this is a headscratcher i was jsut lookig at the text of the problem not knowing wtf to do. Inserting angles into it will make it awkward If we have sides 4,10 and letters a,b taken for interval I will use c as length of final side so this means s=sqrt(1/16(14+c)(6+c)(14-c)(-6+c)) so s=1/4sqrt((14^2-c^2)(c^2-6^2)) from this it results that 60 and 116+t>0 so -116
I don’t think I’ve ever seen you stumped on one of my videos before! And that sickness of mine that I messaged you about earlier is also back pain related. Go figure!
Nice reasoning!
this is a headscratcher i was jsut lookig at the text of the problem not knowing wtf to do. Inserting angles into it will make it awkward
If we have sides 4,10 and letters a,b taken for interval I will use c as length of final side
so this means s=sqrt(1/16(14+c)(6+c)(14-c)(-6+c)) so s=1/4sqrt((14^2-c^2)(c^2-6^2)) from this it results that 60 and 116+t>0 so -116
My back pain can't let me sleep qq
Case 1 : sides extending obtuse angle are size 4 and 10 (previous tryout 10
I don’t think I’ve ever seen you stumped on one of my videos before! And that sickness of mine that I messaged you about earlier is also back pain related. Go figure!