THE SOURCE FOR JEE ADVANCED 2021 VERNIER CALIPERS PROBLEM - CORRECT PREDICTION | NO FORMULA REQUIRED
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- เผยแพร่เมื่อ 24 ก.ค. 2024
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Q : In a specially designed vernier calipers , 10 divisions of the vernier scale are equal to 4divisions of the main scale. In the following figure, the zero error and a measurement are shown . In the zero error, the 5th and the 10th divisions of the vernier coincides with 1 mm and 3 mm mark on the main scale respectively and in the measurement , the 2nd and 7th divisions of the vernier scale coincide with the 23 mm and 25 mm mark on the main scale respecetively as shown in the figure . Report the length measured with due regards to the error.
(a) (b) (c) (d)
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Sir whenever I watch any of your video, I feel like you are teaching like a teacher who is literally siting in front of me, explaining every minute and silly things so that, the most diffucult questions would also seen easy.....
Just amazing sir..
Very Well Presented and It is definitely very helpful for students! :-) loved it.
Thank you sir 😊👍
Yes it was helpful jee adv 2021 meinnaagya
Hello Janardhan sir .
I feel there is a mistake in analysis here , correct me if i am wrong . Calculation of e ( zero error) and l are by two seperate observation and both can have an error of +- 0.2mm , where as this has not been taken into account while calculating e . If the manufacturer of instrument provide value of e then we can directly use it , however here it is calculated from observation sir .By the way I am a big fan of your content sir .
I figured this out by drawing a Vernier callipers in MS word a few months ago. Am amazed to see that it was already covered on TH-cam. Great video sir
Thank you 🙂
u r from doubtion right?
@@yasht633 ya lol
I watched your video of vernier caliper and screw gauge 2 days before jee advance and surprisingly it came and I did it correct, I am thankful to you sir my AIR-3161
Congratulations on your rank and all the best with your IIT Life 🤞😊
That's gr8!
@@143maths ok
Janardhan sirrr ..............u are showing aroma and taste of physics subject....streets ahead of Hyderabad biriyani........luv u sirrrrrrrrrr
😂 nice words 🙏
@@PHYSICSSIRJEE .....actually sir.....though I am iit faculty....without any ego I am suggesting ur vedios to my students....ultimately they have to gain marks sirrr
@@VijayKumar-rl9zb it's a very nice gesture sir🙏😊
Absolutely Fantastic!
Sir please bring a similar video on screw gauge and other error parts...thank you so much for this one. LOVED IT, THANKS SIR
After watching this now I not needed up to mug the formulas it's pretty simple thankyou sir 😁🙏
🥺🥺 thnk u sir pahli baar ye clr hua achchhe se, AMAZING sir jee!!!!!!!!!
Brilliant question and equally brilliant solution. The explaination of the solution is also very simple. Liked it 👍
One video alll the conceptssss !! Thank-you soo much sir ❤️
Thank you sir this method is far superior than the standard formulas :)
Fantastic again....
What is great about your videos is you are trying to get student into proper stride. I take a bow for the passion maitained throughout.....God bless you
Thanks a lot for being able to understand my intentions 🙂🙏
That was really amazing,learnt a lot,thank you so much for presenting this in such a beautiful manner
Thanks for your appreciation 😀. Please,if possible, kindly share this content with your friends groups (whatsapp or telegram) where students may benifit similar to you🙏
Thank you very very much, sir!
It really helped.
didn't know before this video that lc and vc are not same!! THANKYOU SIR!❤❤
Sir, your videos are classics. 🔥🔥🙏
Beautiful explaination sir ❤️🔥
YOU ARE GREAT SIR .
What a beautiful explanation ❤️
Very well illustrated sir
I got this concept only after seeing this video , I had learned the formulae and tried to solve only by that.Its amazing janardhan sir ,truely best
Despite being quite fast, you are articulate in the subject and the language both. That is remarkable quality possessed by few.
Thank you very much sir for the very 1st time I understood it completely
Revised again today
🔥🔥🔥🔥🔥
Loved it a lot sir
Really amazing sir... My fear against this topic was swept out by you. ....sir please explain about phasors topic.. Toughest problems.....after this mains extra topic series
Sir I’ve checked so many websites but no one gave the formula for least count , even iitk website gave 1MSD-1VSD sir. Thanks for giving clarity on concept
Thank you 🙏🙂
An absolute beauty.
This question came in today's advance thank u sir
Awesomeeeee 🔥🔥
Beautiful explanation
Tq so much sir got so much clarity today
I am a JEE Aspirant I thought for 30 mins that why the formula i learned (LC = 1MSD - 1VSD) and used multiple times didn't work for this even though it was derived through the same method of conservation of length on both scales..I came to a conclusion that in that derivation we had only one VSD between the 0th MSD and 1st MSD while in this question we had 2 VSD between 0th MSD and 1st MSD so eventually we had to subtract 2VSD from 1MSD to get least count ... And got to the foemula that for any Vernier scale, L.C. = 1MSD - (n)VSD (; where n is the number of VSD between 0th MSD and 1st MSD ) or For simplicity we can simply keep on subtracting VSD from 1MSD until the value becomes less than or equal to VSD and that value is our L.C... Please correct me if any of my conclusions have mistakes..
nice work, captain obvious. Your existence must also be as redundant as this comment that you thought was a very nice discovery.
good observation
@@korigamik yeah fantastic tone of speaking honourable Sir, not rude at all. I wonder who's redundant.
Super brooo
@@korigamik itna shaana kyon ban rha hai, khud bata bhai kitni rank aayi ki tu itna chaud dikha rha hai?
Thanks sir enjoyed a lot
No words 🔥🔥🔥
An easier way can be to just find distance between the 10th mark on VS. 10mark in reading will be 26.2 i.e. 25+3VSD(=0.4mm). Distance will be 26.2 - 3=23.2
Watching this bfor jee mains to revise vernier calliper☺️thanks sir❤️
Beautiful 😍
Thank you sir :)❤❤
Killing questions with simple maths 👍
Amazing 🔥
Awesome explaination sir. I also use the same method. I have a doubt at 9:17 the length = 23 + 2(.04) + zero error. That will come out to be 23.18 Have we rounded it off to 23.2 because of significant figures or is there any mistake in calculations.
op op op op op op op op op op op op ab mere paas pure thinking based two methods ho gye :)
haan mujhe least count dhoondhna nhi aata tha but ab gya...
aur is question me options easy the isliye bina least count ke bhi ho gya..
nd thnk you sir
An EYE OPENER
Thank you 🙏🙂
Thanks ❤️
Thanks sir helpful
# 49 For my revision ( Fan Of Yours!!🤗)
Amazing sir 🙂✨
This was really helpful Sir
Thank you ,🙂, please kindly share this video with as many people as possible
Thank you sir..
answer to aa gya tha because the options were not set properly; only one option had the correct reading
but learnt a lot of new things from this video about least count. I used to think vernier constant and least count mean the same lol
thanks a lot sir
Superb video sir
Best explanation of principles of vernier. Yet, I have a query. Shouldn't the error reported be twice the least count, i.e., 0.4mm? Measurement of length involves two readings; first being the measurement of zero error itself.
Thanks sir ❤️❤️❤️❤️🙏🙏🙏
Thanks a lot sir 🙏
Hey brother i m seeing ur comment in every video of sir….if u dont mind could u plz guide me in my jee prep and suggest channels for other subjects for jee adv
Thanks you sir
Hey sir..great video..I have an diff insight for least cnt...plz tell if u liked it..in above case..the actual zero of Vernier scale..is 2mm behind the 1mm mark..of main scale..so starting from that zero..I will calculate the position of VSD coinciding with 0 of mains scale..let position be n..so n*2/5 =1mm..as main scale 0 divide two half abt the coinciding divisn..no I get n=2.5..but I knw n=2 is possible and so the 0.5VSD is least extra length needed to shift the 2 divisn of VS to voincide with 0 of mains scale .wgich is hence 0.2mm..
That was a Sirjee-cal strike on the concept!
How do we know whether nth vsd is closer to any of the MSD than the final least count answer?
just got a question wrong on fundamental meaning of least count in fiitjee aits, this video is really helpful
ekdum god lvl
Thank you , please like and share the content
Bursting AIITS questions and Allen Test series questions like a boss with this concept
THANK U SIR FOR THIS VIDEO PLEASE BRING ONE VIDEO ON SCREW GAUGE TOOOO PLS SIR
THIS VIDEO WAS REALLY VERY HELPFULL
THANK U SO MUCH SIRR
Already in plan, it will be coming by next week 🙂
@@PHYSICSSIRJEE thank u so much sir really liked all ur videos.
Sir @12:55 you said that no lines are matching, but isn't the 5th VSD is matching with 2nd MSD.
Thank you sir a lot !!! Sir I have problem related to reduced mass concept application ! How to solve question easily if we know reduced mass concept ! I only know how calculate reduce mass but not it’s application sir ! Help from your side would be highly appreciated sir !!!
Reduced mass is not a universal Concept. It's only applicable as a mathematical tool in reducing our Calculations in certain special cases only . Eg: 1) Energy Calculations in two body collisions 2) Modified Bohr model where nucleus mass is comparable 3) time period Calculation in case of two blocks connected by a spring
Don't worry too much about it by thinking it's a very heavy Concept. Practice above three cases for now. I will plan for a video in coming days 🙂
Sir the solution you gave for calculating least count part means that we would have to draw the "to scale/schematic" diagram as in this question only one main scale mark was there but if we have multiple marks how do we conclude which vernier division is closest to any main scale division ??
For co-primes , you can mathematically prove only one or no coincidence will occur for a reading
Sir a question similar to this came today in advance 2021
🙏
Sir, definitely the best and simple explanation to the topic. I have a doubt. For Least Count calculation, if for example 20 VSD coincides with say 17 MSD. Then how do we draw this to scale in exam and how do we find the least count.
Great idea 👌 , I was planning a video on this anyway . I will give you the answer. Can you figure out how ?. Least count in your problem is (1 MSD) /20 ...as 17,20 are co-primes . Did you see , what I did there ? 😉. In case you couldn't , don't worry , I will plan a video on this 👍
@@PHYSICSSIRJEE
Thank you, shall wait for the video...
@@PHYSICSSIRJEE sir, can we use 1MSD/no of vsd for co-primes.i have checked for few, it is matched with the theory explained above 😍🙏🙏🙏. How to proceed with non co-primes? Thank you for your videos sir.
@@narasimharao9074 I will make video on that , you have to consider GCD for non-coprimes
@@PHYSICSSIRJEE Sir waiting for your video on this topic, I am getting (3 MSD)/20 as the least count if 17 MSD=20 VSD.
similar concept asked today in paper 2 lol
Sir I have a doubt in the least count calculation part:
As you said that it is the least distance to be slid by the vernier scale for a MSD to coincide with VSD . It might be possible that on moving the vernier scale towards the left the least distance is getting obtained.
Example: 3MSD=5VSD, Here least count will be (1MSD-1VSD=0.4mm) or (2VSD-1MSD= 0.2mm).
0.2 mm
@@PHYSICSSIRJEE
So Vernier scale can be moved left (beyond the zero of main scale)?
@@harshrivv it cannot be . 0.2mm is the answer without that . Please draw the two scales and check (by mentally moving VERNIER scale only to the right)
@@PHYSICSSIRJEE Ok sir, I understood now.
Thank you very much sir!!
Sir have you tried that third part of electrostat question again
So is it final that it could not be solved with the provided information so that I could skip that
Skip it for now , I will take it up here later after modifying the Question
I have tried solving pathfinder of electrostat
I did whole chapter but it took a huge time around -25 days to complete that and I don't think in this year itself I would be able to do if I continued like this
So it's a request just give a vague idea About solving that book what to skip and what to actually solve
As I am a neet aspirant and just doing physics for Olympiads I really really want that inpho tag!!!!?
@@shivamvatish5537 my advice for you is to finish all objectives in the book first
Okay that's doable😁
sir can u please tell what would we do for cases having random no. of MSDs coinciding with VSDs?
I saw the discussion in the comments below, from what I have been able to understand:
. for m VSDs coinciding with n MSDs where m,n are coprime, the least count will be 1MSD/m
. for m VSDs coinciding with n MSDs where m,n are not coprime, , the least count will be 1 MSD/p where (p, q) is the pair obtained by dividing (m, n) repeatedly with their GCDs until two co-prime nos. are obtained
Please respond sir if my understanding is right or not
sir please reply to this @Physics Sir JEE
JANARDHAN SIR OPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
How do we come to know when is the least count not equal to vernier constant, do we need to calculate and then comment or is there a way to directly comment upon it ?
By checking the way I did. Btw , the least count and vernier constant are equal only for n MSD = (n+1) VSD style vernier
Thanks a lot sir
@@PHYSICSSIRJEE Sir, What is the difference between Least count and vernier constant. Websites it is given that both are same. Thank you for the in depth concept sir
In what condition the formula given in books for least count is true
You may check that the least count and vernier constant are equal only for n MSD = (n+1) VSD style vernier👍🙂
Sir let's think that we have a defective vernier callipers (standard one ) with -ve zero error of 10^-6 then can we say least count is 10^-6 ? If d definition given in video ie minimum distance that should moved by so as to get a coincidence then I this 10^-6 is fine,I think and also lc depends on zero error.
Or is it necessary to take both zeros coincide when we were to count lc?
@@arunayarramreddy4235 we have to start from both zeroes coincidence👍. Error is also a measurement, so it will be in multiples of LC . So , in the case you mentioned , 10^-6 seems to be too small to be measurable by standards of VERNIER CALIPERS. Unless you tell me MSD vs VSD relationship
🙏🙏🙏👍🏻👍🏻👍🏻
My gut feeling says least count is always
Min{|1MSD - K VSD|} where k is an integer
Please confirm this expression ❤
A easier version but similar again in jee advanced 2021
Was the answer 3.17
@@hridayjasani7773 yes bro
Sir what if 8 MSD= 9 VSD...then for least count calculation...shall we need to draw the whole MS and VS till 9th VSD to check where the least separation is being obtained?
As here it was easy to observe the least separation as it was 2 MSD= 5 VSD
Yes , that’s the basic way . But short cut is LC is MSD/9 in your question
@@PHYSICSSIRJEE sir may I pls know how did u derive this shortcut?and whether this shortcut will be applicable in every case or not?
@@noobiepianist for derivation, I need to make a video... It works if number of divisions are coprimes
@@PHYSICSSIRJEE thanku sir🙏
@@PHYSICSSIRJEE sir one more doubt ..as advance is too close..and i m currently following aur AITS series..so do I need to watch ur other videos..or AITS is enough for buliding good aptitude in this limited time?
TO be revised 8 Jan
B?
Finally an Answer correct lol
Opppppppp
Why not error in measurement of e itself is accounted , should not the error be 0.2+0.2
Time stamp of your doubt please???
Sir at 7.35 , where you are calculating e
@@anujha7310 I couldn't understand the wording of your question but I will try to explain 🙂....
at 7:05 when we calculated error e, we were told in question that the divisions exactly matched (left of the screen) ... So we assumed the calculation of e is perfect from that information. Remember e is called a systematic error.
Now, in any Measurement related to Vernier ( e on left or actual reading on right ) , there will always be a random error which should be reported with a +- (plus or minus) sign separately at the end. That's not to be included in the calculation of e. I hope you understood
Yes sir I do understand
Thank you , I was thinking that e has also been calculated and there will be error in it too , However if according to question it exactly matches and there won’t be any error in it , I am fine .
Thanks a lot sir
Sir one more thing , I had asked a question for jee 2016 rotation problem too , if you can check once I will gain confidence in my understanding .
Thanks sir
14.30......1MSD -1VSD would be 0.6 mm and not 0.1 mm.....speak carefully sir 😂.........least count is the minimum difference between a measured value and a multiple of vernier count........vernier count is taken equal to least count only if that minimum difference is zero....
Thanks for the smiley , and the advice given. I will consider it for future videos. Btw , for this video LC is 0.2 mm as mentioned at 14:30. Least count derived there is correct.Least count is the least measurable length . It’s not 1 msd - 1 vsd always.
There is nothing called ‘vernier count’ in your comment , I think you mean to write ‘vernier constant’ . Please write carefully:) Mistakes can happen, I can understand
@@PHYSICSSIRJEEyou are getting angry sir....this a sign of ego.....Just carefully read what I wrote..........I just said that in your video at 14:30 you said 1 MSD - 1 VSD as 0.1 mm while according to the solution you provided it should be 0.6 mm.......also I very well know that there is a difference between least count and 1 MSD - 1 VSD..............and yes for sure there is no term like vernier count😂 in physics that's my slang term I shouldn't have used it.......and yes JEE is an objective exam also😂
@@Kattar_Hindoooo angry yes , ego no . Angry because of lack of respect and the tone of your comment. Rest all , I leave it to your better judgement
@@PHYSICSSIRJEE this is what we call ego.......I addressed you with designation of sir in my comment and I don't know in how much high esteem you take yourself that even that is a disrespect of yours.........I understand that while we are speaking so much things and at the same time also explaining them then things like this happens ....that's fine.......I just pointed that out.......my intentions were not to disrespect you .......why would I .......I don't even know you........no disregard....no grudges......I am sorry I commented on your video.......
I was referring to " speak carefully sir 😂" part of your first comment. What's there to laugh ? I didn't understand . I couldn't decode your intention. It could be a slip of tongue when I said 0.1 mm in the video.
I just felt there was no need laugh on a video made with pure intention and hardwork. So , I just wanted to highlight that . As , you said , may be I too should have toned down my response. As you said , no grudges , no ill feelings from my side too. And sorry if I hurt you. It's just unfortunate that this conversation started off on wrong note. It can go better from here on , I guess. It would be nice if you can continue commenting on the videos in future , that too , if you choose to 🙂. Have a nice day 👍🏼