Solve ANY Vernier Calliper; No Formula, only logic! JEE Adv 2021
ฝัง
- เผยแพร่เมื่อ 15 ส.ค. 2022
- Learn to solve JEE Advanced 2021 Physics problem on Vernier Calliper in 1 minute without any formula!
You will also learn how to solve any Vernier Calliper problem with pure logic.
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2 years of confusion, all over in just 20 mins. thanks a lot. A video explaining screw gauge too, please?
You are the one who inspire me to think and create logics behind any problem.
One day you are going to become the best teacher of India.
he IS the best teacher of india. Don't you think?
He is*
For the final question:
Reading = 2.83
LC = 0.01 (which is the absolute difference in lengths of MSD and VSD)
This is a question from JEE Advanced 2016 Paper 2.
Your answer is correct.
Mahesh Sir is great at explaining concepts in a very fundamental manner without any complicated formulas. Thank you sir.
bro isn't the least count 0.11 cm
Explanation:
10 VSD= 11 MSD
10 VSD = 11 * 1MSD
10VSD = 11* 0.1cm
1 VSD = 0.11 cm
so least count = 0.11 cm
if i am wrong reply me
@@Lama_60 Bro, 1 Vernier Scale Divison(V.S.D) = 0.11cm but Least Count(L.C) = M.S.D - V.S.D
= 0.1 - 0.11
Least Count(L.C) = -0.01
Here the negative answer means that the "first marking in vernier scale" will be 0.01 ahead of "0.1 marking in main scale" So, if we just need the value, the least count will be 0.01
Ya correct
@@Lama_60 1 VSD isnt the least count the difference of 1vsd-1msd is what matters to be the least count
We have 1 hr or 45 mins videos but he completed in less time and more efficiently
I want more videos like this especially for class 11. 👍 Actually i think this is the best way of teaching as you are teaching us to reinvent something which is most important for our youth!😀
Very nicely explained. Thank You.
I think in the formula, we get the second decimal digit by counting the place that coincided mod 1 but because the zero error had negative shift, it would be 1- the coinciding mark so everyone got the answer as 0.6 when it was actually 0.4. This makes so much more sense thanks to you!!!
dude you solved my childhood mystery
This was so nice sir....
you clearly made it easy for me, the formula always kept me in confusion, now i am sure i can do any q , now i know logic
LC = 0.01 [because it the minimum length which can be moved in the vernier calliper to take the reading]
& Reading = 2.83
your voice is unique and amazing
and the way you teach is awesome
Mahesh sir please make a video on surface tension
I LOVE YOU MAHESH SHENOY
2.83 cm and 0.01 thank you for making and giving logic for stuff which nobody givess
4:20 There is a video by Sal Khan in which he explains how decimal multiplication and divisions work. 😁
Is this suggestion for Mahesh? Sorry Mahesh kidding😅
I know what to do this weekend, thanks! :D
Too bad he doesn't have a video for how to turn on autocorrect and spell it multiplication :P
I used to explain by saying that the number of coincident vernier division shifts by 10 if the gap is 1 mm. so for each coincident vernier division, gap increases by 0.1mm or 0.01 cm. so when coincident vernier division is 6, we need to add 0.06 cm to main scale reading in cm. your explanation however is more complete!
Great perspective :)
thanks for the awesome explanation
these are the answers i got for the last question
1) 2.83 cm
2) 0.01 cm
sir also do this for screw gauge plz
Now this is satisfying
Thank you so much sir
Most welcome!!!
Gem video
You are relatable :)
Great to know that!
Why not screw gauge
bruh my teacher made it soo complicated
first assumption....the 0s of both the scale coincides....now, reading=2.8+x,and 8msd=7vsd+x (8*0.1=7*0.11+x) and therefore x=0.03 and hence reading=2.8+0.3=2.83... now least count is the least distance that you can measure between msd and vsd and least distance between vsd and msd(vsd-msd) will be only in that division which lies *just after* coinciding divisions(the coinciding divisions are 7th division of vsd and 8th divsion of msd) and the division which lies just after that are 8th(of vsd) and 7th(of msd) so as stated above the least distance you can measure is the distance between these division therefore 1vsd-1msd=0.01 cm.....now I know the question here can be how can i subtract msd from vsd(vsd-msd),well I have assumed that the main scale can move...because this type of question is not used in real life(why would you make a scale whose vsd is greater than msd)...so clearly that's why I am allowed to defy this rule :)( at least that's what I think)
Hey bro, your calculation is wrong. 2.8+0.3 is 3.1 and not 2.83..
@@udaypatel9596 he meant 0.03 ig
Sir,Can you please tell me that how do you make your video? and way to make this type of animation?
Yes, will make a few videos on that!
3.15cm
Reading:2.83
LC :0.11
❤
I'm kinda confused at the part where you measured the divisions of vernier scale 0.09 cms each.
Isn't the divisons of vernier scale the least count?
which is calculated as LC= 1main scale division - 1 vernier scale division.
like,
in that question, it was given that
10 VSD = 9MSD
ie, 1 VSD = 0.9 MSD
(smallest division of main scale is 0.1 cm)
then 1 VSD= 0.9(0.1cm)
which is, 0.09 cms
BUT, when you calculate least count then,
you gotta do ,
LC= MSD -VSD
ie, LC= 0.1 cm - 0.09cm
where you get , least count = 0.01 cm.
then why did we calculate the divisions as 0.09 x 6 instead of 0.01 x 6?
@AnimeSketcheshere yeah but that's the thing right? that is what I said. the answers coming wrong with that one.
@AnimeSketcheshere nah.
The reading was simple to calculate... 2.83 main scale divisions
But the least count took me a while.
I got it 1.11(bar).Here's how:
I imagined coinciding the 10th division of VS with the 10thb division on the MS. So there is gap in between the first divisions of both the scale which is equal to 10MSD -10VSD. This 10VSD is nothing but (10/11)*10 = 9.99bar. So answer is 10-9.999 =1.111.
Please confirm if it is correct...
Thank you sir
nope, least count is 0.01 cm
When he said This is the JEE ART over here 😆😆
Reading 2.83cm
Least count is still 0.01cm
@FloatHeadPhysics
sir why did you choose Khan academy as a large number of platform are present in India🙄
Just
I am curious to know this
I think he is in line with the ideals of Khan Academy. "Free World Class Education For Anyone Anywhere in The World".
Every other platform in India is paid and dont even provide the level of Khan Academy. Just try comparing Byjus app and Khan Academy. They are no match. Sure Byjus has more content. But you can't compare qualoty to quantity especially in the case of Education.
Many things, but most importantly the idea of free education and the work culture!
Hlo sir!
This is Yuvraj this side..
I have a doubt and I came across this when I was learning what thermal velocity and drift velocity are.
I'll start in 3..2..1..
My first question is when we say that the average thermal velocity of all the electrons is 0. Do we calculate this at an instant?
If yes then, is my way of calculating it correct?
since the motion of electrons is random inside a conductor. Thus on an average the number of electrons moving in a particular direction is equal to the number of electrons moving in opposite direction at an instant. Thus, the vector sum of the thermal velocities of all the electrons at an instant is 0..(since for every vector there is some other vector nullifying this.) Now the vector sum of the velocities of all the electrons divided by the number of electrons is the average thermal velocity .. Thus average thermal velocity is also 0.. Since 0 divided the number of electrons is 0..
If we calculate it at an instant then is it calculated the same way I have calculated?
One more question if we don't consider a particular instant of time. Then the average thermal velocity of a single electron should also be zero.. Since it goes and comes back to the same spot when there is no electric field?
Love how you are comparing averaging over time for one electron vs averaging over electrons for one instant! Beautiful.
Since things are random, by definition, it should be time independent. Therefore, considering properties of a single electron at multiple instants should be the same as considering multiple electrons at a particular instant.
So you should get the same answer either ways!
Secondly, when we say zero, what we really mean is negligible! It can’t be exactly zero.
Kind of like when you toss a billion coins. You get about half a billion heads. It doesn’t mean it would be exact 0.5 billion. There may be a few 100 thousands here and there. But they are negligible.
That’s the beauty of statistical processes.
Which Device u use for teaching
made my life a millionx easier
When will second video come ??🥺
Coming out tomorrow!
first method is what i used in class but it took time and tr would make fun of me.
♥️♥️♥️♥️♥️♥️♥️♥️♦️
i wonder how this vid is not popular even after mahesh has put jee clickbait.😁😂
Only 6k view 😢
Sir Please bring 10 more concepts which are asked in jee advanced and can be solved logically for next 10 days every day please
This is last request please
I have to renew my passport :(
@@Mahesh_Shenoy 😅
@@Mahesh_Shenoy sir why did you choose Khan academy as a large number of platform are present in India🙄
Just
I am curious to know this
@@jeeniuspandeyji
First go and read about sal khan ...
L.C = 0.03 cm
Reading = 2.83 cm
Pls make video on secrew gauge also
Please either you or sal Khan at least apply for Sandeep maheswari show.