slide calliper practical | vernier calliper practical | Positive and Negative Zero Errors of VC /SC|

Hello Everyone,
In this video I have explained about Zero Errors of Vernier Callipers,There are two types of zero Errors, Positive zero Error and Negative Zero Error.Hope this video will help students.
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[@shreyamishra5416]

Very nice vdo.. Really helpful it's my physics practicle tomorrow 👍Thanku 😊

[@SatyajitKanu]

1 day before exam 😅

[@incrediblerail440]

1 night before exam😅

[@anuthomas5970]

Sir thank you so much for explaining well, I understood it all.
However I have a major doubt ki aapne khud kaha 4:04 me ki humlog ko ye nhi dekhna h ki main scale ka konsa line coincide kr rha but ye dekhna h ki vernier ka konsa coincide kr rha h. Jase ki aapne P. Z. E kiya, vernier ke 2nd line coincide krne pe N 2 liya but N. Z. E me aapne vernier scale ke 2nd coincide krne pr bhi, main scale ke first ke coincide krne vli value kyu bithayi 5:56 me. N ka value toh udhar bhi 2 hoga na according to the observation?

[@ManpreetSingh-qh9vm]

First is correct In second case it's video error 😂

[@sahajnotnani4289]

Yes I have the same doubt

[@sahajnotnani4289]

​@@ManpreetSingh-qh9vm yes you are correct 💯

[@RajaniVerma-yp7xu]

Observed value kya hai??

[@sushilagavel352]

Samaj aa gaya sir

[@manyatasartwork5195]

Very good video

[@priyaprem1213]

Very good sir

[@prasantkumardubey8857]

Great sir

[@soundsgreat5461]

Thanks sir 💪🙏

[@peakvelocity.12]

Thanks 😃

[@AtharvKumar-s8t]

Negative zero error is not correct
The correct formula for negative zero error is: (10-coinciding division)*L.C
Therefore it will be: (10-1)*0.1 mm
=9*0.1mm
=0.9mm or 0.09cm

[@Boyinbubble]

Or you can count from the back, and btw, thank you so much, I was confused whether I'm right or not.

[@maroofnazar3196]

Yes bro this is the correct one i was trying to. remember

[@bishalkumar7800]

And it should be added to its correct observation na?

[@Boyinbubble]

@@bishalkumar7800 if it's negative error then add
If it's positive error then you gotta subtract it from the observation

[@AtharvKumar-s8t]

@@bishalkumar7800 yes

[@tasneemsiddiqui2678]

Thank you sir it was helpful

[@MutadFarhaana]

in negative zero error shouldn't it be (n-x)L.C

[@bishalkumar7800]

Yes it should be -(10-x) × LC na?

[@navneetkrsuman1683]

Me 1st ☺️

[@SanjeevSirPhysics]

Yes