I've said it many times, but this man is a king. His videos are literally saving my grade and my sanity. I wish all instructors were as great as Dr. Hanson.
I've got the worst lecturer of all time.. and everytime i search for a topic to see Dr. Hanson pop up, I'm beyond excited. You really are incredible Doc, thanks alot.
His teaching of the technical elements is amazing...period! but we can't discount how his humour and relaxed personality keeps us engaged so we allow ourselves to learn. I've never met any teacher, instructor or prof like Dr. Hanson. This guy is beyond the real deal.
I'm studying through UNISA, which is a self study from home with no tutor.. Making sense of this without a tutor is a nightmare but you sir are a proper legend!!! Other videos I've come across skip so many steps and I end up more confused.. I saw this 1 hour long video and almost shat myself.. I just need to tell you that this was probably the most valuable hour I have ever spent!! Thank you for the wonderful tutorial and amazing breakdown explaining absolutely every step along the way. You get people that are paid to teach and people that CAN teach and this is your calling!
Dr. Hanson, you've helped me in so many classes. I thought I was doomed because I passed solids and Statics and you didn't have any videos past those subjects. Until I got to analysis of structures and we had to do beam deflection again. 1 hour of you explaining the process and im like a pro again. Thank you for helping me become an engineer.
I don't know why our professors don't teaches like this ..if all professors wear like you .we would have a lot of good students . you are so good at teaching ..thank you for your contribution in my educational life sir..
I Just watched your old video about this lesson to solve my assignment. Thank you Jeff Hanson. I hope you can include superposition method and moment area of theorem too
Jeff kind of messed up at about 17.30 minutes of the video. It'd be better to write the equation for a slope at a point like dy/dx = 1/EI * integral(M(x), dx) for easier understanding...
Mann thank god for you and going this grinder with us, Prof! 😵💫🤓I spent a solid t hrs on one of these with a partial distributed load (same supports) in my last HW today….. I feel way better watching this- except now I know I need to triple check my math/reductions along the way. And shoot maybe I’ll plug it into the smaller v equation and see if that gets me the answer in the back…. I’m confused though, after finding the equation from A to B (across the beam) we were asked to solve for the deflection at A,B and the midway (C). Why wouldn’t the deflection at A and B be zero though? Isn’t that what our boundary conditions State for these pins and rollers??🤔
Greetings from Poland Mr. Hanson. We have a little bit different signs, for example your V it is our R (reaction), but methode is the same. I wish I want to have teachers like you in my University. P.S. In my University I didn't pass exam, because in task like that, my constanses of integration were written in the end of eqation, not in 1 interwal. In profesor's opinion it wasn't agree with ,,art of counting in Clebsh methode"
just by using first 2 boundary conditions we can solve it right ? in that case c2 and c4=0 in fact your c4 is almost zero c4=(11/128 pl^3)=almost (1pl^3/12) do we need to use 4 boundary conditions?
I agree that the slope absolute value would be about the same on either side of c, but wouldn't the values of the actual slope be equal and opposite on each side? Ex.) One will be concave up and one will be concave down ?
No they would be equal but not opposite signs because his coordinates for both his cuts are all in the positive x axis. So the slopes will be both equal and positive.
My school follows beer and johnston book for strength of materials does it goes with your videos ??? You really helped me through statics so i really want to get your help in strength of materials too
I don’t understand in 15:09 when writing the boundary counditions, in left side it is fixed right? And in the right side it is pin. But why isn’t the left sides slope is not 0 ? I mean it’s fixed and the slope in fixed conditions are zero. But you side slope is not zero in point A PLEASE I HAVE A FINAL IN FEW HOURS HELPPPP
Hey Doc Hanson, Did you do any videos on the Moment Area method? We are covering that and I am way lost. I am trying to stay ahead of the game and pick up this method asap.
I don't get how we gave x lenght two different values. In the first section we say that it's lenght x and after in the second longer section we say it's x again how come this?
For the second M(x) equation, could you have set the right side of the beam as the origin and derived an equation that way? Or is it necessary to have the same origin for both equations?
I’m pretty sure that it is necessary because our “x” variable must represent a distance from the same point. If you did set the right side of the beam as the origin, then your value of x would represent the distance from point “B”. X in both equations of M(x) needs to represent distance from point “A”.
@@bhbvh4904 I think it is because 'x' is just a variable used so that you can plug in any length into it; meaning you can find the moment at any length.
how come he used x for lenght of both cut. shouldnt be the lengh of first cut(x) smaller then lenght of second cut(x). why he used same variable for different dimentions.
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i dont know how terrible my student life would be without your tutorial videos. Thank you so much sir!
I've said it many times, but this man is a king. His videos are literally saving my grade and my sanity. I wish all instructors were as great as Dr. Hanson.
I've got the worst lecturer of all time.. and everytime i search for a topic to see Dr. Hanson pop up, I'm beyond excited. You really are incredible Doc, thanks alot.
His teaching of the technical elements is amazing...period! but we can't discount how his humour and relaxed personality keeps us engaged so we allow ourselves to learn. I've never met any teacher, instructor or prof like Dr. Hanson. This guy is beyond the real deal.
I'm studying through UNISA, which is a self study from home with no tutor.. Making sense of this without a tutor is a nightmare but you sir are a proper legend!!! Other videos I've come across skip so many steps and I end up more confused.. I saw this 1 hour long video and almost shat myself.. I just need to tell you that this was probably the most valuable hour I have ever spent!! Thank you for the wonderful tutorial and amazing breakdown explaining absolutely every step along the way. You get people that are paid to teach and people that CAN teach and this is your calling!
Thanks for the great comment. Glad it helped❤
The 15 dislikes in the previous video are 15 professors who lost their job due to Prof. Hanson teaching better than them.
😂😂😂
2023 and only 15 haters, 0 dislike in 2 years he doing aight
Dr. Hanson, you've helped me in so many classes. I thought I was doomed because I passed solids and Statics and you didn't have any videos past those subjects. Until I got to analysis of structures and we had to do beam deflection again. 1 hour of you explaining the process and im like a pro again. Thank you for helping me become an engineer.
37:31 "Holy banana batman", LOL
I don't know why our professors don't teaches like this ..if all professors wear like you .we would have a lot of good students .
you are so good at teaching ..thank you for your contribution in my educational life sir..
What a wonderful lesson. Thankyou Dr. Hanson for your statics and solid mechanics explanation. It helping me so much
I Just watched your old video about this lesson to solve my assignment. Thank you Jeff Hanson. I hope you can include superposition method and moment area of theorem too
lun p char
You are just great. I would have aced this course if I had you as a prof.
Jeff kind of messed up at about 17.30 minutes of the video. It'd be better to write the equation for a slope at a point like dy/dx = 1/EI * integral(M(x), dx) for easier understanding...
Thanks professor. You do a great job explaining this stuff.
Dr Hanson, a true teacher
Mann thank god for you and going this grinder with us, Prof! 😵💫🤓I spent a solid t hrs on one of these with a partial distributed load (same supports) in my last HW today….. I feel way better watching this- except now I know I need to triple check my math/reductions along the way. And shoot maybe I’ll plug it into the smaller v equation and see if that gets me the answer in the back….
I’m confused though, after finding the equation from A to B (across the beam) we were asked to solve for the deflection at A,B and the midway (C). Why wouldn’t the deflection at A and B be zero though? Isn’t that what our boundary conditions State for these pins and rollers??🤔
Just in time! Thank you
Structural Theory on your next videos
Dr. Hanson please
So glad I don't have TH-cam premium, those advert breaks were lifesavers - especially that 18minute long one
Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))
Just in time, thank you professor Hanson!
He is one of the best professors for Mechanics of Materials. Does he teach Advanced Mechanics of Materials?
You're the man Jeff 💂
Thank you for making this simple and clear.
You make it fun. LOL , he said get some popcorn we will be here for a while lollll
You are the best!
Greetings from Poland Mr. Hanson. We have a little bit different signs, for example your V it is our R (reaction), but methode is the same. I wish I want to have teachers like you in my University.
P.S.
In my University I didn't pass exam, because in task like that, my constanses of integration were written in the end of eqation, not in 1 interwal. In profesor's opinion it wasn't agree with ,,art of counting in Clebsh methode"
u are the best!
i have found another legendary teacher
Thanks for the steps !
18:33 "that dude right there is the devil" lmao
just by using first 2 boundary conditions we can solve it right ? in that case c2 and c4=0 in fact your c4 is almost zero c4=(11/128 pl^3)=almost (1pl^3/12)
do we need to use 4 boundary conditions?
I agree that the slope absolute value would be about the same on either side of c, but wouldn't the values of the actual slope be equal and opposite on each side? Ex.) One will be concave up and one will be concave down ?
just look at it, they are concave in the same direction
No they would be equal but not opposite signs because his coordinates for both his cuts are all in the positive x axis. So the slopes will be both equal and positive.
You did it very similar to castiglianos theorem. Only youre solving for Bending Moment.
Amazing !!
Where can I get that eraser! It works better than any I've ever seen!
Thank you so much!!!!!
My school follows beer and johnston book for strength of materials does it goes with your videos ??? You really helped me through statics so i really want to get your help in strength of materials too
You saved me fr
yes you did it!!!!!
You are legend
thanks sir
YASSSS JEFF KEEP IT UP!!
Masterpiece
I don’t understand in 15:09 when writing the boundary counditions, in left side it is fixed right? And in the right side it is pin. But why isn’t the left sides slope is not 0 ? I mean it’s fixed and the slope in fixed conditions are zero. But you side slope is not zero in point A PLEASE I HAVE A FINAL IN FEW HOURS HELPPPP
Hey Doc Hanson, Did you do any videos on the Moment Area method? We are covering that and I am way lost. I am trying to stay ahead of the game and pick up this method asap.
professor Hanson, it should be 1/128 PL^2 + C1; (3/8)*(1/16) = 1/128. Thank you
Is it just me or did Mr. Hanson make a mistake at theta1 og y1.
He mixed up the equation when putting C1 into Theta1 and y1.
Correct me if im wrong?
yes masta
hi. isn't it easier to use mccouly's brackets?
Can you teach mechanics of materials at my school, please!!
If I have a beam with loads in the middle and free ends. Do I have to make cuts at the free ends?
Why the deflection at C does not equal the integral of the slope at c?
dexterity test
@ 50:51 shouldn't theta_c there be a 1/EI?
He fixes it @ 52:25
Shouldn't the deflection at the roller be unknown? if it were a pin it would be secured but it's not...
I don't get how we gave x lenght two different values. In the first section we say that it's lenght x and after in the second longer section we say it's x again how come this?
For the second M(x) equation, could you have set the right side of the beam as the origin and derived an equation that way? Or is it necessary to have the same origin for both equations?
I’m pretty sure that it is necessary because our “x” variable must represent a distance from the same point. If you did set the right side of the beam as the origin, then your value of x would represent the distance from point “B”. X in both equations of M(x) needs to represent distance from point “A”.
I got an hour and 15 min till my exam…. Hope this allows me to do these
i failed(barely) 🤣 second chance tommorow, hopefully it goes better
Holy dooley, please tell me there's an easier way to calculate slope and deflection.
Why is the X in the second moment equation the same as the first? Arent they different lengths?
You dont happen to know why now do you?
@@bhbvh4904 I think it is because 'x' is just a variable used so that you can plug in any length into it; meaning you can find the moment at any length.
@@dan9512 exactly, its arbitrary
how come he used x for lenght of both cut. shouldnt be the lengh of first cut(x) smaller then lenght of second cut(x). why he used same variable for different dimentions.
Thank you❤ jeff_Hanson_PhD🙏🏻
There will be my final exam tomorrow and I knew nothing before I listened these lessons;however, still I can't predict how the exam will be tomorrow.
how did it go
@@willgggg900 I passed with DC or DD I don't remember actually what the grade is.
7:00 Intimidating ! Lol hhhhhhhhhh
I hope he finds out that he made a mistake with C4
@31:38 LOL! Algebra! Don't mess me up algebra!
... I always say
Please Sir, kindly Share with me CONJUGATE METHOD.
Thank you
That's alot of algebra😂
determine the slope and deflection at point c on the beam below (figure 2). 5 kn 4m 4m a c b figure 2
Ay bro this is not chegg. no one is going to help u
bruh