inputs, however that 2 out front of the original equation means we would take x^2, therefore the input would always be positive. That’s why I thought it would still be a solution.
Also, at 6:16 you said that log2 (6) works, but log2 (9) doesn’t work... why doesn’t that work? Assuming it doesn’t work, then why didn’t you reject the solution x=6?
Shouldn't both be correct? logBase2 of x^2 where x=-2 is logBase2 of 4, minus logBase2(x+3) (which works out to be zero) is equal to 2. For 6, 2logBase2(6)-logBase2(9) will equal two as well.
@@brianmclogan 4 days away from 9th anniversary, going through most of your log videos for a test tomorrow, you are an absolute lifesaver for putting these on youtube. My math teacher's explanations make me want to blow my brains out. I wish I was in your class, I'd probably get an A+.
Brian McLogan first of all it turned out that there are two solutions : x =6 and x = -2 ... Near the end of the video you said that if we substituted x = 6 in Log base 2 of ( x + 3 ) it will give us Log base 2 of 9 and it won't work but that's incorrect because Log base 2 of 9 = 3.1699 . Secondly , what I want to understand : why is x = -2 not accepted since 2Log base 2 of x = Log base 2 of (x)^2 = Log base 2 of (-2)^2 = Log base 2 of 4 =2 so why is it unaccepted ?
thank you for being straightforward, long lectures on math just always goes in one ear and out the other so things like this help a lot
God bless!!
Very Good, Brian McLogan, Keep It Up! 🎉🎉🎉🎉
Headphone users = death by keys
it was so LOUD
"Kiss" of death
lmao I turned my volume all the way up because I couldn't hear and the keys were so loud.
By the definition of logarithm, it is directly 2^2 = x^2/(x+3); then this becomes quadratics equation. It ends up with x = 6 and x =-2; You are a great teacher. I wish I had the teacher like you in my high school, explaining everything clearly. Cheers!
God bless! B
youve helped me through my 10-week online college math course. thank you 😭🙏 im rewatching these before the final tomorrow
God bless !!
Can someone help? Why did you reject the solution x=-2? I know logs can’t take negative inputs, however that 2 out front of the original equation means we would take x^2, therefore the input would always be positive. That’s why I thought it would still be a solution.
Also, at 6:16 you said that log2 (6) works, but log2 (9) doesn’t work... why doesn’t that work? Assuming it doesn’t work, then why didn’t you reject the solution x=6?
@@crod1232 , he misspoke.
th-cam.com/video/0K5p49E7TWg/w-d-xo.html
@@jdilksjr so when he misspoke, he meant it X=6 does work?
@@crod1232 That will work, he misspoke. You can use the rule and see the negative sign as (x+3)^-1, which I believe will give you the same answer
you are the BEST! thank you so much for your videos!!
2log2(6)-log2(6+3)=2 x=6
Goodmorning sir, could you please make a video about on how to solve logarithmic inequalities? Thank you
Thank you so much
you have saved me brian. god bless.
Got like 25min before my final 😂
The videos from 2006 are helping
what did you do with the two in log x. Where did it go?
which one? at what point?
Why is 6 still an answer if 6 and 3 =9 and that doesn't work?
Shouldn't both be correct? logBase2 of x^2 where x=-2 is logBase2 of 4, minus logBase2(x+3) (which works out to be zero) is equal to 2. For 6, 2logBase2(6)-logBase2(9) will equal two as well.
you can’t evaluate 2log(-2). you have to plug your x value into the original equation
You are amazing.
Hope you were my teacher.
Thank you happy to help
goog video,thanks
thank you so much man
log5+log(2x+10)-2=log(x-4)
I’m doing a question where log2(x+5/x)=3 how would I get my answer from that
Happy anniversary of this video
cheers!
@@brianmclogan 4 days away from 9th anniversary, going through most of your log videos for a test tomorrow, you are an absolute lifesaver for putting these on youtube. My math teacher's explanations make me want to blow my brains out. I wish I was in your class, I'd probably get an A+.
Thank U ♥♥♥♥
you are very welcome!
هلا وغلا
Thank you for your tutorial in log but it is not visible at all
Not visible please.
What?
Long 7-Minute Video
Dude -2 in the equation is going to be squared and become positive
what time point?
Brian McLogan first of all it turned out that there are two solutions : x =6 and x = -2 ... Near the end of the video you said that if we substituted x = 6 in Log base 2 of ( x + 3 ) it will give us Log base 2 of 9 and it won't work but that's incorrect because Log base 2 of 9 = 3.1699 . Secondly , what I want to understand : why is x = -2 not accepted since 2Log base 2 of x = Log base 2 of (x)^2 = Log base 2 of (-2)^2 = Log base 2 of 4 =2 so why is it unaccepted ?
@@mohammedkhaled2456 because it will become and imaginary number
@@decoyreggieyt4621 I think they mean if you put the 2 back in so it becomes log2(-2^2)
Why are they torturing us?
i think i have adhd
why don't you ever do the problems I have on my actual homework? I have a equal sign in the middle, separating two logs.
Thank you so much