Bro you've literally helped tens of thousands of students all over the globe and that's just gotta be a wonderful feeling damn You even made me like physics (which i used to hate when i didn't know you existed lol) You really changed my look on things for the better man
@@MichelvanBiezen oh woww what a coincidence haha, im from a small village in Antwerp too and is study at KULeuven right now and physics has been a struggle but your videos are so helpful and clear, ty! Where do you live now and are you still able to speak flemish/dutch? I’m kind of interested now haha 😅
mine is is write the example on the board and leave it there. omg and when the test comes he gives very tricky question which is not something similar to these series video.
I'm a student from India and I couldn't thank you enough for the videos you did! I tend to confuse concepts quite easily as I'm preparing for my entrance next year. Its all a rush for us here. I was starting to get worried but that's when I found your video like a gift from heaven! The world could do more with teachers like you Sir :)
@@AafisAslam Hey, I'm happy for you; its nice to see someone in my position moves on to higher things. Good for you! best of luck on your work/academics journey
I have struggled in physics a lot but after watching your videos, I got an A in physics 1 and now I am taking physics 2. I took physics 1 three times!! Thank you for your hard work and God bless you!!
Finally I could solve such these problems in less than 5 min! Many Thanks for Every single word you said to simplify this complicated world of PHYSICS !!
Thanks man! I had a very little doubt about adding up the components and was hesitant to ask my professor, so I tried finding a video that explains it but couldn't find any. Finally found this video and it helped me understand the concept properly.
@michel van biezen just wanted to let you know great job on this video, most proffesor understand and know the material, but lack the skill in teaching it,to where everybody can grasp the idea
OMG Thank you so much for this videos. I speak spanish and I can't find someone who speak it and explain good as you the Coulomb's Law. I have test tomorrow and I didn't understand to my teacher but now I think I can past that test with 10! (10/20)
There are many methods that can be used to solve these types of problems. The method shown is a general method to aid in the understanding and can be used on any type of problem.
While doing homework, I watched your videos! I understood the material so much better after watching, then working through the problem again. Fantastic videos!
Amazing, love the way you explain things. The only thing that confused me is that you used F23 instead of F32 because it's Q3 that is affecting Q2 on this example. Anyway, thank you for sharing this to us, students :)
+Nancy Al Nasri Oh wow it's been 6 months since my comment, good news that I passed Fundamentals of electrical engineering. Back then I thought Coulomb's Law was difficult (electrostatics in general) but apparently it was nothing compared to (especially) magnetism. Wish you best of luck and in the same time I want to thank prof. Michel that was a really big help. Only 6 from 300 students passed btw
Oh wow! That's not what I wanted to hear before my upcoming exam. I wish there was more youtube channels that are as good as Prod Michel. I wish you the best of luck as well! Thanks :)
My physics teacher gave us a very similar problem (really just different charge values, positive/negative charges are the same) but said that when calculating the angle of the final force's magnitude using arctan you would need to add 180 degrees to the answer, which in this case is 41 degrees, because of something to do with the magnitude being in the 3rd quadrant. I notice that you did not do this. So is he right?
Thank you so much you're videos are always beneficial your explanation is clear and simple It might've been two years but I hope you could read this comment of mine Thank you you are a life saviour I wish I had you as my physics teacher hope you're doing well best wishes
Hey that was an amazing video!! I struggled in PHY 1 (bad professor and first physics class ever taken) and trying to do better in PHY 2 and this cleared up much about vector application and charges and coloumbs law and direction of the electric forces! Thank you so much!! PS: At 18:15 I believe the angle of the force is 360 - 41 = 309 degrees due to the force direction being +x direction and -y direction.
@@MichelvanBiezen I see, I just didnt see you add the force attraction between q1 and q3 . I thought that it would have a contribution to pull q3 down by F1,3cos45. but in general, Very clear and helpful video, thank you for your response and clarification.
Thank you for the comment, but with any definition of a "great man" I do no qualify. There are many others who have comitted their life to a much greater extent to the service of humankind. We are just glad that we could do our small part.
i think the angle of the resultant force should be 221 degrees! 41 degrees( what we got ) + 180 degrees( because of the direction of the force) = 221 degrees.
Just want to point out that at 9:30 we are looking for a vector quantity NOT magnitude and thus should be negative. (-.054N x^) Your Videos are saving me in school! A million thank you's sir.
Hello sir. I would like to say a massive massive massive thank you for all your videos. Its help me a lot through my foundation in university! All the love from Malaysia. P/s : definitely i will promote about your lessons to my friends! Keep uploading your new videos yay!!
Thanks so for the vid much appreciation but I have one quiz| F1,2| y is the answer not -0.054 since we are looking for the force on the second charge exerted on the first charge
The magnitude of a vector cannot be negative. But if you write it in vector format, then you must include the negative sign since the force is directed into the negative direction.
Michel van Biezen ,looking at the same problem , when all charges are negative charges does it seems like we wont get the second angle (41)? although it will be a different angle on a third quadrant of a cartesian plane
That depends on what is asked in the question. Typically the question will ask you to find the force on one due to the presence of the others. Therefore it depends on for which one you are trying to find the force
+Kentaro Tourangeau If you switch your headphones or speakers around...your right ear can also share in the "enjoyment" :) When we stared filming we had no, None, ZERO experience in making videos. Our newer videos are in stereo, so your left AND right ears can be happy at the same time. (s*L*s)
Hi, and thanks for the video.Two things: 1- When you calculate for the hypotenuse, you leave it as the square root of 8 (7.26 min) and continue on with your calculations. I like to work it all out and got 2.8 meters. I still got the same answer for mag for F2,3 using the 2.8 meters. Then: 2- I was wondering, let's say that when we were looking for theta (10:15 min) we didn't automatically see that this was a 45 degree angle. We do the calculation for the cos a/h. The answer doesn't come out the same here when I try to calculate for the X comp of F 2,3? Shouldn't it all equal the same regardless of whether you employ short cuts or calculate out the actual numbers?
+TheVenusRising Since the two legs of the triangle are both 2 m long, the angle must be 45 degrees. Any method, when done without making errors should give you the same answer.
Thanks for the quick reply. Sometimes I just like to test methods in order check the work. This one is easy because of the 45 degree angle. But, I figured it must all be the same regardless if you use the degree angle or measurement in meters. Thanks for the videos!
For the initial part of the question, why did you use the parallelogram principle for vectors ? Why couldn't you have just drawn a line to connect the two vectors? (In which, that line would've been the total force)
There are often multiple valid ways by which one can solve a particular problem. The methods I use are those that appear to have the best success in the classroom.
I know like charge repel, unlike attract and they have a force between them but the question i want to ask is why there is a force between them? any little information will help... thanks
When a charge is placed in "space" it affects space which results in a force of attraction or repulsion. At the quantum mechanic level it is theorized that particles are exchanged that "create" the force that we measure. In the case of electromagetic forces the exchange particle are photons.
@micheal van biezen Love the video, but set your recording to mono-mic instead of stereo, otherwise it defaults to left-channel only. kind of distracting on headphones
![[LIVE] : ONE ลุมพินี 87 วันนี้!! คู่เอก "ก้องชัย vs โชคปรีชา"](http://i.ytimg.com/vi/YN6e7HVnekw/mqdefault.jpg)
I hope you realize the difference you make in the world. You're amazing! Truly thankful!
r u still alive
Bro you've literally helped tens of thousands of students all over the globe and that's just gotta be a wonderful feeling damn
You even made me like physics (which i used to hate when i didn't know you existed lol)
You really changed my look on things for the better man
Thank you for sharing. I was born and raised in the small town of Kapellen, north of Antwerpen. 🙂
@@MichelvanBiezen oh woww what a coincidence haha, im from a small village in Antwerp too and is study at KULeuven right now and physics has been a struggle but your videos are so helpful and clear, ty!
Where do you live now and are you still able to speak flemish/dutch? I’m kind of interested now haha 😅
Ik woon nu in de VS (in de buurt van Los Angeles). Mijn Vlaams is wat roestig, maar na een dag of twee terug in België komt het gelijk terug.
@@MichelvanBiezen thats so cool and ye even know it looks good haha, wishing you all the best in the future mr !
Thank you. 🙂
Your explanation is so much clearer than my high school teacher.Thanks a lot.
Searched 30 minutes for a German video and they were not even close to be as good as yours, thanks a lot and greetings from Germany.
Welcome to the channel!
Just wanted to say how much I appreciate you making these videos. You are very clear and make things easy to understand.
wish you could be my physics teacher. My teacher is not half good explaining as you.
mine is is write the example on the board and leave it there. omg and when the
test comes he gives very tricky question which is not something similar to these series video.
+Toan Pham i agree with u
We must be going to the same school because my physics teacher does the exact same
@@84toanpham ify too dude, it sucks, and then u somehow get a failing grade
My left ear likes this video.
Lol yea
Thought it's me only
Play it on loudspeaker, instead of earphones
Yes Only on the left
My right ear disagree 😅
I wish I would've found you much earlier in my physics course. You made everything so easy to understand and explained it clearly! Thank you!
Thanks for helping to make the summer term get off to a good start. I appreciate having every step thoroughly explained.
All the best in your summer class. 🙂
I'm a student from India and I couldn't thank you enough for the videos you did! I tend to confuse concepts quite easily as I'm preparing for my entrance next year. Its all a rush for us here. I was starting to get worried but that's when I found your video like a gift from heaven! The world could do more with teachers like you Sir :)
I am glad you found the videos and they are helping. Good luck with you exam next year.
@Ahmad Elwi yes I got into a good government funded engineering college(opposed to private funded colleges) which I'm happy with!
@@AafisAslam Hey, I'm happy for you; its nice to see someone in my position moves on to higher things. Good for you! best of luck on your work/academics journey
I have struggled in physics a lot but after watching your videos, I got an A in physics 1 and now I am taking physics 2.
I took physics 1 three times!!
Thank you for your hard work and God bless you!!
That is great. Thanks for sharing.
I would listen a lecture recording almost 5 times but understand nothing. Sir you're a genius!! Thank you so much!
You are welcome. Glad you found our videos! 🙂
Your videos are so helpful and clear. Thank you for the time you have spent making these. They have helped so many students!
Finally I could solve such these problems in less than 5 min! Many Thanks for Every single word you said to simplify this complicated world of PHYSICS !!
You are welcome!
Sir, because of you I start to love physic even more.. I owe you my grade
Thanks man! I had a very little doubt about adding up the components and was hesitant to ask my professor, so I tried finding a video that explains it but couldn't find any. Finally found this video and it helped me understand the concept properly.
Glad you found our videos.
Thank you so much, sir! You helped me pass Physics 1 and I'm glad to be able to learn from your videos for Physics II.
@michel van biezen just wanted to let you know great job on this video, most proffesor understand and know the material, but lack the skill in teaching it,to where everybody can grasp the idea
Kenneth Miller Is
OMG Thank you so much for this videos. I speak spanish and I can't find someone who speak it and explain good as you the Coulomb's Law. I have test tomorrow and I didn't understand to my teacher but now I think I can past that test with 10! (10/20)
助けてくれた、ありがとう先生。it's been a great help for me. thank you very much teacher.
His explanation is very clear. Good job sir!
When your professor directs you to all Mr. Biezen's videos and you're wondering what he (your professor) get's paid for. :)
Great Explanation. Teachers like you are a godsend.
You are a great teacher i understand you more than my techer that speak my language😊 even thought you speak in english.THANKKKK U SOO MUCH
thank you , you are saving me in my first year at korea university, phys 2 here is so difficult
Yes, I heard that academics are very difficult in Korea. Glad our videos are helpful.
sir you can also solve it directly by using formula Fnet= [(F23)²+(F21)²+2(F23)(F21)(COSQ)]½ Where q =135°(angle b/w F21 and F23)
There are many methods that can be used to solve these types of problems. The method shown is a general method to aid in the understanding and can be used on any type of problem.
@@MichelvanBiezen yes sir thanku sir...sir i have i doubt can i follow this playlist for preapration of jee exam 2024?
While doing homework, I watched your videos! I understood the material so much better after watching, then working through the problem again. Fantastic videos!
Thank you for the clear explanation Sir
Your explanation is a lot easier to understand
Hi! This really helped me a lot since I am having difficulties understanding this in Physics class. Thank yooouu so much!
You are welcome. Glad it helped! 🙂
I've a test tomorrow, watching all your tutorials!!
Good luck on your test. Study hard.
Thank you, your lectures are saving me, thank you
hi im from the Philippines .. and this video helps me a lot in my physics subject
+Cornelios Lavente hi im from america and it helps me too
People like you save students like us.
You are a lifesaver. Thank you for all you do!
Legendary lectures.
Thank you. Glad you like them.
Amazing, love the way you explain things. The only thing that confused me is that you used F23 instead of F32 because it's Q3 that is affecting Q2 on this example.
Anyway, thank you for sharing this to us, students :)
+ArtyBoney
F23 = F32 because of Newton's third law.
+Arti Same thing I was confused about. I know it equals in magnitude, but not in the same direction. If it was F2,3 it would be in the opp. direction.
+Nancy Al Nasri Oh wow it's been 6 months since my comment, good news that I passed Fundamentals of electrical engineering. Back then I thought Coulomb's Law was difficult (electrostatics in general) but apparently it was nothing compared to (especially) magnetism. Wish you best of luck and in the same time I want to thank prof. Michel that was a really big help. Only 6 from 300 students passed btw
Oh wow! That's not what I wanted to hear before my upcoming exam. I wish there was more youtube channels that are as good as Prod Michel. I wish you the best of luck as well! Thanks :)
Remind me a lot of my class experience 😂😂😂 you're doing great.....
This video was so well explained and easy to understand. Thank you very much.
Glad you enjoyed it!
Thank you very much Teacher, you are the best teacher I've ever known
Thank you very much for the video! This might save my academic career! :)
My physics teacher gave us a very similar problem (really just different charge values, positive/negative charges are the same) but said that when calculating the angle of the final force's magnitude using arctan you would need to add 180 degrees to the answer, which in this case is 41 degrees, because of something to do with the magnitude being in the 3rd quadrant. I notice that you did not do this. So is he right?
It all depends on what reference you want to use. Both are correct as stated within the answer.
I really enjoyed this teaching...
Much appreciated sir 🫡
Amen, I have found refuge.
Fantastic. Your explanation and notation are top notch. Very well done, thank you!
Thank you so much
you're videos are always beneficial
your explanation is clear and simple
It might've been two years
but I hope you could read this comment of mine
Thank you
you are a life saviour
I wish I had you as my physics teacher
hope you're doing well
best wishes
ooops
I meant 4 years
pardon me
this is one of the side effects of studying physics for 7 hours in a row!
We do try to read all the comments and we appreciate your feedback. Thank you.
Hey that was an amazing video!! I struggled in PHY 1 (bad professor and first physics class ever taken) and trying to do better in PHY 2 and this cleared up much about vector application and charges and coloumbs law and direction of the electric forces! Thank you so much!!
PS: At 18:15 I believe the angle of the force is 360 - 41 = 309 degrees due to the force direction being +x direction and -y direction.
We have your entire course on video (found from the home page). Angles can be expressed with respect to any axis. (done in this video)
Respect boss! You are a true legend. Thank you so very much
Thank you. Glad you find our videos helfpul.
men, your videos are just great
THANK YOU, YOU SAVED MY GRADE !
I totally love your methods. you really made me love physics even more😀
Excellent presentation.
This video was so helpful thank you very much!
Respect & Love from Bangladesh
Welcome to the channel!
thank you sir this is very clear and helpful in our elemag sub
Glad you found our videos! 🙂
Thank you this was very easy to follow and well explained. I just wish my instructor was this easy to follow.
your videos have helped me in physics so much!!!! thank you.
For F2,3 vector, I think you forgot to add the contribution of of F1,3 cos45
No, each vector and each component of each vector is considered separately, and then added together. The video is correct.
@@MichelvanBiezen I see, I just didnt see you add the force attraction between q1 and q3 . I thought that it would have a contribution to pull q3 down by F1,3cos45. but in general, Very clear and helpful video, thank you for your response and clarification.
professional ..you saved me
Glad you found our videos. 🙂
What a great man you are, Thank You!
Thank you for the comment, but with any definition of a "great man" I do no qualify. There are many others who have comitted their life to a much greater extent to the service of humankind. We are just glad that we could do our small part.
I was confused since I only had my right earbud on and I kept hearing static.... anyway, thank you for this.
i think the angle of the resultant force should be 221 degrees!
41 degrees( what we got ) + 180 degrees( because of the direction of the force) = 221 degrees.
It all depends on the reference point and what you are measuring. The angle between Q1-Q2 and Q1-Q3 is 41 degrees.
Absolutely amazing!!! Keep up the good work
thanks for saving my life
Just want to point out that at 9:30 we are looking for a vector quantity NOT magnitude and thus should be negative. (-.054N x^)
Your Videos are saving me in school! A million thank you's sir.
The absolute value signs indicate we are finding the magnitude of the component.
@@MichelvanBiezen yes I see thank you. I made the comment before I finished the video. Excellent work.
Hello sir. I would like to say a massive massive massive thank you for all your videos. Its help me a lot through my foundation in university! All the love from Malaysia. P/s : definitely i will promote about your lessons to my friends! Keep uploading your new videos yay!!
+Nadhirah Zulkifli
It is great to hear from students around the world. All the best in your studies.
Thanks so for the vid much appreciation but I have one quiz| F1,2| y is the answer not -0.054 since we are looking for the force on the second charge exerted on the first charge
The magnitude of a vector cannot be negative. But if you write it in vector format, then you must include the negative sign since the force is directed into the negative direction.
Life saving video :) Thank you so much sir !
Thanks 🙏 so much
It's clear and so helpful explained
michel you simply physics so amazingly thx for your videos !
I love him so much.
Gabriel,
cos 45 = 0.707
Michel van Biezen ,looking at the same problem , when all charges are negative charges does it seems like we wont get the second angle (41)? although it will be a different angle on a third quadrant of a cartesian plane
sizwe mbokazi
Yes, the angle would be different
When writing down the angle, you would need to make clear which direction right? You could put 41 degrees south of west or 221 degrees wre?
Yes. You can also show the angle graphically thus not requiring the description.
Great explanation i love it
Wow, how do you teach so well?
I SWEAR URE THE BEST
It should be 135 degrees. 45 plus 180 since we're finding the angle of point charge 2
It is better not to use angle greater than 90 degrees.
Wow....finally makes sense, really isnt that difficult! Thx!
How would I know when I am going to solve for F23? Because with other problems it can be solved using F21 and F31 only
That depends on what is asked in the question. Typically the question will ask you to find the force on one due to the presence of the others. Therefore it depends on for which one you are trying to find the force
@@MichelvanBiezen Thank you very much, sir!
You saved me forever grateful 😭
awesome video
my left ear enjoyed this very much
+Kentaro Tourangeau If you switch your headphones or speakers around...your right ear can also share in the "enjoyment" :) When we stared filming we had no, None, ZERO experience in making videos. Our newer videos are in stereo, so your left AND right ears can be happy at the same time. (s*L*s)
great job
thank you so much! you are a Godsend
So if they wanted the answer in standard polar form it would be (0.038N , 221.8°) ?
+Jomel Sagsagat
That is correct.
thanks for all your help
Thanks a milli mayne! You've been a great help!
minute 2.40
I think it's F3,2 right?
thanks very helpful.
great one.thanks
thank you for your benevolence, kind sir
Hi, and thanks for the video.Two things: 1- When you calculate for the hypotenuse, you leave it as the square root of 8 (7.26 min) and continue on with your calculations. I like to work it all out and got 2.8 meters. I still got the same answer for mag for F2,3 using the 2.8 meters. Then: 2- I was wondering, let's say that when we were looking for theta (10:15 min) we didn't automatically see that this was a 45 degree angle. We do the calculation for the cos a/h. The answer doesn't come out the same here when I try to calculate for the X comp of F 2,3? Shouldn't it all equal the same regardless of whether you employ short cuts or calculate out the actual numbers?
+TheVenusRising
Since the two legs of the triangle are both 2 m long, the angle must be 45 degrees.
Any method, when done without making errors should give you the same answer.
Thanks for the quick reply. Sometimes I just like to test methods in order check the work. This one is easy because of the 45 degree angle. But, I figured it must all be the same regardless if you use the degree angle or measurement in meters. Thanks for the videos!
For the initial part of the question, why did you use the parallelogram principle for vectors ? Why couldn't you have just drawn a line to connect the two vectors? (In which, that line would've been the total force)
There are often multiple valid ways by which one can solve a particular problem. The methods I use are those that appear to have the best success in the classroom.
Thank you Professor
Your video is so helpful sir. But can i ask about the magnitude of the f1,2 y components, is it cancelled?why?
Magnitudes of vectors cannot be cancelled. But when you have two vectors with the same magnitude and opposite directions, they will cancel.
In this case F12 is added to the x-component of F23x so it is not cancelled.
You are a huge help!! Thank you.
I know like charge repel, unlike attract and they have a force between them but the question i want to ask is why there is a force between them? any little information will help... thanks
When a charge is placed in "space" it affects space which results in a force of attraction or repulsion. At the quantum mechanic level it is theorized that particles are exchanged that "create" the force that we measure. In the case of electromagetic forces the exchange particle are photons.
You are a legend!
Thanks!
@micheal van biezen Love the video, but set your recording to mono-mic instead of stereo, otherwise it defaults to left-channel only. kind of distracting on headphones
Yes, our older videos were recorded in mono before we figured it out.
thank you so much! this was very helpful
thank you so mush you're amazing teacher
thenk you you help me a lot