Hey, here's a dedicated CBSE course on our website where you can practice all the concepts related to this video and more. And oh, it's always free. www.khanacademy.org/science/in-in-class-12th-physics-india/in-in-semiconductors
I have a question here when the critical state of transistor us achieved Vce is 0 then .... wouldn't that be a forward bias between collector and base so there should be a net flow of electrons and it is that part of the curve which is not parallel to voltage axis
It would be great if someone could clear my doubt - We increased Ib, so Ic increased but Vce decreased. And so we are trying to find till what we can increase Ib to, so that amplification still happens....but according to what you said in the last video, after Vce decreases below 0.7V, the base-collector gets forward biased and for amplification process to happen we must be in the right side of the output characteristics graph. So for the active state shouldn't 0.7
@@KhanAcademyIndiaEnglish Thanks a lot for clearing that! And these videos are great. I tried multiple resources but never understood this chapter properly, until i found these.
very helpful sir, I had watched a lot of video on youtube about saturation of transistor but I did not understand the saturation of transistor clearly.many many thanks for understanding this lesson easily.
Sir, at 07:47, the Output Voltage has become 0 Volts This means that the Input voltage is greater than the output voltage So the reverse biasing has stopped and Forward bias has started, right?(As the P type is now connected to a more positive than N type). Which means the transistor ceases to amplify
SIR / KHAN ACADEMI Just now i watched yr video on TRANSISTORS (NPN)--CUTOFF, SATURATION AND AMPLIFICATION REGION. Liked yr video AND U TAUGHT VERY WELL. U EXPLAINED CLEARLY AND I UNDERSTOOD WITHOUT A DOUBT. YR WRITINGS VISIBILITY, EXPLANATION SOUND ALL EXCELLENT. THANKS VATSA
This definitely helped explain the saturation region a lot. The saturation and cutoff regions can be used for oscillators -- in coupled transformers positive feedback to the base using an coupled inductor is the basis for ring choke flyback transformers
One of the best videos on this I have seen. I'd just like to note that many courses like to use V_ce = 0.2 V for sat and that V_be = 0.6 V for anyone watching. Thanks!
Very very thanks sir.I struggled a lot to understand transistors but after this I realised it's quite easy. Your teaching style is awesome sir. Respect u!!🙇🙇
This is a very excellent explanation. It really contributed to my overall understanding of how the NPN transistor works and the accompanying technical vocabulary. Thank you very much!
i mean there can't be a better explanation than this one most of the videos that i've saw are way too complicated and not comprehensive at all unlike this one thank you from the heart man
Sir another doubt... At 11:10, you have said that for the transistor to work as an amplifier, the Input Current has to be within a rang. But in the 3rd case, even though the Input current is greater than 30 microamperes (outside the range), the output current is 3 milliamperes (still almost 100 times the Input current). So doesn't it continue to be an amplifier Because the condition for an amplifier is that the Output current must be much greater than the Input current, and the condition is still satisfied). Kindly clarify this sir
his voice is really great and the way he speaks makes me to listen and stick on to the video till the end !! great sir keep doing videos on many different topics in electronics subject
In saturation we say Transistor acts as closed switch. That is collector current = emitter current. But wouldn't emitter current be equal to base current + collector current according to KCL. why we assume it directly equal to collector current alone?
If the output voltage is connected to a load, and base voltage is zero, will the 1k resistor will have a voltage drop? Or the Vce will get the full 3v? Thanks
Its an awesome vedio pertaining to electronics ..... please put up more such vedios for students from electronics engineering background...i understood it well thanks!!.
Here Vce can never be equal to or less than 0.7 volt as base collecter will become forward biased...sir u too Vce=0v minm...can't understand...plzzz help
The value of Vce depends on choice of resistor and supply voltage. You are absolutely right that when Vce goes below 0.7 volt the base collector gets forward biased. This is actually where the saturation region begins. In saturation region both b-c and b-e are forward biased
@@KhanAcademyIndiaEnglish Sir if the base collector juntion becomes forward biased how will the electrons move from the base to the collector ??? How can their be a collector current even when at saturation both the b-e and b-c juntion are forward biased
Can you please tell me which configuration you spoke about in this video.....is it common base or common emitter configuration or for both this mechanism will work? Plz reply if possible 😅
in transister collector base junction is alaways reverse bise but ....... how you are teeling vce is 0(zero) and vBE (0.7v) in a sturated state it created a forward baise and transistor working is possible in a collector to base in forward baising ??????????????
In saturation, as the name suggests the output current is maxed out. (In our video example 3mA). In this state as the input current changes output will stay constant. That's not an amplifier right? An amplifier would be if output current is always some number (beta) times in put. Which means as input changes output must keep changing accordingly
Hey, here's a dedicated CBSE course on our website where you can practice all the concepts related to this video and more. And oh, it's always free.
www.khanacademy.org/science/in-in-class-12th-physics-india/in-in-semiconductors
I have a question here when the critical state of transistor us achieved Vce is 0 then .... wouldn't that be a forward bias between collector and base so there should be a net flow of electrons and it is that part of the curve which is not parallel to voltage axis
What does "fie wold" mean?
you guyes are gem
This is by far the most understandable and usefull electronic tutorial I have ever watched. You are blessed with an amazing teaching skill.
same to me
Yup bro
Yup. He makes the best simply understandable concepts.
I'm studying telecommunications engineering and no words to say. This is perfect. Easy to understand, just what i need. Thank you for your good job.
I've been trying to understand the basic concepts of transistor for years and this has definitely helped alot. Thank you🙂
same to me!
Same
This whole transistor series of lessons was superb! I think i finally grasped a decent understanding now!
your entire series on semiconductors has been invaluable to me in understanding the basics. Thank you!
To answer your question.
You: I hope this makes sense ?
Me: it makes more than sense.
The application of the cutoff mode and saturation mode is a switch. I finally understand, Thank you!
It would be great if someone could clear my doubt - We increased Ib, so Ic increased but Vce decreased. And so we are trying to find till what we can increase Ib to, so that amplification still happens....but according to what you said in the last video, after Vce decreases below 0.7V, the base-collector gets forward biased and for amplification process to happen we must be in the right side of the output characteristics graph. So for the active state shouldn't 0.7
You are absolutely right. I oversimplified it.
@@KhanAcademyIndiaEnglish Thanks a lot for clearing that! And these videos are great. I tried multiple resources but never understood this chapter properly, until i found these.
I watched 3 videos on the subject before this. Superbly done!
Finally understood the concept! Thanks Sir Mahesh! :)
Without a single flaw you explained this very well
very helpful sir, I had watched a lot of video on youtube about saturation of transistor but I did not understand the saturation of transistor clearly.many many thanks for understanding this lesson easily.
Sir, at 07:47, the Output Voltage has become 0 Volts
This means that the Input voltage is greater than the output voltage
So the reverse biasing has stopped and Forward bias has started, right?(As the P type is now connected to a more positive than N type). Which means the transistor ceases to amplify
I agree. I guess there should be no current but why is there still I_c?
Some Eureka moments for me in this video. Thanks.
I loved the colour factor you used,it made it easier to understand..thnks :)
Typical Khan academy style. You nailed it my man.
SIR / KHAN ACADEMI
Just now i watched yr video on TRANSISTORS (NPN)--CUTOFF, SATURATION AND AMPLIFICATION REGION.
Liked yr video AND U TAUGHT VERY WELL.
U EXPLAINED CLEARLY AND I UNDERSTOOD WITHOUT A DOUBT.
YR WRITINGS VISIBILITY, EXPLANATION SOUND ALL EXCELLENT.
THANKS
VATSA
This definitely helped explain the saturation region a lot. The saturation and cutoff regions can be used for oscillators -- in coupled transformers positive feedback to the base using an coupled inductor is the basis for ring choke flyback transformers
This is the most understandable explanation I have ever seen in BJT topics
Excellent! Crystal clear presentation, idea by idea. Best transistor modes vid I've seen so far :)
This channel deserves way more views
You a legend sir
One of the best videos on this I have seen. I'd just like to note that many courses like to use V_ce = 0.2 V for sat and that V_be = 0.6 V for anyone watching. Thanks!
Sir you are the best teacher who teaches about the transistor working
Very very thanks sir.I struggled a lot to understand transistors but after this I realised it's quite easy. Your teaching style is awesome sir. Respect u!!🙇🙇
Ur amazing sir .. so happy to have u as my mentor🙏🙏🙏❤
This vedio is great 👍 . I clear my confusion regarding modes of operation for transistor after watching it .
This is so good omg
Thank you so much, understanding electronics has never been easier. A very lucid tutorial!
just like Khan math --> well done. thank you
Simplified explanation. Very Good 👍
This is very good.and at last he teased digital switches which is very interesting.
This is a very excellent explanation. It really contributed to my overall understanding of how the NPN transistor works and the accompanying technical vocabulary. Thank you very much!
Absolutely amazing explanation sir.. ❤❤
i mean there can't be a better explanation than this one most of the videos that i've saw are way too complicated and not comprehensive at all unlike this one thank you from the heart man
Awesome man, hats off to youtube Algo.
Just what I needed clarity on 🎉❤
by far the more useful video i came across.
Sir another doubt...
At 11:10, you have said that for the transistor to work as an amplifier, the Input Current has to be within a rang. But in the 3rd case, even though the Input current is greater than 30 microamperes (outside the range), the output current is 3 milliamperes (still almost 100 times the Input current). So doesn't it continue to be an amplifier Because the condition for an amplifier is that the Output current must be much greater than the Input current, and the condition is still satisfied).
Kindly clarify this sir
Yeah but you're not getting an amplified current as you're supplying more current from base region..
I have read Boylestad + Floyd but failed to understand in short time.
Your single 13 min is enough to understand Operation of Mode.
Thanks
his voice is really great and the way he speaks makes me to listen and stick on to the video till the end !! great sir keep doing videos on many different topics in electronics subject
Thanks a lot !!, Very well explained!!. I think this is the easiest explanation I have found on the Internet.
11:58
I guess we can use 'cut_off' & 'saturation' to apply digital logic i.e. 1 or 0 ???
Thanks so much for your absolutely helpful lecture sir.
In saturation we say Transistor acts as closed switch. That is collector current = emitter current. But wouldn't emitter current be equal to base current + collector current according to KCL. why we assume it directly equal to collector current alone?
Wish I had seen this video much earlier... Thank you, super clear explanation.
You are the best. I do not have any questions after watching your tutorial. Thanks a lot
your video is so good from 1st video to end video,,,,yyou are a legend;;;
This has to be appreciated. I can't thank anymore.
Great lesson, very good teacher.
I learned in 12 minutes what I didn't learn in 1 hour at university. Thankful
Mahesh shenoy sir you are simply great!
Best explanation.you are a great physics teacher.
Best explanation! Thank you!
Tough thinks make easier . Great.
If the output voltage is connected to a load, and base voltage is zero, will the 1k resistor will have a voltage drop? Or the Vce will get the full 3v? Thanks
Excellent Explanation Congrats
Really thank you soo much I want to understand this from many years but now with this video it's very clear
Thank you sir for your effort, please continue if you wish🙇♂️👍
This is the best explanation in this topic.
Its an awesome vedio pertaining to electronics ..... please put up more such vedios for students from electronics engineering background...i understood it well thanks!!.
Amazing, thank you khan
Here Vce can never be equal to or less than 0.7 volt as base collecter will become forward biased...sir u too Vce=0v minm...can't understand...plzzz help
The value of Vce depends on choice of resistor and supply voltage.
You are absolutely right that when Vce goes below 0.7 volt the base collector gets forward biased.
This is actually where the saturation region begins.
In saturation region both b-c and b-e are forward biased
@@KhanAcademyIndiaEnglish Sir how can the transistor b-e (be) forward biased when when input voltage is less than 0.7 volt please explain .
@@KhanAcademyIndiaEnglish Sir if the base collector juntion becomes forward biased how will the electrons move from the base to the collector ??? How can their be a collector current even when at saturation both the b-e and b-c juntion are forward biased
@@KhanAcademyIndiaEnglish How is the I_C max when b-c is forward biased? Shouldn't there be no current in the collector pin?
@@KhanAcademyIndiaEnglish so it means that amplification can done only in active region.
Very useful video👍👍👍
Wow thank you so much! Great explanation, I couldn't find such great explanation anywhere! You're great!
Amazing lectures!! Really pretty detailed information in a very understandable manner.What could we want more than this in physics👌😀
Very well explained sir
Simply put, great video, thank you.
Great presentation. Thanks
Sir ur subscribers are incresing
Congratulations for creating this superb piece of video. I have gone thru number of other videos but no match
Excellent 🙌👌
U explain in a very simple way .thanku so much Sir
absolutely amazing job
Can you please tell me which configuration you spoke about in this video.....is it common base or common emitter configuration or for both this mechanism will work?
Plz reply if possible 😅
Thank you soon much for providing Crystal clear explanation 😊 finally understood the concept!!
woooow,, thank you sir @LK
Yes sir explanation is from very basic
Toughest topic I have ever studied in physics
Excellent explanation. Thank you!
I guess saturation, & cutoff can be used as a NOT gate.
Great Guess. Close..ie a switch
Why you not plot the graph between output current and voltage?
Best teacher 😀💙
Thank u khan academy 😀
Because of saturation and cutoff transistor can be used in binary operations .. like citoff means 0 and saturation means 1
Electronic is way to imaginative for me,it seems like its not real loll but you did great job explaining all my doubts.
When we're taking the new Vce what about the internal voltages INSIDE the transistor ?
Very nice explanation!
Thank you very much ..so clear brief and conscise
in transister collector base junction is alaways reverse bise but ....... how you are teeling vce is 0(zero) and vBE (0.7v) in a sturated state it created a forward baise and transistor working is possible in a collector to base in forward baising ??????????????
Simply...
Thanks
Nice video, thank you for sharing :)
Sir if output voltage become 0v the isn't collector base junction will be in forward biased.
God level teaching
thanks so much for such a nice explanation!!
Thank you so much. Save me few days
Your not a ordinary man
Very cleaver !
Sir what act as a single in transistor current or voltage???
pls reply:-
can't transistor act as an amplifier in saturation region? isn't amplification dependent only on the current?
In saturation, as the name suggests the output current is maxed out. (In our video example 3mA).
In this state as the input current changes output will stay constant.
That's not an amplifier right? An amplifier would be if output current is always some number (beta) times in put. Which means as input changes output must keep changing accordingly
@@KhanAcademyIndiaEnglish thankyou for replying!
@@KhanAcademyIndiaEnglish Awesome